Chapter 8: Problem 5
Find the least squares line for the given data. $$ (0,2),(1,3),(2,5),(3,5),(4,9),(5,8),(6,10) $$
Short Answer
Expert verified
The least squares line is \( y = 2.14x - 0.42 \).
Step by step solution
01
Calculate Means
First, we calculate the mean of the x-values and y-values. The x-values are 0, 1, 2, 3, 4, 5, and 6. Their mean is \( \bar{x} = \frac{0+1+2+3+4+5+6}{7} = 3 \) . The y-values are 2, 3, 5, 5, 9, 8, and 10. Their mean is \( \bar{y} = \frac{2+3+5+5+9+8+10}{7} = 6 \).
02
Compute the Slope
Now, we calculate the slope \( m \) of the least squares line using the formula \( m = \frac{\sum_{i=1}^{n}(x_i - \bar{x})(y_i - \bar{y})}{\sum_{i=1}^{n}(x_i - \bar{x})^2} \). Here's how the calculations work out:- \( \sum (x_i - \bar{x})(y_i - \bar{y}) = (0-3)(2-6) + (1-3)(3-6) + (2-3)(5-6) + (3-3)(5-6) + (4-3)(9-6) + (5-3)(8-6) + (6-3)(10-6) = 60 \)- \( \sum (x_i - \bar{x})^2 = (0-3)^2 + (1-3)^2 + (2-3)^2 + (3-3)^2 + (4-3)^2 + (5-3)^2 + (6-3)^2 = 28 \)Thus, the slope \( m = \frac{60}{28} \approx 2.14 \).
03
Compute the Intercept
Next, we find the y-intercept \( b \) using the formula \( b = \bar{y} - m \cdot \bar{x} \). Substitute the previously found values: \( b = 6 - 2.14 \cdot 3 = -0.42 \).
04
Formulate the Least Squares Line Equation
With the values of \( m \) and \( b \) established, we can write the equation of the least squares line as \( y = 2.14x - 0.42 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope Calculation
In least squares regression, calculating the slope is a crucial step to understand how changes in one variable impact another. For our given dataset, we first computed the mean of the x-values and y-values. These are fundamental to finding the slope.The slope, represented as \( m \), reveals the rate of change between the variables. To find this, we use the formula: \[ m = \frac{\sum(x_i - \bar{x})(y_i - \bar{y})}{\sum(x_i - \bar{x})^2} \] This equation helps us determine the best-fit line for the data. In simpler terms, the numerator represents how the x and y values vary together, while the denominator accounts for how much the x values vary individually.For the dataset provided, when substituting in, we have: - \( \sum (x_i - \bar{x})(y_i - \bar{y}) = 60 \) - \( \sum (x_i - \bar{x})^2 = 28 \) Thus, the slope calculation results in \[ m = \frac{60}{28} \approx 2.14 \] This slope of approximately 2.14 suggests that for every unit increase in x, y increases by about 2.14 units.
Y-Intercept Calculation
Once we have the slope, the next step is to determine the y-intercept, denoted as \( b \). The y-intercept is the point where the line crosses the y-axis, providing a starting point for the line on the graph.The formula used for this is: \[ b = \bar{y} - m \cdot \bar{x} \] This allows us to relate the slope we've calculated to the actual points in our dataset.For our data:- \( \bar{x} = 3 \) and \( \bar{y} = 6 \)- Using our slope \( m = 2.14 \), the calculation becomes: \( b = 6 - 2.14 \times 3 = -0.42 \) The y-intercept of \(-0.42\) implies that when \( x = 0 \), the predicted \( y \) value on this line is \(-0.42\). This value helps define the starting point of our regression line in the real-world context of the data.
Data Analysis
Analyzing data using least squares regression is a powerful method to understand relationships between variables. With our line equation \( y = 2.14x - 0.42 \), we can predict y values from given x values. This analytical approach is valuable in making predictions or understanding trends. Several key aspects should be considered when performing data analysis using least squares regression:
- **Line of Best Fit**: The least squares method aims to minimize the differences between the data points and the predicted values given by the regression line.
- **Predictive Power**: It allows us to make forecasts based on the model, which can guide decisions and strategies.
- **Correlation Insight**: The slope indicates the strength and direction of a linear relationship between variables. In our case, a slope of 2.14 suggests a moderately strong positive link between x and y.