Chapter 17: Problem 27
Express \(\ln z\) in the form \(a+i b\). \(z=\sqrt{2}+\sqrt{6} i\)
Short Answer
Expert verified
\(\ln z = \frac{3}{2} \ln 2 + i \frac{\pi}{3}\).
Step by step solution
01
Identify the structure of complex number z
The complex number is given as \( z = \sqrt{2} + \sqrt{6} i \). Recognize it in the form \( z = x + yi \), where \( x = \sqrt{2} \) and \( y = \sqrt{6} \).
02
Calculate the modulus of z
The modulus \( |z| \) of a complex number \( z = x + yi \) is given by \( |z| = \sqrt{x^2 + y^2} \). Substitute \( x = \sqrt{2} \) and \( y = \sqrt{6} \), resulting in \( |z| = \sqrt{(\sqrt{2})^2 + (\sqrt{6})^2} = \sqrt{2 + 6} = \sqrt{8} = 2\sqrt{2} \).
03
Determine the argument of z
The argument \( \theta \) of a complex number \( z = x + yi \) can be calculated using \( \tan \theta = \frac{y}{x} \). For \( z = \sqrt{2} + \sqrt{6} i \), \( \tan \theta = \frac{\sqrt{6}}{\sqrt{2}} = \sqrt{3} \). Thus, \( \theta = \arctan(\sqrt{3}) = \frac{\pi}{3} \).
04
Express ln z in terms of its modulus and argument
Using the polar form, the logarithm of a complex number is \( \ln z = \ln |z| + i \theta \). Here, \( \ln |z| = \ln(2 \sqrt{2}) \) and \( \theta = \frac{\pi}{3} \). Therefore, \( \ln z = \ln(2 \sqrt{2}) + i \frac{\pi}{3} \).
05
Simplify ln(z)
Since \( \ln(2 \sqrt{2}) = \ln 2 + \ln \sqrt{2} = \ln 2 + \frac{1}{2} \ln 2 = \frac{3}{2} \ln 2 \), the expression simplifies to \( \ln z = \frac{3}{2} \ln 2 + i \frac{\pi}{3} \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Modulus of a Complex Number
The modulus of a complex number provides the distance of the complex point from the origin in the complex plane. Imagine a point corresponding to the complex number on a grid. The modulus is simply the straight-line distance from this point back to the origin at (0,0). In mathematical terms, the modulus of a complex number \( z = x + yi \) is calculated using the formula \( |z| = \sqrt{x^2 + y^2} \).
In the example, we have \( z = \sqrt{2} + \sqrt{6}i \). By substituting \( x = \sqrt{2} \) and \( y = \sqrt{6} \) into the modulus formula, we get \( |z| = \sqrt{(\sqrt{2})^2 + (\sqrt{6})^2} = \sqrt{2 + 6} = \sqrt{8} = 2\sqrt{2} \). This value tells us the magnitude or absolute size of our complex number.
In the example, we have \( z = \sqrt{2} + \sqrt{6}i \). By substituting \( x = \sqrt{2} \) and \( y = \sqrt{6} \) into the modulus formula, we get \( |z| = \sqrt{(\sqrt{2})^2 + (\sqrt{6})^2} = \sqrt{2 + 6} = \sqrt{8} = 2\sqrt{2} \). This value tells us the magnitude or absolute size of our complex number.
Argument of a Complex Number
The argument of a complex number represents the direction or angle of the complex number from the positive x-axis. This is like an angle you would find in a triangle, determining its orientation. In general, you calculate the argument \( \theta \) by using the tangent relationship \( \tan \theta = \frac{y}{x} \), where \( x \) and \( y \) are the real and imaginary parts of the complex number, respectively.
For the complex number \( z = \sqrt{2} + \sqrt{6} i \), this becomes \( \tan \theta = \frac{\sqrt{6}}{\sqrt{2}} \), which equals \( \sqrt{3} \). Solving for \( \theta \), we obtain \( \theta = \arctan(\sqrt{3}) = \frac{\pi}{3} \). This angle provides the direction of our complex number in the polar coordinate system, exactly like a compass or a clock telling us which way the number points.
For the complex number \( z = \sqrt{2} + \sqrt{6} i \), this becomes \( \tan \theta = \frac{\sqrt{6}}{\sqrt{2}} \), which equals \( \sqrt{3} \). Solving for \( \theta \), we obtain \( \theta = \arctan(\sqrt{3}) = \frac{\pi}{3} \). This angle provides the direction of our complex number in the polar coordinate system, exactly like a compass or a clock telling us which way the number points.
Polar Form of Complex Numbers
The polar form of complex numbers is a way to express these numbers using their modulus and argument. Instead of the standard form \( z = x + yi \), the polar form is written as \( z = r(\cos \theta + i \sin \theta) \), where \( r \) is the modulus and \( \theta \) is the argument. With Euler's formula, you can simplify this to \( z = re^{i\theta} \).
Think of it as a different method of writing a complex number, focusing more on its size and direction rather than its individual components.
For \( z = \sqrt{2} + \sqrt{6} i \), we've found \( r = 2\sqrt{2} \) and \( \theta = \frac{\pi}{3} \), so the polar form becomes \( 2\sqrt{2} e^{i \frac{\pi}{3}} \). This format is especially helpful for operations like multiplication and finding powers or roots of complex numbers.
Think of it as a different method of writing a complex number, focusing more on its size and direction rather than its individual components.
For \( z = \sqrt{2} + \sqrt{6} i \), we've found \( r = 2\sqrt{2} \) and \( \theta = \frac{\pi}{3} \), so the polar form becomes \( 2\sqrt{2} e^{i \frac{\pi}{3}} \). This format is especially helpful for operations like multiplication and finding powers or roots of complex numbers.
Natural Logarithm of Complex Numbers
The natural logarithm of complex numbers: if it sounds complex, it's because it involves both the magnitude and the angle of the complex number. Once you understand the modulus and argument, the natural logarithm \( \ln z \) can be calculated in terms of these two quantities: \( \ln z = \ln |z| + i\theta \).
This formula bridges complex numbers with exponential functions, expanding our understanding of logarithms beyond the real number line.
In our example, the complex number \( z = \sqrt{2} + \sqrt{6} i \) has a modulus \( |z| = 2\sqrt{2} \) and argument \( \theta = \frac{\pi}{3} \). Therefore, \( \ln z = \ln(2\sqrt{2}) + i \frac{\pi}{3} \). By simplifying \( \ln(2\sqrt{2}) \) into \( \frac{3}{2} \ln 2 \), the expression becomes \( \ln z = \frac{3}{2} \ln 2 + i \frac{\pi}{3} \). This result showcases how complex logarithms provide a unique expression merging both magnitude and direction of a complex number.
This formula bridges complex numbers with exponential functions, expanding our understanding of logarithms beyond the real number line.
In our example, the complex number \( z = \sqrt{2} + \sqrt{6} i \) has a modulus \( |z| = 2\sqrt{2} \) and argument \( \theta = \frac{\pi}{3} \). Therefore, \( \ln z = \ln(2\sqrt{2}) + i \frac{\pi}{3} \). By simplifying \( \ln(2\sqrt{2}) \) into \( \frac{3}{2} \ln 2 \), the expression becomes \( \ln z = \frac{3}{2} \ln 2 + i \frac{\pi}{3} \). This result showcases how complex logarithms provide a unique expression merging both magnitude and direction of a complex number.