Chapter 17: Problem 36
Express the given complex number first in polar form and then in the form \(a+i b\). $$ \frac{\left[8\left(\cos \frac{3 \pi}{8}+i \sin \frac{3 \pi}{8}\right)\right]^{3}}{\left[2\left(\cos \frac{\pi}{16}+i \sin \frac{\pi}{16}\right)\right]^{10}} $$
Short Answer
Expert verified
The final expression in rectangular form is \( \frac{i}{2} \).
Step by step solution
01
Identify Polar Forms
The given complex numbers are already in polar form:- \( z_1 = 8 \left(\cos \frac{3\pi}{8} + i \sin \frac{3\pi}{8} \right) \) with modulus \( r_1 = 8 \) and argument \( \theta_1 = \frac{3\pi}{8} \).- \( z_2 = 2 \left(\cos \frac{\pi}{16} + i \sin \frac{\pi}{16} \right) \) with modulus \( r_2 = 2 \) and argument \( \theta_2 = \frac{\pi}{16} \).
02
Apply De Moivre's Theorem
Calculate each power using De Moivre's Theorem:- \( z_1^3 = 8^3 \left(\cos \left( 3 \times \frac{3\pi}{8} \right) + i \sin \left( 3 \times \frac{3\pi}{8} \right) \right) \).- \( z_2^{10} = 2^{10} \left(\cos \left( 10 \times \frac{\pi}{16} \right) + i \sin \left( 10 \times \frac{\pi}{16} \right) \right) \).
03
Simplify the Powers
Calculate each power:- \( 8^3 = 512 \).- \( 2^{10} = 1024 \).Calculate the arguments:- The argument for \( z_1^3 \) is \( \frac{9\pi}{8} \).- The argument for \( z_2^{10} \) is \( \frac{10\pi}{16} = \frac{5\pi}{8} \).
04
Divide the Polar Forms
Divide the moduli and subtract the arguments for the quotient:\[ \frac{z_1^3}{z_2^{10}} = \frac{512}{1024} \left( \cos \left( \frac{9\pi}{8} - \frac{5\pi}{8} \right) + i \sin \left( \frac{9\pi}{8} - \frac{5\pi}{8} \right) \right) = \frac{1}{2} \left( \cos \frac{4\pi}{8} + i \sin \frac{4\pi}{8} \right) \].Simplify the argument: \( \cos \frac{\pi}{2} = 0 \) and \( \sin \frac{\pi}{2} = 1 \).
05
Convert to Rectangular Form
Convert the polar form to rectangular form:\[ \frac{1}{2} \left( 0 + i \cdot 1 \right) = \frac{i}{2} \].
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Form
The polar form of complex numbers expresses them in terms of a magnitude and angle. It is particularly useful when dealing with multiplication and division of complex numbers, as well as calculating powers and roots. In the polar form, a complex number is represented as
- \( z = r \left(\cos \theta + i \sin \theta\right) \)
De Moivre's Theorem
De Moivre's Theorem beautifully links complex numbers in polar form to the world of trigonometry and exponents. It states that for a complex number \( z = r(\cos \theta + i \sin \theta) \) and any integer \( n \), the power of \( z^n \) is computed as
- \[ z^n = r^n \left( \cos(n\theta) + i \sin(n\theta) \right) \]
Rectangular Form
The rectangular form of a complex number, also known as Cartesian form, is simply the expression
- \( a + ib \)
- \( a = r \cos \theta \)
- \( b = r \sin \theta \)
Complex Arithmetic
Arithmetic involving complex numbers, whether in polar or rectangular form, follows specific rules. In rectangular form:
- Addition/Subtraction: \(a + ib\) and \(c + id\) result in \((a+c) + i(b+d)\).
- Multiplication: \(a + ib\)(c + id) = \(ac-bd) + i(ad+bc)\).
- Division requires multiplying by the complex conjugate.
- Multiplication: Simply multiply the moduli and add the arguments.
- Division: Divide the moduli and subtract the arguments.