Chapter 3: Problem 33
In Problems 31-34, verify that the given two-parameter family of functions is the general solution of the nonhomogeneous differential equation on the indicated interval. $$ \begin{aligned} &y^{\prime \prime}-4 y^{\prime}+4 y=2 e^{2 x}+4 x-12 \\ &y=c_{1} e^{2 x}+c_{2} x e^{2 x}+x^{2} e^{2 x}+x-2,(-\infty, \infty) \end{aligned} $$
Short Answer
Step by step solution
Calculate y' and y''
Substitute into the Differential Equation
Simplify the Expression
Verify the Match
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
General Solution Verification
- Determine the derivatives: We begin by finding the first and second derivatives of the given function. This helps us to substitute back into the differential equation.
- Substitute and verify: After calculating the derivatives, we substitute them into the differential equation to check if both sides equal.
Differentiation Techniques
- We use the chain rule to differentiate exponential functions like \(e^{2x}\), which involves taking the derivative of the exponent and multiplying it by the original function.
- The product rule is applied when we differentiate terms like \(xe^{2x}\) or \(x^2e^{2x}\), which means differentiating each part separately and then using the product rule formula, \( (uv)' = u'v + uv' \).
Solution Simplification
- The simplification usually involves combining like terms. For example, gathering terms with \(e^{2x}\), \( xe^{2x}\), and \( x^2e^{2x}\).
- It is crucial to systematically cancel out terms that naturally negate each other during the substitution process, significantly shortening the expression.
- In this exercise, simplification leads us to the form \(2e^{2x} + 4x - 12\), which should match the right hand side of the original differential equation.
Interval Analysis
- The nature of the solution, being composed of exponential and polynomial terms, suggests that it is defined for all real numbers, fitting the interval perfectly.
- Additionally, interval analysis confirms that there are no discontinuities or undefined points within the solution across the specified range.
- This step gives us confidence that our verification holds true comprehensively for the entire interval, ensuring the solution's applicability in a broad sense.