Chapter 17: Problem 15
In Problems 15 and 16, find \(z_{1} z_{2}\) and \(z_{1} / z_{2} .\) Write the number in the form \(a+i b\). $$ z_{1}=2\left(\cos \frac{\pi}{8}+i \sin \frac{\pi}{8}\right), z_{2}=4\left(\cos \frac{3 \pi}{8}+i \sin \frac{3 \pi}{8}\right) $$
Short Answer
Expert verified
\(z_1 z_2 = 8i; \frac{z_1}{z_2} = \frac{\sqrt{2}}{4} - i\frac{\sqrt{2}}{4}\)
Step by step solution
01
Express Both Complex Numbers in Exponential Form
First, convert both given complex numbers from their trigonometric form to exponential form using Euler's formula:\[ z = r(\cos \theta + i \sin \theta ) = re^{i\theta} \] Therefore, we have: \[ z_1 = 2e^{i(\pi/8)} \] and \[ z_2 = 4e^{i(3\pi/8)} \].
02
Multiply the Complex Numbers
To find \(z_1 z_2\), multiply the magnitudes and add the angles:\[ z_1 z_2 = (2)(4) e^{i(\pi/8 + 3\pi/8)} = 8e^{i(\pi/2)} \] Convert back to trigonometric form: \[ 8e^{i(\pi/2)} = 8(\cos \pi/2 + i \sin \pi/2) = 8(0 + i\cdot 1) = 8i \].
03
Divide the Complex Numbers
To find \(\frac{z_1}{z_2}\), divide the magnitudes and subtract the angles:\[ \frac{z_1}{z_2} = \frac{2}{4} e^{i(\pi/8 - 3\pi/8)} = \frac{1}{2}e^{-i(\pi/4)} \] Convert back to trigonometric form:\[ \frac{1}{2}e^{-i(\pi/4)} = \frac{1}{2}(\cos(-\pi/4) + i \sin(-\pi/4)) = \frac{1}{2}\left(\frac{\sqrt{2}}{2} - i\frac{\sqrt{2}}{2}\right) \]Simplify:\[ \frac{z_1}{z_2} = \frac{\sqrt{2}}{4} - i\frac{\sqrt{2}}{4} \].
04
Write the Results in Standard Form
Now express both results in the standard form \(a + ib\):For \(z_1 z_2\):\[ 8i = 0 + 8i \].For \(\frac{z_1}{z_2}\):\[ \frac{\sqrt{2}}{4} - i\frac{\sqrt{2}}{4} \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Euler's Formula
Euler's Formula is a crucial bridge between trigonometry and complex analysis. It offers a beautiful way to represent complex numbers, making them easier to work with. The formula is expressed as: \[ e^{i\theta} = \cos(\theta) + i\sin(\theta) \] This formula shows that a complex number can be written with an exponential involving an imaginary unit, where \(e\) is the base of the natural logarithm, \(i\) is the imaginary unit \(\sqrt{-1}\), and \(\theta\) is the angle in radians. By utilizing Euler’s formula, calculations, especially multiplication and division, of complex numbers become more straightforward. For example, the complex numbers \(z_1 = 2(\cos \frac{\pi}{8} + i \sin \frac{\pi}{8})\) can be easily converted to the exponential form \(z_1 = 2e^{i(\pi/8)}\). Similarly, \(z_2 = 4e^{i(3\pi/8)}\). This converts the tiring multiplication and division of trigonometric components into simpler operations with exponential forms.
Trigonometric Form
The trigonometric form of a complex number is built on the foundation of geometry, linking complex numbers with angles and radii. The form is expressed as: \[ z = r(\cos \theta + i\sin \theta) \] Here, \(r\) denotes the radius or magnitude of the complex number and \(\theta\) is the angle formed with the positive x-axis in a polar coordinate system. This representation is helpful when visualizing complex numbers on a plane and when dealing with complex number operations.
- Magnitude \(r\) is calculated as \(\sqrt{a^2 + b^2}\).
- Angle \(\theta\) can be found using \(\tan^{-1}(b/a)\).
Complex Multiplication
Multiplication of complex numbers in their trigonometric or exponential form can significantly simplify computations. When two complex numbers are multiplied:
- Multiply their magnitudes.
- Add their angles.
- \(z_1 = 2e^{i(\pi/8)}\) and \(z_2 = 4e^{i(3\pi/8)}\).
- Their product in exponential form is \(8e^{i(\pi/2)}\).
- This is equivalent to \( z_1 z_2 = 8i \), a very simple form to interpret.
Complex Division
Dividing complex numbers uses a similar approach to multiplication, but involves dividing magnitudes and subtracting angles. For two complex numbers \(z_1\) and \(z_2\):
- Divide their magnitudes.
- Subtract their angles.
- \(\frac{z_1}{z_2} = \frac{1}{2}e^{-i(\pi/4)}\), which translates to a simple trigonometric form.
- Breaking this down gives \( \frac{\sqrt{2}}{4} - i\frac{\sqrt{2}}{4} \).