Chapter 9: Problem 45
Consider the vector field \(\mathbf{F}=x^{2} y z \mathbf{i}-x y^{2} z \mathbf{j}+(z+5 x) \mathbf{k}\) Explain why \(\mathbf{F}\) is not the curl of another vector field \(\mathbf{G}\).
Short Answer
Expert verified
The divergence of \(\mathbf{F}\) is not zero, so it cannot be the curl of another vector field.
Step by step solution
01
Understand the Problem
We need to determine if the vector field \(\mathbf{F}\) is the curl of another vector field \(\mathbf{G}\). To do so, \(\mathbf{F}\) must satisfy certain conditions outlined by vector calculus principles. One key condition is that the divergence of \(\mathbf{F}\) should be zero for it to be the curl of some vector field \(\mathbf{G}\).
02
Compute the Divergence of \(\mathbf{F}\)
Calculate the divergence of \(\mathbf{F}\), which is given by \(abla \cdot \mathbf{F} = \frac{\partial F_x}{\partial x} + \frac{\partial F_y}{\partial y} + \frac{\partial F_z}{\partial z}\). Here, \(F_x = x^2 y z\), \(F_y = -xy^2 z\), and \(F_z = z + 5x\).
03
Partial Derivative of \(F_x\) with Respect to \(x\)
Differentiate \(F_x = x^2 y z\) with respect to \(x\): \(\frac{\partial F_x}{\partial x} = 2xy z\).
04
Partial Derivative of \(F_y\) with Respect to \(y\)
Differentiate \(F_y = -xy^2 z\) with respect to \(y\): \(\frac{\partial F_y}{\partial y} = -2xy z\).
05
Partial Derivative of \(F_z\) with Respect to \(z\)
Differentiate \(F_z = z + 5x\) with respect to \(z\): \(\frac{\partial F_z}{\partial z} = 1\).
06
Add to Find the Divergence
Add the partial derivatives: \(abla \cdot \mathbf{F} = 2xyz - 2xyz + 1 = 1\).
07
Analyze the Result
Since the divergence of \(\mathbf{F}\) is \(1\) and not zero, \(\mathbf{F}\) is not the curl of another vector field. A vector field must have zero divergence to be the curl of another vector field.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Divergence
In vector calculus, divergence is a critical concept which measures how much a vector field originates from or converges towards a point. Mathematically, given a vector field \( \mathbf{F} = F_x \mathbf{i} + F_y \mathbf{j} + F_z \mathbf{k} \), the divergence is calculated as \( abla \cdot \mathbf{F} = \frac{\partial F_x}{\partial x} + \frac{\partial F_y}{\partial y} + \frac{\partial F_z}{\partial z} \). This operation results in a scalar field telling us the magnitude of the source or sink at the respective point.
If the divergence is zero, \( abla \cdot \mathbf{F} = 0 \), the vector field is said to be divergence-free, meaning it expresses no net flow in or out of a point. Such fields are of special interest because they can possibly be the curl of another vector field, \( \mathbf{G} \).
In our exercise, the vector field \( \mathbf{F} = x^2 y z \mathbf{i} - x y^2 z \mathbf{j} + (z + 5x) \mathbf{k} \), has a divergence of 1. Since it’s not zero, \( \mathbf{F} \) cannot be the curl of another vector field. It shows that \( \mathbf{F} \) has a net generation of field lines, ruling out the possibility of it being solely derived from rotation.
If the divergence is zero, \( abla \cdot \mathbf{F} = 0 \), the vector field is said to be divergence-free, meaning it expresses no net flow in or out of a point. Such fields are of special interest because they can possibly be the curl of another vector field, \( \mathbf{G} \).
In our exercise, the vector field \( \mathbf{F} = x^2 y z \mathbf{i} - x y^2 z \mathbf{j} + (z + 5x) \mathbf{k} \), has a divergence of 1. Since it’s not zero, \( \mathbf{F} \) cannot be the curl of another vector field. It shows that \( \mathbf{F} \) has a net generation of field lines, ruling out the possibility of it being solely derived from rotation.
Vector Field
A vector field assigns a vector to each point in space, often modeling physical phenomena. In mathematics and physics, vector fields are instrumental in visualizing forces like gravitational, electric, and magnetic fields.
For a vector field \( \mathbf{F} = (F_x, F_y, F_z) \), each component corresponds to the field's behavior in the \( x \), \( y \), and \( z \) directions, respectively. This enables us to observe how the field acts differently at various points in space and how it interacts with its environment.
In our exercise, the field \( \mathbf{F} = x^2 y z \mathbf{i} - x y^2 z \mathbf{j} + (z + 5x) \mathbf{k} \) showcases a complex interaction governed by mathematical functions of \( x, y, \) and \( z \). Analyzing such fields helps us predict how an object might move through it or how forces accumulate in space.
For a vector field \( \mathbf{F} = (F_x, F_y, F_z) \), each component corresponds to the field's behavior in the \( x \), \( y \), and \( z \) directions, respectively. This enables us to observe how the field acts differently at various points in space and how it interacts with its environment.
In our exercise, the field \( \mathbf{F} = x^2 y z \mathbf{i} - x y^2 z \mathbf{j} + (z + 5x) \mathbf{k} \) showcases a complex interaction governed by mathematical functions of \( x, y, \) and \( z \). Analyzing such fields helps us predict how an object might move through it or how forces accumulate in space.
Curl of a Vector Field
The curl of a vector field is another pivotal concept in vector calculus, primarily associated with the rotation in the field. It's defined for a vector field \( \mathbf{F} = F_x \mathbf{i} + F_y \mathbf{j} + F_z \mathbf{k} \) as \( abla \times \mathbf{F} \). The resulting vector indicates the axis of rotation and the amount of "twisting" at any point in the field.
For a field to be a curl of another vector field \( \mathbf{G} \), it must have zero divergence. This is because, theoretically, pure rotational motion does not have any sources or sinks, thus \( abla \cdot \mathbf{G} = 0 \).
In the given exercise, we compute the divergence of \( \mathbf{F} \) and found it to be \( 1 \), indicating it is not purely rotational since there's a non-zero divergence. Hence, \( \mathbf{F} \) cannot be the curl of another vector field, solidifying its identity as neither purely rotational nor divergence-free.
For a field to be a curl of another vector field \( \mathbf{G} \), it must have zero divergence. This is because, theoretically, pure rotational motion does not have any sources or sinks, thus \( abla \cdot \mathbf{G} = 0 \).
In the given exercise, we compute the divergence of \( \mathbf{F} \) and found it to be \( 1 \), indicating it is not purely rotational since there's a non-zero divergence. Hence, \( \mathbf{F} \) cannot be the curl of another vector field, solidifying its identity as neither purely rotational nor divergence-free.