Chapter 3: Problem 57
Find a homogeneous linear differential equation with constant coefficients whose general solution is given. $$ y \quad c_{1}+c_{2} x+c_{3} e^{7 x} $$
Short Answer
Expert verified
The differential equation is \( y''' - 7y'' = 0 \).
Step by step solution
01
Identify the General Solution Components
The general solution given is \( y = c_{1} + c_{2} x + c_{3} e^{7x} \). It comprises a polynomial component \( c_{1} + c_{2} x \) and an exponential component \( c_{3} e^{7x} \). These components will guide us to determine the roots of the characteristic equation of the differential equation.
02
Determine Characteristics for Polynomial Component
The polynomial component \( c_{1} + c_{2} x \) reflects the presence of real roots with multiplicity. Specifically, it corresponds to a root \( r = 0 \) with multiplicity 2 in the characteristic equation, resulting in solutions like \( c_{1} + c_{2} x \).
03
Determine Characteristics for Exponential Component
The exponential term \( c_{3} e^{7x} \) reflects the existence of a real, distinct root \( r = 7 \) in the characteristic equation. This term indicates an exponential solution linked to this non-zero real root.
04
Formulate the Characteristic Polynomial
Based on the roots identified: a double root at \( r = 0 \) and a simple root at \( r = 7 \). The characteristic polynomial can be expressed as \((r - 0)^2 (r - 7) = r^2 (r - 7)\).
05
Write the Differential Equation
The characteristic polynomial \( r^2 (r - 7) \) corresponds to the differential operator \( (D^2)(D - 7) \), where \( D = \frac{d}{dx} \). Applying this gives the differential equation: \[ \frac{d^3y}{dx^3} - 7 \frac{d^2y}{dx^2} = 0. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Characteristic Equation
In the study of homogeneous linear differential equations, the characteristic equation plays a critical role. Basically, it is a tool that helps to find solutions for differential equations.
The characteristic equation is obtained from the differential equation by substituting the derivatives with powers of a variable (usually denoted as \( r \)). This substitution transforms the differential operator into a polynomial equation. In our exercise, we identified the characteristic polynomial as \( r^2 (r - 7) \) from the general solution components.
The characteristic equation is obtained from the differential equation by substituting the derivatives with powers of a variable (usually denoted as \( r \)). This substitution transforms the differential operator into a polynomial equation. In our exercise, we identified the characteristic polynomial as \( r^2 (r - 7) \) from the general solution components.
- Step 2 of the solution revealed real roots indicating polynomial components.
- Step 3 connected exponential solutions with distinct roots.
Roots of Polynomial
The roots of the characteristic polynomial are crucial in forming the solution to a differential equation. They determine the form of the general solution by dictating whether the solution involves exponentials, sines, or polynomials.
In our case, the solution consists of a polynomial component \( c_1 + c_2 x \) and an exponential component \( c_3 e^{7x} \).
In our case, the solution consists of a polynomial component \( c_1 + c_2 x \) and an exponential component \( c_3 e^{7x} \).
- The polynomial component arises from a double root at \( r = 0 \).
- The exponential component is due to a single, distinct root of \( r = 7 \).
General Solution
The general solution of a homogeneous linear differential equation encompasses all possible solutions derived from its characteristic equation. It typically comprises terms based on the roots and their multiplicities.
For the given solution \( y = c_1 + c_2 x + c_3 e^{7x} \), each part originates from the roots of the characteristic polynomial.
For the given solution \( y = c_1 + c_2 x + c_3 e^{7x} \), each part originates from the roots of the characteristic polynomial.
- \( c_1 + c_2 x \) corresponds to the double root \( r = 0 \).
- \( c_3 e^{7x} \) stems from the distinct root \( r = 7 \).
Exponential Functions
Exponential functions often appear in the solutions of linear differential equations, especially when the characteristic equation has distinct or complex roots. They take the form \( e^{rx} \), where \( r \) is a root from the characteristic polynomial.
In our example, the term \( c_3 e^{7x} \) represents the exponential part of the solution.
In our example, the term \( c_3 e^{7x} \) represents the exponential part of the solution.
- It arises from the distinct root \( r = 7 \).
- This exponential solution contributes its unique shape to the behavior of the general solution.