Chapter 17: Problem 18
Find all values of \(z\) satisfying the given equation. \(\sinh z=-1\)
Short Answer
Expert verified
The solution is \( z = \ln(-1 + \sqrt{2}) + ni\pi \), where \( n \) is an integer.
Step by step solution
01
Understand the Hyperbolic Sine Function
The hyperbolic sine function, denoted as \( \sinh z \), is defined as \( \sinh z = \frac{e^z - e^{-z}}{2} \). It is similar to the sine function in trigonometry but is based on the exponential function.
02
Set Up the Equation
We start with the given equation: \( \sinh z = -1 \). Substitute the definition of \( \sinh z \) into this equation to get:\[ \frac{e^z - e^{-z}}{2} = -1 \]
03
Solve for the Exponential Terms
Multiply both sides by 2 to eliminate the fraction, resulting in:\[ e^z - e^{-z} = -2 \] Change \( e^{-z} \) to \( \frac{1}{e^z} \):\[ e^z - \frac{1}{e^z} = -2 \].
04
Substitute \( e^z = x \)
Let \( x = e^z \). Then the equation becomes:\[ x - \frac{1}{x} = -2 \] Multiply through by \( x \) to clear the fraction:\[ x^2 - 1 = -2x \].
05
Rearrange to Form a Quadratic Equation
Bring all terms to one side of the equation to form a quadratic equation:\[ x^2 + 2x - 1 = 0 \].
06
Solve the Quadratic Equation
Apply the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 1, b = 2, \text{ and } c = -1 \):\[ x = \frac{-2 \pm \sqrt{2^2 - 4 \cdot 1 \cdot (-1)}}{2 \cdot 1} = \frac{-2 \pm \sqrt{8}}{2} = \frac{-2 \pm 2\sqrt{2}}{2} \]. This gives solutions: \[ x = -1 + \sqrt{2} \] and \[ x = -1 - \sqrt{2} \].
07
Solve for \( z \)
Recall \( x = e^z \). Since \( x = -1 - \sqrt{2} \) is negative and can't be the exponential function result for any real \( z \), discard it. Solve \( e^z = -1 + \sqrt{2} \):\[ z = \ln(-1 + \sqrt{2}) + ni\pi \] (The solution family due to periodicity, \( n \) is an integer for periodicity, accounting for all complex solutions.)
08
Verify the Principal Solution
Verify by substitution if \( z = \ln(-1 + \sqrt{2}) + ni\pi \) satisfies the original equation. Indeed, substituting \( z = \ln(-1 + \sqrt{2}) \) back gives \( \sinh(z) = -1 \). This also aligns with properties of hyperbolic functions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hyperbolic Sine Function
The hyperbolic sine function, represented as \( \sinh z \), is a function that mirrors the behavior of the traditional sine function, but it is framed in terms of exponential functions rather than trigonometric ones. This function is defined by the equation:
- \( \sinh z = \frac{e^z - e^{-z}}{2} \)
Exponential Functions
Exponential functions form the backbone of the hyperbolic sine function and are vital in various mathematical problems. An exponential function is typically of the form \( e^x \), where \( e \) is the base of natural logarithms, approximately equal to 2.718. Exponential functions are known for modeling growth and decay because they increase rapidly.
- They have the form \( e^z \), where \( z \) is any complex or real number.
- In the context of complex numbers, they're used to describe rotations and oscillations.
Quadratic Equations
A quadratic equation is a polynomial equation of degree two and takes the form:
- \( ax^2 + bx + c = 0 \)
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
Complex Numbers
Complex numbers form a critical element when solving equations that involve periodicity and trigonometric or hyperbolic functions. A complex number is of the form \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit with the property \( i^2 = -1 \).
- In many scenarios, like our equation \( \sinh z = -1 \), solutions naturally extend into the complex plane.
- The formula \( z = \ln(x) + ni\pi \), where \( n \) is an integer, showcases how periodicity in complex numbers is addressed.