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In Problems 1-26, write the given number in the form \(a+i b\). $$ i^{8} $$

Short Answer

Expert verified
\(i^8 = 1\), so in the form \(a + ib\), it is \(1 + 0i\).

Step by step solution

01

Understand the Powers of i

The imaginary unit, denoted as \(i\), is defined as the square root of -1. It has a cyclical pattern when raised to successive powers. Specifically, \(i\) has the following properties:\[\i^1 = i \i^2 = -1 \i^3 = -i \i^4 = 1 \]This pattern repeats every four powers. Thus, we can use this cyclical nature to solve the problem.
02

Determine the Cycle Position

To find \(i^8\), observe that the powers of \(i\) repeat every 4 terms. Therefore, the exponent 8 can be divided by 4: \[8 \div 4 = 2\] The remainder is 0, indicating that \(i^8\) aligns with \(i^4\) in the cycle.
03

Solve for i^8

From the properties of \(i\), as established in Step 1, we know that \(i^4 = 1\). Therefore, based on the cyclical pattern, \(i^8 = (i^4)^2 = 1^2 = 1\).
04

Write the Result in a + ib Form

We are tasked with expressing the result in the form \(a + ib\), where \(a\) and \(b\) are real numbers. Since \(i^8 = 1\), it can be written as \(1 + 0i\), which fits this format.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Imaginary Unit
In mathematics, especially when dealing with complex numbers, the imaginary unit is a crucial component. Represented by the symbol \(i\), the imaginary unit is defined such that \(i^2 = -1\). It helps extend the real number system to include solutions to equations that do not have real number solutions. For example, an equation like \(x^2 + 1 = 0\) has no real solutions because no real number squared will equal -1.
However, if we allow for the imaginary unit, then \(x = i\) or \(x = -i\) are solutions, as \(i^2\) equals \(-1\).
Understanding the imaginary unit opens up a whole new world in mathematics called complex numbers, where numbers take the form \(a + ib\). Here, \(a\) and \(b\) are real numbers, and \(ib\) is the imaginary part.
Powers of i
The powers of the imaginary unit \(i\) reveal a beautiful, repeating pattern that can simplify calculations significantly.
When \(i\) is raised to different powers, we can observe:
  • \(i^1 = i\)
  • \(i^2 = -1\)
  • \(i^3 = -i\)
  • \(i^4 = 1\)
  • \(i^5 = i\), repeating the cycle
This cyclical pattern continues indefinitely, repeating every four powers. Therefore, recognizing this pattern allows us to simplify expressions involving powers of \(i\). For instance, knowing that \(i^8\) aligns with \(i^4\) can make the process of finding a solution much quicker and easier.
Cyclical Pattern of i
The cyclical pattern in the powers of \(i\) is notable because it simplifies complex calculations and shows how powerful patterns can be in mathematics.
The cycle through four different results: \(i\), \(-1\), \(-i\), and \(1\), before repeating, means that any power of \(i\) can be reduced by simply taking the exponent modulo 4.
For example, if you have a large exponent like 1000, you only need to compute \(1000 \mod 4\), which equals 0, showing that \(i^{1000} = 1\) since it corresponds to \(i^4 = 1\) in the cycle.
  • When you divide the exponent by 4 and the remainder is 1, \(i^n = i\).
  • When the remainder is 2, \(i^n = -1\).
  • When the remainder is 3, \(i^n = -i\).
  • When the remainder is 0, \(i^n = 1\).
Understanding this cyclical nature is key to effectively managing tasks involving complex numbers.

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