Chapter 9: Problem 14
In Problems, find the vector function that describes the curve \(C\) of intersection between the given surfaces. Sketch the curve \(C\). Use the indicated parameter. $$ z=x^{2}+y^{2}, z=1 ; x=\sin t $$
Short Answer
Expert verified
Vector function: \( \mathbf{r}(t) = \langle \sin t, \cos t, 1 \rangle \). Curve: Circle at \( z = 1 \).
Step by step solution
01
Analyzing the given surfaces
We are given two surfaces: \( z = x^2 + y^2 \) and \( z = 1 \). These surfaces intersect at points where \( x^2 + y^2 = 1 \). This equation represents a circle in the \( xy \)-plane.
02
Using the parameterization
We are also given that \( x = \sin t \). We can substitute this into the equation \( x^2 + y^2 = 1 \), which becomes \( (\sin t)^2 + y^2 = 1 \). Simplifying gives \( y^2 = 1 - \sin^2 t \).
03
Solving for other variables
From the equation \( y^2 = 1 - \sin^2 t \), we know \( y = \pm \cos t \) due to the Pythagorean identity \( \sin^2 t + \cos^2 t = 1 \). We have two possible functions for \( y \): \( y = \cos t \) or \( y = -\cos t \).
04
Determining the vector function
The vector function \( \mathbf{r}(t) \) describing the curve is \( \mathbf{r}(t) = \langle \sin t, y, 1 \rangle \). Using the positive solution for \( y \), we have \( \mathbf{r}(t) = \langle \sin t, \cos t, 1 \rangle \).
05
Describing the curve
The parameterization \( \mathbf{r}(t) = \langle \sin t, \cos t, 1 \rangle \) traces a circle in the plane at \( z = 1 \) as \( t \) varies from \( 0 \) to \( 2\pi \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Intersection of Curves
Finding the intersection between curves is a common problem in calculus. Here, we have two surfaces: \( z = x^2 + y^2 \) and \( z = 1 \). These equations describe surfaces in three-dimensional space. To find their intersection, we set them equal: \( x^2 + y^2 = 1 \). This is our key relationship. This equation, \( x^2 + y^2 = 1 \), describes a circle in the \( xy \)-plane. Hence, the intersection of these surfaces is a curve that lies along this circle as it resides in the plane defined by \( z = 1 \).
When tackling problems with curve intersections, it’s important to think about:
When tackling problems with curve intersections, it’s important to think about:
- The dimensions involved (e.g., 3D space in this instance).
- The geometric shapes the equations represent (e.g., circles, planes).
- The resulting equations when comparing these shapes (like \( x^2 + y^2 = 1 \)).
Understanding Parameterization
Parameterization is a way of expressing a curve by introducing a parameter, typically \( t \), that moves a point along the curve. In this problem, we used \( x = \sin t \) as a parameter. By substituting \( x = \sin t \) into the equation \( x^2 + y^2 = 1 \), we can express \( y \) in terms of \( t \). This use of parameterization simplifies the expression of complex curves.
Simplifying our equation, \( (\sin t)^2 + y^2 = 1 \), gives \( y^2 = 1 - \sin^2 t \). Parameterizing allows:
Simplifying our equation, \( (\sin t)^2 + y^2 = 1 \), gives \( y^2 = 1 - \sin^2 t \). Parameterizing allows:
- Easy traversal over the curve as \( t \) changes.
- Simplifying calculations and expressions.
- Understanding the direction and speed at which the curve is traced.
Pythagorean Identity in Action
The Pythagorean identity, \( \sin^2 t + \cos^2 t = 1 \), is foundational in trigonometry. In this exercise, it helps solve for \( y \). We know \( x = \sin t \), and based on our circle equation \( x^2 + y^2 = 1 \), we have \( y^2 = 1 - \sin^2 t \). The identity gives us that \( y = \pm \cos t \). This shows how trigonometric identities link to geometry by simplifying our expressions back to fundamental forms.
Some important points about the Pythagorean identity:
Some important points about the Pythagorean identity:
- It relates directly to a unit circle.
- It allows transformations between sine and cosine.
- It is a key identity in calculating lengths and angles.
Visualizing a Circle in the xy-plane
A circle in the \( xy \)-plane is an important geometric figure whose representation greatly assists in spatial understanding. In this exercise, the equation \( x^2 + y^2 = 1 \) describes a circle of radius 1 centered at the origin. When parameterized as \( x = \sin t \) and \( y = \cos t \), it traces a circle as \( t \) ranges from 0 to \( 2\pi \), at a fixed height \( z = 1 \).
Key aspects of understanding circles include:
Key aspects of understanding circles include:
- The equation \( x^2 + y^2 = r^2 \) where \( r \) is the radius.
- A complete understanding of unit circles in trigonometry.
- Visualizing circular motion and pathways.