Chapter 17: Problem 2
In Problems 1 and 2 , the given function is analytic for all \(z\). Show that the Cauchy-Riemann equations are satisfied at every point. $$ f(z)=3 z^{2}+5 z-6 i $$
Short Answer
Expert verified
The Cauchy-Riemann equations are satisfied, so the function is analytic everywhere.
Step by step solution
01
Express the function in terms of real and imaginary components
Given the function \( f(z) = 3z^2 + 5z - 6i \), we start by expressing \( z \) as \( z = x + yi \), where \( x \) and \( y \) are real numbers.Substitute \( z \) in the function: \( f(z) = 3(x + yi)^2 + 5(x + yi) - 6i \).
02
Expand the squared term
Expand \( (x + yi)^2 \) using the formula: \[ (x+yi)^2 = x^2 + 2xyi - y^2. \] Now, substitute this back into the function:\[ f(z) = 3(x^2 - y^2) + 3(2xy)i + 5x + 5yi - 6i. \]
03
Combine real and imaginary parts
Combine the real and imaginary parts in the expression:Real part: \( 3x^2 - 3y^2 + 5x \).Imaginary part: \( (6xy + 5y - 6)i \). Thus, \( f(z) = (3x^2 - 3y^2 + 5x) + (6xy + 5y - 6)i \).
04
Find partial derivatives for the Cauchy-Riemann equations
Define \( u(x, y) = 3x^2 - 3y^2 + 5x \) and \( v(x, y) = 6xy + 5y - 6 \).Compute partial derivatives:- \( \frac{\partial u}{\partial x} = 6x + 5 \)- \( \frac{\partial u}{\partial y} = -6y \)- \( \frac{\partial v}{\partial x} = 6y \)- \( \frac{\partial v}{\partial y} = 6x + 5 \).
05
Verify the Cauchy-Riemann equations
The Cauchy-Riemann equations are:- \( \frac{\partial u}{\partial x} = \frac{\partial v}{\partial y} \)- \( \frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x} \).Verify:- \( \frac{\partial u}{\partial x} = 6x + 5 = \frac{\partial v}{\partial y} \)- \( \frac{\partial u}{\partial y} = -6y = -6y = -\frac{\partial v}{\partial x} \).Both equations satisfy Cauchy-Riemann conditions, so the function is analytic everywhere.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cauchy-Riemann Equations
The Cauchy-Riemann equations are essential in complex analysis because they provide a condition for a function to be analytic, meaning it is differentiable at every point in a domain. These equations involve partial derivatives of the real and imaginary components of a complex function. For a function \( f(z) = u(x, y) + iv(x, y) \), where \( z = x + yi \), the Cauchy-Riemann equations state that:
- \( \frac{\partial u}{\partial x} = \frac{\partial v}{\partial y} \)
- \( \frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x} \)
Analytic Functions
In complex analysis, an analytic function is one that is separable in terms of its differential calculus properties. Simply put, a function is analytic at a point if it can be expressed as a power series around that point. The term is often interchangeable with "holomorphic". An important implication of a function being analytic is that it is both differentiable and smooth within its radius of convergence.
Analytic functions have several fascinating properties:
Analytic functions have several fascinating properties:
- They can be represented by a convergent power series.
- They are infinitely differentiable.
- They conform to the rigidity principle which states that if two analytic functions agree on a set with an accumulation point, they agree everywhere on their domain.
Complex Differentiation
Complex differentiation deals with finding the derivative of a function that has complex variables. Unlike real differentiation, complex differentiation is more restrictive due to the demands of the Cauchy-Riemann equations. This restriction results in functions having derivatives that can be much richer in character.
To differentiate a complex function \( f(z) = u(x, y) + iv(x, y) \), follow these steps:
To differentiate a complex function \( f(z) = u(x, y) + iv(x, y) \), follow these steps:
- Express \( z \) in terms of its real and imaginary parts ( \( z = x + yi \)).
- Write \( f(z) \) as a combination of its real part \( u(x, y) \) and imaginary part \( v(x, y) \).
- Ensure that the function meets the Cauchy-Riemann conditions.