Chapter 8: Problem 22
$$ \begin{aligned} &\text { If } \mathbf{A}=\left(\begin{array}{ll} 1 & 2 \\ 2 & 4 \end{array}\right) \text { and } \mathbf{B}=\left(\begin{array}{rr} -2 & 3 \\ 5 & 7 \end{array}\right), \text { find }\\\ &\text { (a) } \mathbf{A}+\mathbf{B}^{T} \text { , }\\\ &\text { (b) } 2 \mathbf{A}^{T}-\mathbf{B}^{T},(\mathbf{c}) \mathbf{A}^{T}(\mathbf{A}-\mathbf{B}) . \end{aligned} $$
Short Answer
Step by step solution
Transpose Matrix B
Compute A + B^T
Transpose Matrix A
Compute 2A^T
Compute 2A^T - B^T
Compute A - B
Compute A^T(A - B)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Addition
- \( \mathbf{A} = \begin{pmatrix} 1 & 2 \ 2 & 4 \end{pmatrix} \)
- \( \mathbf{B} = \begin{pmatrix} -2 & 5 \ 3 & 7 \end{pmatrix} \)
- The top-left element becomes \( 1 + (-2) = -1 \)
- The top-right element becomes \( 2 + 5 = 7 \)
- The bottom-left element becomes \( 2 + 3 = 5 \)
- The bottom-right element becomes \( 4 + 7 = 11 \)
Matrix Transposition
- \( \mathbf{B} = \begin{pmatrix} -2 & 3 \ 5 & 7 \end{pmatrix} \)
- \( \mathbf{B}^T = \begin{pmatrix} -2 & 5 \ 3 & 7 \end{pmatrix} \)
Matrix Multiplication
- \( \mathbf{A}^T = \begin{pmatrix} 1 & 2 \ 2 & 4 \end{pmatrix} \)
- \( \mathbf{A} - \mathbf{B} = \begin{pmatrix} 3 & -1 \ -3 & -3 \end{pmatrix} \)
- Final matrix: \( \begin{pmatrix} -3 & -7 \ -6 & -14 \end{pmatrix} \)
Matrix Subtraction
- \( \mathbf{A} = \begin{pmatrix} 1 & 2 \ 2 & 4 \end{pmatrix} \)
- \( \mathbf{B} = \begin{pmatrix} -2 & 3 \ 5 & 7 \end{pmatrix} \)
- Top-left: \( 1 - (-2) = 3 \)
- Top-right: \( 2 - 3 = -1 \)
- Bottom-left: \( 2 - 5 = -3 \)
- Bottom-right: \( 4 - 7 = -3 \)