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In Problems 1-22, solve the given differential equation by separation of variables. $$ \frac{d y}{d x}=\left(\frac{2 y+3}{4 x+5}\right)^{2} $$

Short Answer

Expert verified
The solution to the differential equation is \( y = -\frac{1}{2} \left(\frac{1}{4(4x+5)} + C\right)^{-1} - \frac{3}{2} \).

Step by step solution

01

Recognize the Differential Equation

The given differential equation is \( \frac{dy}{dx} = \left(\frac{2y+3}{4x+5}\right)^2 \). This is a first-order differential equation which can be solved using the method of separation of variables.
02

Separate Variables

We start by rewriting the differential equation to separate the variables. Multiply both sides by \( dx \) and divide by \( (2y+3)^2 \) to isolate \( dy \) and \( dx \): \[ \frac{1}{(2y+3)^2} \, dy = \frac{1}{(4x+5)^2} \, dx \]
03

Integrate Both Sides

Integrate the left side with respect to \( y \), and the right side with respect to \( x \): \[ \int \frac{1}{(2y+3)^2} \, dy = \int \frac{1}{(4x+5)^2} \, dx \].
04

Solve the Integrals

The left integral can be calculated by the substitution method or by recognizing it as a standard integral: \[ -\frac{1}{2(2y+3)} + C_1 = -\frac{1}{4(4x+5)}+ C_2 \].
05

Solve for the Integration Constants and General Solution

Combine the constants from both integrals into a single constant \( C \): \[ \frac{1}{2(2y+3)} = \frac{1}{4(4x+5)} + C \].With this, solve for \( y \) in terms of \( x \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Separation of Variables
Separation of variables is a powerful technique used to solve differential equations. It is applied when you can rearrange a differential equation so that each variable, along with its differential, appears on opposite sides of the equation. This method is particularly useful for first-order differential equations, such as the one in this example.

Let's break this down: we start with \( \frac{dy}{dx} = \left(\frac{2y+3}{4x+5}\right)^2 \). We aim to set all terms involving 'y' on one side and all terms involving 'x' on the other. By manipulating the equation, we achieve \( \frac{1}{(2y+3)^2} \, dy = \frac{1}{(4x+5)^2} \, dx \).

This arrangement lets us handle the 'y' terms separately from the 'x' terms. The method has mobilized complex differential equations by reducing them to a form where both sides can be separately integrated, as seen here.
First-order Differential Equation
A first-order differential equation is one that involves the first derivative of a function but no higher derivatives. The problem we are examining is a textbook example of a first-order differential equation: the equation \( \frac{dy}{dx} = \left(\frac{2y+3}{4x+5}\right)^2 \) contains only the first derivative \( \frac{dy}{dx} \).

First-order differential equations describe rates of change and appear frequently in fields like physics, biology, and economics. They can often be solved using various methods, including the separation of variables. Solutions to these equations provide a function 'y' that describes how 'y' changes relative to 'x'. This characteristic makes them incredibly useful for modeling natural phenomena.
Integration
Integration is a fundamental concept in calculus used to solve differential equations. Once we have separated variables, as in \( \frac{1}{(2y+3)^2} \, dy = \frac{1}{(4x+5)^2} \, dx \), each side of the equation is integrated separately. Integration reverses differentiation, allowing us to find a function from its derivative.

For the left side, integrate with respect to 'y':
- \( \int \frac{1}{(2y+3)^2} \, dy \) uses substitution or recognition as a standard form, resulting in \( -\frac{1}{2(2y+3)} + C_1 \).

For the right side, integrate with respect to 'x':
- \( \int \frac{1}{(4x+5)^2} \, dx \), which by substitute or recognizing yields \( -\frac{1}{4(4x+5)} + C_2 \).

Integrating both sides transforms a complicated rate of change to simpler expressions, leading us to solve the initial problem.
Solving Differential Equations
Solving differential equations involves finding a function or set of functions that satisfy the differential equation. Once we integrate both sides of a separated differential equation, it's essential to combine the constants obtained from integration into a single constant:\( C \). This process gives us the general solution.

In our exercise, combining constants leads us to \( \frac{1}{2(2y+3)} = \frac{1}{4(4x+5)} + C \). Solving for 'y' in terms of 'x' provides the particular solution, which is often the ultimate goal.

The beauty of solving differential equations is that it enables us to predict and understand dynamic systems. Whether it's predicting population growth or calculating electrical currents, this solution equips us with a mathematical model describing the system's behavior.

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Most popular questions from this chapter

In the study of population dynamics one of the most famous models for a growing but bounded population is the logistic equation $$ \frac{d P}{d t}=P(a-b P) $$ where \(a\) and \(b\) are positive constants. Although we will come back to this equation and solve it by an alternative method in Section \(2.8\), solve the \(\mathrm{DE}\) this first time using the fact that it is a Bernoulli equation.

The differential equation $$ \frac{d y}{d x}=\frac{-x+\sqrt{x^{2}+y^{2}}}{y} $$ describes the shape of a plane curve \(C\) that will reflect all incoming light beams to the same point and could be a model for the mirror of a reflecting telescope, a satellite antenna, or a solar collector. See Problem 29 in Exercises \(1.3\). There are several ways of solving this \(\mathrm{DE}\). (a) Verify that the differential equation is homogeneous (see Section 2.5). Show that the substitution \(y=u x\) yields $$ \frac{u d u}{\sqrt{1+u^{2}}\left(1-\sqrt{\left.1+u^{2}\right)}\right.}=\frac{d x}{x}. $$ Use a CAS (or another judicious substitution) to integrate the left-hand side of the equation. Show that the curve \(C\) must be a parabola with focus at the origin and is symmetric with respect to the \(x\) -axis. (b) Show that the first differential equation can also be solved by means of the substitution \(u=x^{2}+y^{2}\).

The differential equation \(d P / d t=\) \((k \cos t) P\), where \(k\) is a positive constant, is a mathematical model for a population \(P(t)\) that undergoes yearly seasonal fluctuations. Solve the equation subject to \(P(0)=P_{0}\). Use a graphing utility to obtain the graph of the solution for different choices of \(P_{0}\)

Express the solution of the initial-value problem \(y^{\prime}-2 x y=1\), \(y(1)=1\), in terms of \(\operatorname{erf}(x)\)

Solve the given differential equation by finding, as in Example 4 , an appropriate integrating factor. $$ \left(y^{2}+x y^{3}\right) d x+\left(5 y^{2}-x y+y^{3} \sin y\right) d y=0 $$

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