Chapter 9: Problem 56
Find the center of mass of the solid that is bounded by the graphs of \(y^{2}+z^{2}=16, x=0\), and \(x=5\) if the density at a point \(P\) is directly proportional to distance from the \(y z\) -plane.
Short Answer
Expert verified
To find the center of mass, additional calculations for coordinates are needed.
Step by step solution
01
Describe the solid
The solid is defined by a cylinder, with a circular cross-section given by the equation \(y^2 + z^2 = 16\), which has a radius of 4 and extends from \(x=0\) to \(x=5\). The axis of the cylinder is along the \(x\)-axis.
02
Set up the density function
Given that the density \(\rho\) is directly proportional to the distance from the \(yz\)-plane, the density function can be expressed as \(\rho(x, y, z) = kx\), where \(k\) is the constant of proportionality.
03
Calculate the mass of the solid
The mass of the solid \(M\) is calculated using the integral formula: \[ M = \int_{0}^{5} \int_{-4}^{4} \int_{-\sqrt{16-y^2}}^{\sqrt{16-y^2}} kx \, dz \, dy \, dx \]. Evaluating the integral, we find:\[ M = k \int_{0}^{5} x \, dx \int_{-4}^{4} \int_{-\sqrt{16-y^2}}^{\sqrt{16-y^2}} \, dz \, dy = k \int_{0}^{5} x \, dx \times (2 \times \frac{1}{2} \times \pi \times 4^2) = 160 \pi \times \frac{k}{2} x^2 \bigg|_0^5 = 2000\pi k \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Density Function
A density function describes how density varies across different points in a given region. In physics and engineering, density refers to mass per unit volume. When density is specified as a function, changes in density are expressed depending on the variable coordinates at each location.
For this exercise, the density at a point is directly proportional to its distance from the yz-plane. This means that as you move further away from this plane (parallel to the x-axis), the density increases. Consequently, the density function is represented as \( \rho(x, y, z) = kx \), where \( k \) is a constant.
Key features of this density function include:
For this exercise, the density at a point is directly proportional to its distance from the yz-plane. This means that as you move further away from this plane (parallel to the x-axis), the density increases. Consequently, the density function is represented as \( \rho(x, y, z) = kx \), where \( k \) is a constant.
Key features of this density function include:
- Direct proportionality: The density is directly related to the distance along the x-axis. Larger x-values lead to higher densities.
- Constant of proportionality: The factor \( k \) adjusts how rapidly density changes with distance in the x-direction.
- Variable dependency: Density changes only with respect to x, reflecting the distance from the yz-plane. No dependency on y or z is seen in this context.
Cylindrical Coordinates
Cylindrical coordinates are a three-dimensional coordinate system consisting of a radial distance \( r \), angle \( \theta \), and vertical height \( z \). This system is incredibly useful for dealing with problems involving cylindrical symmetry, as it simplifies calculations significantly.
In the original problem, the solid is a cylinder with a circular cross-section equation \( y^2 + z^2 = 16 \). By converting to cylindrical coordinates, where \( y = r \cos(\theta) \) and \( z = r \sin(\theta) \), the circular base can be easily described with \( r=4 \), showcasing the radius remains constant.
Key advantages of using cylindrical coordinates include:
In the original problem, the solid is a cylinder with a circular cross-section equation \( y^2 + z^2 = 16 \). By converting to cylindrical coordinates, where \( y = r \cos(\theta) \) and \( z = r \sin(\theta) \), the circular base can be easily described with \( r=4 \), showcasing the radius remains constant.
Key advantages of using cylindrical coordinates include:
- Simplifies integration: Calculations involving circular or cylindrical structures become straightforward, reducing complex three-variable integrals into simpler forms.
- Matches symmetry: Problems with rotational or cylindrical symmetry fit naturally, allowing coordinates to align with the physical dimension of the structure.
- Transforms equations: Converting Cartesian equations to cylindrical forms can reveal patterns and features not otherwise visible.
Triple Integrals
Triple integrals are used to compute quantities over a three-dimensional region, such as volume, mass, and center of mass. They extend the concept of single and double integrals to three dimensions, allowing for comprehensive calculations in a variety of fields.
In this exercise, the triple integral:\[ M = \int_{0}^{5} \int_{-4}^{4} \int_{-\sqrt{16-y^2}}^{\sqrt{16-y^2}} kx \, dz \, dy \, dx \]calculates the mass of the cylindrical solid. The integral must be evaluated over the defined limits for x, y, and z.
Important aspects of triple integrals include:
In this exercise, the triple integral:\[ M = \int_{0}^{5} \int_{-4}^{4} \int_{-\sqrt{16-y^2}}^{\sqrt{16-y^2}} kx \, dz \, dy \, dx \]calculates the mass of the cylindrical solid. The integral must be evaluated over the defined limits for x, y, and z.
Important aspects of triple integrals include:
- Iterated Integration: Integration is carried out successively in three layers, often beginning with the innermost variable.
- Boundaries: Set specific limits that encompass the entire region of interest, accommodating any shapes or curves present.
- Variable substitution: In some cases, converting coordinates (e.g., Cartesian to cylindrical) simplifies the integration process.