Chapter 19: Problem 15
Determine whether the given geometric series is convergent or divergent. If convergent, find its sum. \(\sum_{k=0}^{\infty}(1-i)^{k}\)
Short Answer
Expert verified
The series is divergent.
Step by step solution
01
Identify the First Term
The given series is \( \sum_{k=0}^{\infty}(1-i)^{k} \). The first term \( a \) of the series is the value of the expression when \( k=0 \). Thus, \( a = (1-i)^{0} = 1 \).
02
Identify the Common Ratio
The common ratio \( r \) is the term that is used to multiply each term to get the next term in the series. It is given by what you multiply each term by: \( r = (1-i) \).
03
Check for Convergence
A geometric series converges if the absolute value of the common ratio \( |r| \) is less than 1. Calculate \( |1-i| \):\[|1-i| = \sqrt{1^2 + (-1)^2} = \sqrt{2}\]Since \( \sqrt{2} > 1 \), the series is divergent.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers
Complex numbers are numbers that have both a real part and an imaginary part. They are typically represented in the form \( a + bi \), where \( a \) is the real part and \( b \) is the imaginary part. The imaginary part includes the imaginary unit \( i \), which is defined by the property \( i^2 = -1 \). This unique characteristic allows complex numbers to provide solutions to equations that would be unsolvable using only real numbers.
For instance, the complex number \( 1-i \) used in the original exercise consists of a real part (1) and an imaginary part (-1). When working with complex numbers, you often find yourself performing operations like addition, subtraction, multiplication, and division, just like with real numbers. In the step-by-step solution, they calculate the modulus or absolute value of \( 1-i \), which involves finding the distance of the number from the origin in a complex plane:
This modulus is crucial in determining properties such as convergence in a geometric series.
For instance, the complex number \( 1-i \) used in the original exercise consists of a real part (1) and an imaginary part (-1). When working with complex numbers, you often find yourself performing operations like addition, subtraction, multiplication, and division, just like with real numbers. In the step-by-step solution, they calculate the modulus or absolute value of \( 1-i \), which involves finding the distance of the number from the origin in a complex plane:
- Absolute value: \(|1-i| = \sqrt{1^2 + (-1)^2} = \sqrt{2}\)
This modulus is crucial in determining properties such as convergence in a geometric series.
Convergence and Divergence
When analyzing series, one of the central concepts is determining whether the series is convergent or divergent. A geometric series is said to converge if the absolute value of its common ratio \( |r| \) is less than 1. This means the terms are getting smaller and approaching a limit, resulting in the series adding up to a finite value.
Conversely, a series diverges if \( |r| \geq 1 \). This means the terms of the series do not approach zero, causing the series to increase indefinitely or oscillate without approaching a specific value. In the original exercise, we determined that the series \( \sum_{k=0}^{\infty}(1-i)^k \) is divergent because:
Understanding convergence and divergence helps us predict the behavior of infinite series, allowing us to determine whether the series will result in a meaningful sum or not.
Conversely, a series diverges if \( |r| \geq 1 \). This means the terms of the series do not approach zero, causing the series to increase indefinitely or oscillate without approaching a specific value. In the original exercise, we determined that the series \( \sum_{k=0}^{\infty}(1-i)^k \) is divergent because:
- \(|1-i| = \sqrt{2}\), which is greater than 1.
Understanding convergence and divergence helps us predict the behavior of infinite series, allowing us to determine whether the series will result in a meaningful sum or not.
Infinite Series
An infinite series is the sum of an infinite sequence of terms. More formally, it is expressed in the form \( \sum_{k=0}^{\infty} a_k \), where \( a_k \) represents the sequence of terms.
This concept is particularly important in mathematics because it allows us to extend the ideas of summation beyond a finite number of terms to an infinite context. Geometric series are a fundamental example of infinite series. They follow the specific form \( a + ar + ar^2 + ar^3 + \ldots \) where \( a \) is the first term and \( r \) is the common ratio.
.
This concept is particularly important in mathematics because it allows us to extend the ideas of summation beyond a finite number of terms to an infinite context. Geometric series are a fundamental example of infinite series. They follow the specific form \( a + ar + ar^2 + ar^3 + \ldots \) where \( a \) is the first term and \( r \) is the common ratio.
.
- For a geometric series to have a sum, it must converge, which requires the criterion \( |r| < 1 \).