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$$ \begin{aligned} &\frac{\partial^{2} u}{\partial x^{2}}+\sin x \cos t=\frac{\partial^{2} u}{\partial t^{2}}, 00 \\ &u(0, t)=0, u(\pi, t)=0, t>0 \\ &u(x, 0)=0,\left.\frac{\partial u}{\partial t}\right|_{t=0}=0,0

Short Answer

Expert verified
Solve using separation of variables with Fourier series to meet boundary and initial conditions.

Step by step solution

01

Recognize the Problem Type

The given problem is a boundary value problem involving a partial differential equation (PDE) with specified boundary and initial conditions. We have a wave equation with a perturbation term \( \sin x \cos t \) added to the left-hand side.
02

Identify Appropriate Solution Method

For this type of wave equation with non-homogeneous terms, the method of separation of variables coupled with a Fourier series expansion is often suitable. Our goal is to turn this PDE into ordinary differential equations (ODEs) by assuming a solution of the form \( u(x, t) = X(x)T(t) \) and leveraging the boundary conditions.
03

Apply Boundary Conditions to Simplify

Given \( u(0,t) = 0 \) and \( u(\pi,t) = 0 \), we look for solutions of the form \( X(x) = \sin(nx) \) where \( n \) is a positive integer. This satisfies the spatial boundary conditions and naturally leads to a Fourier sine series expansion.
04

Assume a Separated Solution Form

Assume \( u(x, t) = \sum_{n=1}^{} a_n(t) \sin(nx) \) to meet the boundary conditions and transform the PDE into a standard form for Fourier series. Substitute this form into the PDE to equate coefficients and isolate the temporal component.
05

Obtain ODEs for Temporal Part

Substitute \( u(x, t) = \sum_{n=1}^{} a_n(t) \sin(nx) \) into the PDE and compare terms. This gives rise to a differential equation for \( a_n(t) \) of the form \( \frac{d^2a_n(t)}{dt^2} + n^2a_n(t) = b_n \cos t \), where \( b_n \) comes from the Fourier decomposition of \( \sin x \).
06

Solve the Homogeneous ODE for Temporal Part

The homogeneous solution to \( \frac{d^2a_n(t)}{dt^2} + n^2a_n(t) = 0 \) is \( a_{n,h}(t) = c_1 \cos(nt) + c_2 \sin(nt) \). Use the initial conditions \( u(x, 0)=0 \) and \( \left.\frac{\partial u}{\partial t}\right|_{t=0}=0 \) to determine these constants.
07

Solve the Non-Homogeneous ODE

For the particular solution, we assume a form consistent with the driving function \( \cos t \), solve \( \frac{d^2a_n^p(t)}{dt^2} + n^2a_n^p(t) = b_n \cos t \), and apply the method of undetermined coefficients.
08

Construct General Solution

The general solution for \( a_n(t) = a_{n,h}(t) + a_{n,p}(t) \) is obtained, after applying initial conditions and determining \( c_1 \), \( c_2 \), and the form of the particular solution. \( u(x, t) = \sum_{n=1}^{\infty}( c_1 \cos(nt) + c_2 \sin(nt) + a_{n,p}(t))\sin(nx) \) becomes the solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boundary Value Problem
In mathematics, a Boundary Value Problem (BVP) is a differential equation along with a set of additional constraints, called boundary conditions. Boundary conditions specify the behavior of the solution at the borders of the domain they are applied to.
A familiar example is the string fixed at both ends upon which a wave travels. Here, the boundary conditions dictate that the displacement at the endpoints remains zero.
This is precisely what our exercise asks us to solve within a particular range, typically represented as the boundaries where the solution \( u(x, t) \) must satisfy \( u(0, t) = 0 \) and \( u(\pi, t) = 0 \).
Such problems are common in physics and engineering, particularly in scenarios where determining values at boundaries is crucial for system stability or operation.
Fourier Series Expansion
The Fourier Series Expansion is a method of expressing a function as a sum of sinusoidal functions. This expansion is particularly useful for solving differential equations.
In boundary value problems, especially where trigonometric functions are naturally involved, Fourier series provides a powerful tool that transforms problems into easier-to-handle forms.
  • A Fourier sine series is often used when the solution is required to be zero at the boundaries, like \( X(x) = \sin(nx) \).
  • The function \( f(x) \) that we're interested in can be represented as \( f(x) = \, \sum_{n=1}^{} a_n \sin(nx) \).
These approaches are favored in handling partial differential equations as they simplify the complex relationship between variables into manageable sums of sines and cosines.
Separation of Variables
Separation of Variables is a commonly used method to solve a PDE (Partial Differential Equation) by breaking it into simpler, solvable ODEs (Ordinary Differential Equations).
This technique assumes that a multiparameter function can be written as a product of single-variable functions, e.g., \( u(x, t) = X(x)T(t) \). This approach allows the decomposition of a complex problem by isolating dependencies on different variables.
  • By substituting \( u(x, t) = X(x)T(t) \) into the PDE, each part can be separated and set equal to a constant, simplifying our task.
  • Both parts then develop into individual ordinary differential equations to solve separately, such as dealing with temporal and spatial components independently.
Eventually, separation of variables turns the original problem into more manageable pieces.
Wave Equation
The Wave Equation is a second-order linear partial differential equation (PDE) that describes wave propagation, such as sound or light waves. In its simplest form, it is written as \( \frac{\partial^2 u}{\partial t^2} = c^2 \frac{\partial^2 u}{\partial x^2} \), where \( c \) represents the wave speed.
The exercise involves a wave equation that is modified by an added term: \( \sin x \cos t \). This term converts the homogeneous PDE into a more challenging non-homogeneous version, inviting more complex solutions.
  • Our given wave problem lies within a fixed temporal and spatial domain, with boundary-specific constraints.
  • Solutions here typically visualize oscillations or propagations that fit within given boundary conditions, and the added complexity necessitates use of techniques like Fourier series to find accurate solutions.
Wave equations like these are pivotal in the study of vibrations and waves in physical systems.
Homogeneous and Non-Homogeneous Solutions
When solving PDEs, distinguishing between homogeneous and non-homogeneous solutions becomes crucial. A Homogeneous Solution satisfies the PDE without any external influences or added terms.
Non-Homogeneous Solutions, in contrast, account for these added terms, such as \( \sin x \cos t \) in our problem.
  • The homogeneous equation \( \frac{d^2a_n(t)}{dt^2} + n^2a_n(t) = 0 \) is solved to get the natural response of the system, i.e., without the non-homogeneous term affecting it.
  • The particular solution deals with the external force or disturbance, guided by methods such as undetermined coefficients or variations of parameters.
Thus, the general solution can be obtained by combining both solutions. This comprehensive answer uses both parts to satisfy the entire set of given conditions.

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Most popular questions from this chapter

Consider the boundary-value problem $$ \begin{aligned} &k \frac{\partial^{2} u}{\partial x^{2}}=\frac{\partial u}{\partial t}, 00 \\ &u(0, t)=u_{0}, u(L, t)=u_{1} \\ &u(x, 0)=f(x) \end{aligned} $$ that is a model for the temperature \(u\) in a rod of length \(L\). If \(u_{0}\) and \(u_{1}\) are different nonzero constants, what would you intuitively expect the temperature to be at the center of the rod after a very long period of time? Prove your assertion.

Discuss whether product solutions \(u=X(x) Y(y)\) can be found for the given partial differential equation. [Hint: Use the superposition principle.]\(\frac{\partial^{2} u}{\partial x \partial y}+\frac{\partial u}{\partial x}=0\)

In Problems 17-26, classify the given partial differential equation as hyperbolic, parabolic, or elliptic. $$ a^{2} \frac{\partial^{2} u}{\partial x^{2}}=\frac{\partial^{2} u}{\partial t^{2}} $$

The vertical displacement \(u(x, t)\) of an infinitely long string is determined from the initial-value problem $$ \begin{aligned} &a^{2} \frac{\partial^{2} u}{\partial x^{2}}=\frac{\partial^{2} u}{\partial t^{2}}, \quad-\infty0 \\ &u(x, 0)=f(x),\left.\quad \frac{\partial u}{\partial t}\right|_{t=0}=g(x) \end{aligned} $$ This problem can be solved without separating variables. (a) Show that the wave equation can be put into the form \(\partial^{2} u / \partial \eta \partial \xi=0\) by means of the substitutions \(\xi=x+a t\) and \(\eta=x-a t .\) (b) Integrate the partial differential equation in part (a), first with respect to \(\eta\) and then with respect to \(\xi\), to show that \(u(x, t)=F(x+a t)+G(x-a t)\), where \(F\) and \(G\) are arbitrary twice differentiable functions, is a solution of the wave equation. Use this solution and the given initial conditions to show that $$ \begin{aligned} &F(x)=\frac{1}{2} f(x)+\frac{1}{2 a} \int_{x_{0}}^{x} g(s) d s+c \\ &\text { and } \quad G(x)=\frac{1}{2} f(x)-\frac{1}{2 a} \int_{x_{0}}^{x} g(s) d s-c, \end{aligned} $$ where \(x_{0}\) is arbitrary and \(c\) is a constant of integration. (c) Use the results in part (b) to show that \(u(x, t)=\frac{1}{2}[f(x+a t)+f(x-a t)]+\frac{1}{2 a} \int_{x-a t}^{x+a t} g(s) d s .\) (14) Note that when the initial velocity \(g(x)=0\) we obtain $$ u(x, t)=\frac{1}{2}[f(x+a t)+f(x-a t)],-\infty

Classify the given partial differential equation as hyperbolic, parabolic, or elliptic.\(a^{2} \frac{\partial^{2} u}{\partial x^{2}}=\frac{\partial^{2} u}{\partial t^{2}}\)

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