Chapter 9: Problem 7
Graph the curve traced by the given vector function. $$ \mathbf{r}(t)=\langle\sqrt{2} \sin t, \sqrt{2} \sin t, 2 \cos t\rangle ; 0 \leq t \leq \pi / 2 $$
Short Answer
Expert verified
The curve is a quarter of an elliptical cylinder on the line \( y = x \) from \( t = 0 \) to \( t = \pi/2 \).
Step by step solution
01
Understand the Vector Function
The given vector function is \( \mathbf{r}(t) = \langle \sqrt{2} \sin t, \sqrt{2} \sin t, 2 \cos t \rangle \). It describes a space curve based on parameter \( t \) ranging from \( 0 \) to \( \pi/2 \). Each component of the vector gives the position in a different dimension: the first and second components represent the \( x \) and \( y \) coordinates, and the third component represents the \( z \) coordinate.
02
Examine Individual Components
Break down the vector into its components: \( x = \sqrt{2} \sin t \), \( y = \sqrt{2} \sin t \), and \( z = 2 \cos t \). Notice that \( x \) and \( y \) are identical, implying symmetry about the line \( y = x \) in the \( xy \)-plane.
03
Identify Curve Relationship
Substitute \( x = \sqrt{2} \sin t \) and \( z = 2 \cos t \) into trigonometric identities. Since \( \sin^2 t + \cos^2 t = 1 \), \( (x/\sqrt{2})^2 + (z/2)^2 = 1 \). This is the equation of an ellipse in the \( xz \)-plane.
04
Solve for the Projected Curve in 3D
Recognizing that \( x = y \) and substituting into the ellipse equation shows that the curve lies on the line \( y = x \) and follows an elliptical path in \( xz \) and \( yz \) planes. This describes a quarter of an elliptical cylinder between \( t = 0 \) and \( t = \pi/2 \).
05
Sketch the Graph
Plot points for key values of \( t \): - At \( t = 0 \), \( \mathbf{r}(0) = \langle 0, 0, 2 \rangle \). - At \( t = \pi/4 \), \( \mathbf{r}(\pi/4) = \langle \sqrt{2}, \sqrt{2}, \sqrt{2} \rangle \).- At \( t = \pi/2 \), \( \mathbf{r}(\pi/2) = \langle \sqrt{2}, \sqrt{2}, 0 \rangle \).Draw the path, which starts high on the z-axis and moves symmetrically outwards until \( t = \pi/2 \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametric Equations
Parametric equations are a way to represent a curve by using a parameter, often denoted as \( t \). Instead of a single equation relating \( x \) and \( y \) in the plane or \( x \), \( y \), and \( z \) in space, parametric equations use separate equations for each coordinate in terms of \( t \). This approach allows us to describe more complex curves.
- The equation \( x = f(t) \) provides the horizontal position.
- The equation \( y = g(t) \) gives the vertical position.
- For 3D, \( z = h(t) \) describes the depth or height.
Space Curves
Space curves are curves that extend into the three-dimensional space. Unlike curves contained within a plane, space curves utilize three coordinate functions: \( x(t) \), \( y(t) \), and \( z(t) \). A vector function like \( \mathbf{r}(t) = \langle x(t), y(t), z(t) \rangle \) defines a space curve.
- These can include familiar shapes, such as lines and circles, as well as more intricate forms like helices.
- A space curve may exhibit twisting or bending that isn't possible in just two dimensions.
Ellipse in 3D
An ellipse in 3D can lie in any plane or be part of a more complex surface. Typically, we express an ellipse using its standard form in one of the coordinate planes. The equation \( \left(\frac{x}{a}\right)^2 + \left(\frac{y}{b}\right)^2 = 1 \) is transformed into 3D depending on the situation.
- In our solved example, the ellipse equation emerges in the \( xz \)-plane: \( \left(\frac{x}{\sqrt{2}}\right)^2 + \left(\frac{z}{2}\right)^2 = 1 \).
- This represents an elliptical shape as seen from the side, projected into the \( xz \)-plane.
- With \( x = y \), the ellipse also projects identically into the \( yz \)-plane.