Chapter 9: Problem 15
Find the first partial derivatives of the given function. $$ z=5 x^{4} y^{3}-x^{2} y^{6}+6 x^{5}-4 y $$
Short Answer
Expert verified
The partial derivatives are \( \frac{\partial z}{\partial x} = 20x^3 y^3 - 2x y^6 + 30x^4 \) and \( \frac{\partial z}{\partial y} = 15x^4 y^2 - 6x^2 y^5 - 4 \).
Step by step solution
01
Understand the given function
We are given the function \( z = 5x^4 y^3 - x^2 y^6 + 6x^5 - 4y \). We need to find the first partial derivatives with respect to \( x \) and \( y \).
02
Differentiate with respect to x
To find the partial derivative of \( z \) with respect to \( x \), treat \( y \) as a constant while differentiating. 1. Differentiate \( 5x^4 y^3 \) with respect to \( x \): \( 20x^3 y^3 \).2. Differentiate \( -x^2 y^6 \) with respect to \( x \): \( -2x y^6 \).3. Differentiate \( 6x^5 \) with respect to \( x \): \( 30x^4 \).4. The term \( -4y \) has no \( x \), so its derivative is \( 0 \).Therefore, the partial derivative with respect to \( x \) is: \[ \frac{\partial z}{\partial x} = 20x^3 y^3 - 2x y^6 + 30x^4 \].
03
Differentiate with respect to y
To find the partial derivative of \( z \) with respect to \( y \), treat \( x \) as a constant while differentiating. 1. Differentiate \( 5x^4 y^3 \) with respect to \( y \): \( 15x^4 y^2 \).2. Differentiate \( -x^2 y^6 \) with respect to \( y \): \( -6x^2 y^5 \).3. The term \( 6x^5 \) has no \( y \), so its derivative is \( 0 \).4. Differentiate \( -4y \) with respect to \( y \): \( -4 \).Therefore, the partial derivative with respect to \( y \) is: \[ \frac{\partial z}{\partial y} = 15x^4 y^2 - 6x^2 y^5 - 4 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differentiation
Differentiation is a fundamental concept in calculus. It involves calculating the rate at which a quantity changes. This process is known as finding the derivative. In simpler terms, if you have a function, the derivative provides information on how the function's output varies as you change the input. For single-variable functions, differentiation is straightforward. You only have one variable to consider.
When you differentiate a function like \( y = x^2 \), you find \( \frac{dy}{dx} = 2x \). This tells you the slope or rate of change of the function at any point \( x \). Differentiation has broad applications, including in physics for calculating velocity and acceleration, and in economics for analyzing profit maximization.
Differentiation is truly a versatile tool that aids in describing how systems evolve or vary over time or space.
When you differentiate a function like \( y = x^2 \), you find \( \frac{dy}{dx} = 2x \). This tells you the slope or rate of change of the function at any point \( x \). Differentiation has broad applications, including in physics for calculating velocity and acceleration, and in economics for analyzing profit maximization.
Differentiation is truly a versatile tool that aids in describing how systems evolve or vary over time or space.
Multivariable Calculus
Multivariable calculus is an extension of single-variable calculus to functions involving more than one variable. It opens up a wealth of possibilities for modeling and analyzing real-world phenomena. The functions you encounter are like landscapes with hills (maxima), valleys (minima), and saddle points, rather than simple curves on a graph.
In multivariable calculus, we often deal with functions like \( z = f(x, y) \), which map two variables to a single output. This becomes useful when analyzing systems with more than one influencing factor, such as temperature over a region or economic output based on labor and capital.
In multivariable calculus, we often deal with functions like \( z = f(x, y) \), which map two variables to a single output. This becomes useful when analyzing systems with more than one influencing factor, such as temperature over a region or economic output based on labor and capital.
- Gradient: A vector that points in the direction of the steepest ascent and plays a similar role to the derivative in single-variable calculus.
- Level curves: Contours representing points of equal function value, useful for visualizing multivariable functions.
Partial Derivative Rules
Partial derivatives extend the concept of single-variable differentiation to multivariable calculus. They measure how a function changes as one of the variables is altered, keeping the others constant. Imagine you are at a point in a landscape and move east or north, partial derivatives tell you the slope in each direction.
To find the partial derivative with respect to \( x \), denoted \( \frac{\partial z}{\partial x} \), keep \( y \) constant and differentiate the function as though it only depends on \( x \). Similarly, to find \( \frac{\partial z}{\partial y} \), consider \( x \) as a constant.
To find the partial derivative with respect to \( x \), denoted \( \frac{\partial z}{\partial x} \), keep \( y \) constant and differentiate the function as though it only depends on \( x \). Similarly, to find \( \frac{\partial z}{\partial y} \), consider \( x \) as a constant.
- Power rule: Differentiate functions like \( ax^n \) by multiplying the power \( n \) by the coefficient \( a \) and decrementing the power: \( n \cdot ax^{n-1} \).
- Constant multiple rule: Multiply the derivative by the constant factor if the function is multiplied by a constant.