Chapter 8: Problem 14
$$ \begin{aligned} &\text { In Problems } \text { } , \text { find the entries } c_{23} \text { and } c_{12} \text { for the matrix }\\\ &\mathbf{C}=2 \mathbf{A}-3 \mathbf{B} \end{aligned} $$ $$ \mathbf{A}=\left(\begin{array}{rrr} 1 & -1 & 1 \\ 2 & 2 & 1 \\ 0 & -4 & 1 \end{array}\right), \quad \mathbf{B}=\left(\begin{array}{lll} 2 & 0 & 5 \\ 0 & 4 & 0 \\ 3 & 0 & 7 \end{array}\right) $$
Short Answer
Step by step solution
Understand the Problem
Calculate \(2\mathbf{A}\)
Calculate \(3\mathbf{B}\)
Calculate \(\mathbf{C} = 2\mathbf{A} - 3\mathbf{B}\)
Identify \( c_{23} \) and \( c_{12} \)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Addition
For example, if we have matrices \( \mathbf{X} \) and \( \mathbf{Y} \) that are both 3x3 matrices, their sum \( \mathbf{Z} = \mathbf{X} + \mathbf{Y} \) is given by adding each corresponding element:
- The element in the first row, first column of \( \mathbf{Z} \) is \( x_{11} + y_{11} \).
- The element in the first row, second column of \( \mathbf{Z} \) is \( x_{12} + y_{12} \).
- This pattern continues throughout the matrix.
Matrix Subtraction
Let's say you have two matrices \( \mathbf{P} \) and \( \mathbf{Q} \), both 3x3. When you find the matrix \( \mathbf{R} = \mathbf{P} - \mathbf{Q} \), each element in \( \mathbf{R} \) is formulated as follows:
- The element in the first row, first column of \( \mathbf{R} \) is \( p_{11} - q_{11} \).
- The element in the first row, second column of \( \mathbf{R} \) is \( p_{12} - q_{12} \).
- This subtraction continues for all corresponding elements in the matrix.
Scalar Multiplication
For instance, consider a matrix \( \mathbf{M} \) and a scalar \( k \). The resulting matrix, \( k \mathbf{M} \), has each element of \( \mathbf{M} \) multiplied by \( k \). More precisely:
- The element in the first row, first column of \( k \mathbf{M} \) is \( k \times m_{11} \).
- The element in the first row, second column of \( k \mathbf{M} \) is \( k \times m_{12} \).
- This process is repeated for every entry in the matrix.
Matrix Elements
Consider a simple 3x3 matrix:\(\begin{pmatrix} a & b & c \d & e & f \g & h & i \end{pmatrix}\)
- The element \( a \) is located in the first row, first column, and can be referred to as \( m_{11} \).
- The element \( e \) in the second row, second column can be denoted as \( m_{22} \).
- Each element has a unique position, indicated by its row and column number, such as \( m_{32} \) for the element in the third row, second column.