Chapter 9: Problem 11
In Problems \(7-16\), find the curl and the divergence of the given vector field. $$ \mathbf{F}(x, y, z)=3 x^{2} y \mathbf{i}+2 x z^{3} \mathbf{j}+y^{4} \mathbf{k} $$
Short Answer
Expert verified
The curl is \((4y^3 - 6xz^2)\mathbf{i} + (2z^3 - 3x^2)\mathbf{k}\) and the divergence is \(6xy\).
Step by step solution
01
Understand the Vector Field
The given vector field is \( \mathbf{F}(x, y, z) = 3x^2y\mathbf{i} + 2xz^3\mathbf{j} + y^4\mathbf{k} \), where the components are \( F_1 = 3x^2y \), \( F_2 = 2xz^3 \), and \( F_3 = y^4 \). Our goal is to find both the curl and the divergence of this vector field.
02
Set Up the Curl Formula
The curl of a vector field \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \) is given by the determinant: \\[ abla \times \mathbf{F} = \left| \begin{array}{ccc} \mathbf{i} & \mathbf{j} & \mathbf{k} \ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \ P & Q & R \end{array} \right| \] \ Substituting \( P = 3x^2y \), \( Q = 2xz^3 \), and \( R = y^4 \) into the determinant.
03
Calculate the Curl
Using the determinant to calculate the curl: \\[ abla \times \mathbf{F} = \left( \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} \right) \mathbf{i} - \left( \frac{\partial R}{\partial x} - \frac{\partial P}{\partial z} \right) \mathbf{j} + \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) \mathbf{k} \] \ Calculating each component: \- \( \frac{\partial R}{\partial y} = \frac{\partial y^4}{\partial y} = 4y^3 \) \ - \( \frac{\partial Q}{\partial z} = \frac{\partial (2xz^3)}{\partial z} = 6xz^2 \) \ - \( \frac{\partial R}{\partial x} = \frac{\partial y^4}{\partial x} = 0 \) \ - \( \frac{\partial P}{\partial z} = \frac{\partial (3x^2y)}{\partial z} = 0 \) \ - \( \frac{\partial Q}{\partial x} = \frac{\partial (2xz^3)}{\partial x} = 2z^3 \) \ - \( \frac{\partial P}{\partial y} = \frac{\partial (3x^2y)}{\partial y} = 3x^2 \) \Thus, the curl is \( (4y^3 - 6xz^2)\mathbf{i} - (0 - 0)\mathbf{j} + (2z^3 - 3x^2)\mathbf{k} \). This simplifies to \((4y^3 - 6xz^2)\mathbf{i} + (2z^3 - 3x^2)\mathbf{k}\).
04
Set Up the Divergence Formula
The divergence of \( \mathbf{F} \) is given by the expression: \\[ abla \cdot \mathbf{F} = \frac{\partial F_1}{\partial x} + \frac{\partial F_2}{\partial y} + \frac{\partial F_3}{\partial z} \] \ Substituting \( F_1 = 3x^2y \), \( F_2 = 2xz^3 \), and \( F_3 = y^4 \).
05
Calculate the Divergence
Calculate each partial derivative: \- \( \frac{\partial F_1}{\partial x} = \frac{\partial (3x^2y)}{\partial x} = 6xy \) \- \( \frac{\partial F_2}{\partial y} = \frac{\partial (2xz^3)}{\partial y} = 0 \) \- \( \frac{\partial F_3}{\partial z} = \frac{\partial y^4}{\partial z} = 0 \) \Hence, the divergence is \( 6xy + 0 + 0 = 6xy \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Field
A vector field is a mathematical construct that assigns a vector to every point in space. Imagine a gentle breeze sweeping through a park. At every point in the park, the wind has a specific direction and strength. This is similar to a vector field. In vector fields, each point in a space (defined by coordinates) is associated with a vector, which has both direction and magnitude.
For example, a vector field \( \mathbf{F}(x, y, z) = 3x^2y\mathbf{i} + 2xz^3\mathbf{j} + y^4\mathbf{k} \) defines vectors at each point on a 3D plane using the coordinates \(x, y,\text{ and } z\).
For example, a vector field \( \mathbf{F}(x, y, z) = 3x^2y\mathbf{i} + 2xz^3\mathbf{j} + y^4\mathbf{k} \) defines vectors at each point on a 3D plane using the coordinates \(x, y,\text{ and } z\).
- The term \(3x^2y\mathbf{i}\) indicates how the vector changes in the \(x\)-direction.
- \(2xz^3\mathbf{j}\) shows the change in the \(y\)-direction.
- Lastly, \(y^4\mathbf{k}\) depicts changes in the \(z\)-direction, reflecting the vector's magnitude and direction at that point.
Curl of a Vector Field
The curl of a vector field gives us information about the rotational motion at any point in the field. A simple way to think about curl is to imagine how a small paddlewheel would rotate if placed in the vector field. If there's rotation, the curl will be non-zero.
The formula for curl involves partial derivatives and is derived from operations similar to finding the determinant of a matrix. For a vector field \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \), the curl is calculated as:
\[abla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \ P & Q & R \end{vmatrix}\]
After computing the partial derivatives of the components and substituting, the curl gives you a new vector field. In our example, the calculated curl is \((4y^3 - 6xz^2)\mathbf{i} + (2z^3 - 3x^2)\mathbf{k}\).
The formula for curl involves partial derivatives and is derived from operations similar to finding the determinant of a matrix. For a vector field \( \mathbf{F} = P\mathbf{i} + Q\mathbf{j} + R\mathbf{k} \), the curl is calculated as:
\[abla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \ P & Q & R \end{vmatrix}\]
After computing the partial derivatives of the components and substituting, the curl gives you a new vector field. In our example, the calculated curl is \((4y^3 - 6xz^2)\mathbf{i} + (2z^3 - 3x^2)\mathbf{k}\).
- The \(\mathbf{i}\)-component, \(4y^3 - 6xz^2\), shows a localized rotation around the \(x\)-axis.
- The \(\mathbf{k}\)-component, \(2z^3 - 3x^2\), shows rotation around the \(z\)-axis.
Divergence of a Vector Field
Divergence is a measure of how much a vector field spreads out from or converges into a point. Think of how water behavior varies as it comes out of a sprinkler, either dispersing or concentrating.
The divergence of a vector field is represented by \(abla \cdot \mathbf{F}\) and involves taking partial derivatives of the components of the vector field. In mathematical terms, it is calculated as:
\[abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z}\]
For our example vector field \( \mathbf{F}(x, y, z) = 3x^2y\mathbf{i} + 2xz^3\mathbf{j} + y^4\mathbf{k} \), the divergence equates to \(6xy\).
The divergence of a vector field is represented by \(abla \cdot \mathbf{F}\) and involves taking partial derivatives of the components of the vector field. In mathematical terms, it is calculated as:
\[abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z}\]
For our example vector field \( \mathbf{F}(x, y, z) = 3x^2y\mathbf{i} + 2xz^3\mathbf{j} + y^4\mathbf{k} \), the divergence equates to \(6xy\).
- This means that at any point \((x, y, z)\), the field tries to spread out with a magnitude proportional to \(6xy\).
- A positive divergence indicates a source, suggesting that the field is expanding from that point.
- If the divergence were negative, it would imply a sink, converging the field inward.