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Construct a linear fractional transformation that maps the given triple \(z_{1}, z_{2}\), and \(z_{3}\) to the triple \(w_{1}, w_{2}\), and \(w_{3}\). \(-1,0,1\) to \(\infty,-i, 1\)

Short Answer

Expert verified
The transformation is \( f(z) = \frac{(2+i)z - i}{z + 1} \).

Step by step solution

01

Understanding the Linear Fractional Transformation

A linear fractional transformation is a function of the form \( f(z) = \frac{az + b}{cz + d} \) where \( a, b, c, \) and \( d \) are complex numbers and \( ad - bc eq 0 \). This transformation maps one set of points in the complex plane to another.
02

Setting Up the Transformation Conditions

To determine the transformation, you need to satisfy the conditions that the points \(-1, 0, \) and \( 1 \) are mapped to \( \infty, -i, \) and \( 1 \) respectively. Therefore:\(\begin{align*}f(-1) & = \infty, \f(0) & = -i, \f(1) & = 1.\end{align*}\)
03

Apply the Condition for \(z_1 = -1\)

If \( f(-1) = \infty \), then \( -c + d = 0 \). This implies that \( d = c \).
04

Apply the Condition for \(z_2 = 0\)

Since \( f(0) = -i \), we have \( f(0) = \frac{b}{d} = -i \). Thus, \( b = -id \).
05

Apply the Condition for \(z_3 = 1\)

As \( f(1) = 1 \), we equate \( \frac{a + b}{c + d} = 1 \). Substituting \( b = -id \) and \( d = c \), this becomes:\[ a - id = 2c. \]
06

Solve the System of Equations

We now have the system:\(\begin{align*}d &= c, \b &= -id, \a - id &= 2c.\end{align*}\)Substitute \( b \) and \( d \):\( a - i(c) = 2c \) leads to \( a = 2c + ic \) which simplifies to \( a = (2 + i)c \).
07

Determining the Transformation Coefficients

Let \( c = 1 \), a possible choice to satisfy \( a = (2+i)c \). This gives us:\[ a = 2 + i, \quad b = -i, \quad c = 1, \quad d = 1. \]
08

Construct the Transformation

Substitute \( a, b, c, \) and \( d \) into the transformation function:\[ f(z) = \frac{(2+i)z - i}{z + 1}. \]
09

Verify the Mapping

Check each mapping condition with the function:- For \( z = -1 \), \( f(-1) = \frac{(2+i)(-1) - i}{-1 + 1} = \frac{-\infty}{0} = \infty \).- For \( z = 0 \), \( f(0) = \frac{-i}{1} = -i \).- For \( z = 1 \), \( f(1) = \frac{2+i - i}{1+1} = 1 \). All conditions are satisfied.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Numbers
Complex numbers are a foundational element in mathematics, particularly when dealing with transformations like the linear fractional transformation. A complex number is expressed as a combination of a real part and an imaginary part:
  • Real part is denoted as a real number, for example, 2.
  • Imaginary part is represented as an imaginary unit 'i,' which satisfies the equation \( i^2 = -1 \), for instance, 3i.
Thus, a complex number looks like 2 + 3i. When working with transformations, these numbers serve as coordinates on the complex plane. They help map one set of values onto another using specified rules. Understanding how to manipulate complex numbers is crucial for applying and constructing transformations adequately. This manipulation includes addition, subtraction, multiplication, and division, all of which adhere to standard operations while also considering the unique property that \( i^2 = -1 \).
Mapping Conditions
Mapping conditions are the desired outcomes for each point transformation in a linear fractional transformation. They specify where each input complex number \( z \) should map under the transformation to a new output number \( w \).
To set up mapping conditions:
  • Identify the points in the original complex plane like \( z_1, z_2, \) and \( z_3 \).
  • Determine their corresponding locations in the target map like \( w_1, w_2, \) and \( w_3 \).
For instance, mapping points like
  • \( z_1 = -1 \) maps to \( w_1 = \infty \)
  • \( z_2 = 0 \) maps to \( w_2 = -i \)
  • \( z_3 = 1 \) maps to \( w_3 = 1 \)
This understanding is essential because each condition becomes an equation in your system, helping you find the coefficients of your transformation function. These conditions ensure that the transformation matches the specified mapping.
Transformation Function
A transformation function is a type of mapping, specifically a linear fractional transformation in this context, which is represented by the formula \( f(z) = \frac{az + b}{cz + d} \). This formula transforms a complex input \( z \) to another complex number. Key components include:
  • Coefficients \( a, b, c, \) and \( d \) are complex numbers.
  • A requirement is that \( ad - bc eq 0 \) to ensure the function is well-defined and has an inverse.
The transformation function is utilized to map each input \( z \) to a pre-determined output \( w \) using the transformation's coefficients. To find these coefficients, one must solve the system of equations derived from the mapping conditions set for the specific transformation task. When the transformation is accurately defined, every input-output pair should satisfy the transformation function.
System of Equations
Creating and solving a system of equations is crucial in the context of determining the coefficients for the linear fractional transformation. Based on the mapping conditions, each condition translates to an equation that relates to the coefficients \( a, b, c, \) and \( d \). For instance, given conditions:
  • If \( f(-1) = \infty \), it means \(-c + d = 0 \).
  • If \( f(0) = -i \), it implies that \( \frac{b}{d} = -i \).
  • If \( f(1) = 1 \), you have \( \frac{a+b}{c+d} = 1 \).
These conditions bring together equations, such as \(-c + d = 0\), \( b = -id\), and \( a - id = 2c \), creating a system. Solving this system enables you to calculate the specific values for \( a, b, c, \) and \( d \), which make the transformation function valid. Once solved, these values are substituted back into the transformation equation, allowing the satisfaction of all given mapping conditions.

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Most popular questions from this chapter

Use the identity \(\sinh z=-i \sin (i z)\) to find the image of the strip \(-\pi / 2 \leq y \leq \pi / 2, x \geq 0\), under the complex mapping \(w=\sinh z\). What is the image of a vertical line segment in the strip?

Construct a linear fractional transformation that maps the given triple \(z_{1}, z_{2}\), and \(z_{3}\) to the triple \(w_{1}, w_{2}\), and \(w_{3}\). \(1, i,-i\) to \(-1,0,3\)

A complex velocity potential \(G(z)\) is defined on a region \(R\). (a) Find the stream function and verify that the boundary of \(R\) is a streamline. (b) Find the corresponding velocity vector field \(\mathbf{V}(x, y)\). (c) Use a graphing utility to sketch the streamlines of the flow. \(G(z)=z^{2}+1 / z^{2}\)

A real-valued function \(\phi(x, y)\) is called biharmonic in a domain \(D\) when the fourth-order differential equation $$\frac{\partial^{4} \phi}{\partial x^{4}}+2 \frac{\partial^{4} \phi}{\partial x^{2} \partial y^{2}}+\frac{\partial^{4} \phi}{\partial y^{4}}=0$$ at all points in \(D\). Examples of biharmonic functions are the Airy stress function in the mechanics of solids and velocity potentials in the analysis of viscous fluid flow. (a) Show that if \(\phi\) is biharmonic in \(D\), then \(u=\partial^{2} \phi / \partial x^{2}+\) \(\partial^{2} \phi / \partial y^{2}\) is harmonic in \(D\). (b) If \(g(z)\) is analytic in \(D\) and \(\phi(x, y)=\operatorname{Re}(\bar{z} g(z))\), show that \(\phi\) is biharmonic in \(D\).

Find a complex mapping from the given region \(R\) in the \(z\) -plane to the image region \(R^{\prime}\) in the \(w\) -plane. Strip \(1 \leq y \leq 4\) to the strip \(0 \leq u \leq 3\)

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