Chapter 13: Problem 9
When a vibrating string is subjected to an external vertical force that varies
with the horizontal distance from the left end, the wave equation takes on the
form
$$
a^{2} \frac{\partial^{2} u}{\partial x^{2}}+A x=\frac{\partial^{2} u}{\partial
t^{2}}
$$
where \(A\) is constant. Solve this partial differential equation subject to
$$
\begin{aligned}
&u(0, t)=0, \quad u(1, t)=0, t>0 \\
&u(x, 0)=0,\left.\frac{\partial u}{\partial t}\right|_{t=0}=0,0
Short Answer
Step by step solution
Understanding the Problem
Homogeneous Solution
Applying Separation of Variables
Solving Spatial Component
Solving Temporal Component
General Solution of Homogeneous Equation
Particular Solution for Non-homogeneous Equation
Construct Full Solution
Determine Coefficients Using Initial Conditions
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partial Differential Equations
In our specific problem, the wave equation \( a^{2} \frac{\partial^{2} u}{\partial x^{2}} + A x = \frac{\partial^{2} u}{\partial t^{2}} \) describes a vibrating string influenced by an external force. The term \( A x \) adds complexity, making it non-homogeneous, which means it doesn't equal zero when all terms and derivatives are added together. Solving this equation involves understanding both the homogeneous part (ignoring \( A x \)) and the non-homogeneous part (considering \( A x \)).
Boundary Conditions
These conditions mean that at \( x = 0 \) and \( x = 1 \), the displacement \( u \) is always zero, ensuring no movement at these points. Similarly, the initial conditions given are \( u(x, 0) = 0 \) and \( \frac{\partial u}{\partial t}\big|_{t=0} = 0 \). These stand for the initial displacement and velocity of the string being zero across \( x \).
Solving the wave equation involves applying these conditions to both the homogeneous and particular solutions, ensuring solutions adhere to physical constraints of the problem, like fixed-string ends and initial stillness.
Separation of Variables
This assumption allows the separation of the wave equation into two ordinary differential equations (ODEs). One depends on \( x \) and the other on \( t \). Usually, separation leads to simpler equations easier to solve individually.
- Spatial Component: \( a^2 X''(x) = -\lambda X(x) \)
- Temporal Component: \( T''(t) = -(an\pi)^2 T(t) \)
For the spatial part, solutions like \( X_n(x) = \sin(n\pi x) \) coincide with fixed boundary values. Temporal solutions engage oscillatory forms, \( T_n(t) = A_n \cos(an\pi t) + B_n \sin(an\pi t) \), expressing time-dependent vibrations.
Non-homogeneous Equations
In this wave equation, non-homogeneity comes from the term \( A x \), representing an external force. Rather than zero, this term demands direct integration to find a specific solution that satisfies this added condition.
To solve, first tackle the homogeneous equation. Afterward, find a particular solution \( u_p(x) \) satisfying the entire non-homogeneous form by direct integration - a method that involves simply integrating twice with respect to \( x \), given the form \( a^{2} \frac{d^{2} u_p}{dx^{2}} + A x = 0 \). The particular solution is then combined with the homogeneous solution to form the complete answer that fulfills both equation and boundary conditions.
- Integrate to find \( u_p(x) = -\frac{A}{2a^2} x^2 + C_1 x + C_2 \)
- Use boundary conditions to find constants \( C_1 \) and \( C_2 \)