Chapter 17: Problem 34
Express \(\operatorname{Ln} z\) in the form \(a+i b\). \(z=(1+i)^{4}\)
Short Answer
Expert verified
\(\ln z = \ln 4 + i\pi\).
Step by step solution
01
Find the modulus of the complex number
First, we find the modulus of the base complex number \((1 + i)\). The modulus is calculated as \(|1+i| = \sqrt{1^2 + 1^2} = \sqrt{2}\).
02
Express the complex number in polar form
Convert the complex number \(1+i\) to its polar form. The modulus is \(\sqrt{2}\) (from Step 1), and the argument \(\theta\) is determined by \(\tan^{-1}(\frac{1}{1}) = \frac{\pi}{4}\). Hence, in polar form, \(1+i = \sqrt{2}(\cos \frac{\pi}{4} + i \sin \frac{\pi}{4})\).
03
Use De Moivre's Theorem
Apply De Moivre's theorem to \((1+i)^4\). We have: \((\sqrt{2})^4 (\cos(4 \cdot \frac{\pi}{4}) + i \sin(4 \cdot \frac{\pi}{4})) = 4(\cos \pi + i \sin \pi)\), which simplifies to \(-4\).
04
Convert back to rectangular form
Recognize that \(-4\) in rectangular form is \(-4+0i\).
05
Apply the logarithmic property
Now apply the complex logarithm formula: \(\ln z = \ln |z| + i\arg z\). For \(-4\), the modulus \(|z| = 4\) and \(\arg z = \pi\).
06
Calculate the logarithm
Compute \(\ln 4 + i\pi\). So, \(\ln(-4) = \ln 4 + i\pi\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Modulus
The complex modulus is a core concept when working with complex numbers. It is similar to finding the length of a vector in two dimensions.
The modulus of a complex number is indicated as |z|, where the complex number is in the form of a + bi. In mathematical terms, it is given by the formula: \[ |z| = \sqrt{a^2 + b^2} \]This formula calculates the distance of the complex number from the origin in the complex plane.
The modulus of a complex number is indicated as |z|, where the complex number is in the form of a + bi. In mathematical terms, it is given by the formula: \[ |z| = \sqrt{a^2 + b^2} \]This formula calculates the distance of the complex number from the origin in the complex plane.
- For example, with z = 1 + i, the modulus is |1+i| = \sqrt{1^2 + 1^2} = \sqrt{2}.
- The modulus is always a non-negative real number.
Polar Form
The polar form of a complex number provides an alternative way of expressing complex numbers, especially useful for multiplication and division. Instead of using the rectangular (a + bi) form, the polar form utilizes the modulus and the argument (angle) of the number.
A complex number in polar form is expressed as: \[ z = r(\cos \theta + i \sin \theta) \]where:
A complex number in polar form is expressed as: \[ z = r(\cos \theta + i \sin \theta) \]where:
- r is the modulus or magnitude, equivalent to |z|.
- \theta is the argument or angle.
- r = \sqrt{2}, and \theta = \frac{\pi}{4}, hence 1 + i can be written as \sqrt{2}(\cos \frac{\pi}{4} + i \sin \frac{\pi}{4}).
De Moivre's Theorem
De Moivre's Theorem is a powerful tool for finding powers and roots of complex numbers when they are in polar form. This theorem states that for a complex number z in polar form:\[ (r(\cos \theta + i \sin \theta))^n = r^n(\cos(n\theta) + i \sin(n\theta)) \]This simplifies the computation of powers of complex numbers significantly.
For example, for (1+i)^4, you first express 1+i in polar form: \(\sqrt{2}(\cos \frac{\pi}{4} + i \sin \frac{\pi}{4})\). Applying De Moivre's Theorem:\[ (\sqrt{2})^4 (\cos(4 \cdot \frac{\pi}{4}) + i \sin(4 \cdot \frac{\pi}{4})) = 4(\cos \pi + i \sin \pi) \] This simplifies to -4 (as \cos \pi = -1 and \sin \pi = 0). De Moivre's Theorem turns complex multiplication into manageable calculations.
For example, for (1+i)^4, you first express 1+i in polar form: \(\sqrt{2}(\cos \frac{\pi}{4} + i \sin \frac{\pi}{4})\). Applying De Moivre's Theorem:\[ (\sqrt{2})^4 (\cos(4 \cdot \frac{\pi}{4}) + i \sin(4 \cdot \frac{\pi}{4})) = 4(\cos \pi + i \sin \pi) \] This simplifies to -4 (as \cos \pi = -1 and \sin \pi = 0). De Moivre's Theorem turns complex multiplication into manageable calculations.
Complex Numbers
Complex numbers extend the concept of the usual real numbers by introducing an imaginary unit denoted as
i, where
i^2 = -1. A complex number is typically represented in the form
a + bi, where
a is the real part and
b is the imaginary part.
They are represented in a plane called the complex plane.
They are represented in a plane called the complex plane.
- The horizontal axis represents the real part, and the vertical axis represents the imaginary part.
- A point in this plane corresponds to a complex number.