Problem 37 When a nonlinear capacitor is pr... [FREE SOLUTION]

Chapter 11: Problem 37

When a nonlinear capacitor is present in an $L R C$-series circuit, the voltage drop is no longer given by $q / C$ but is more accurately described by $\alpha q+\beta q^{3}$, where $\alpha$ and $\beta$ are constants and $\alpha>0$. Differential equation (34) of Section $3.8$ for the free circuit is then replaced by $$ L \frac{d^{2} q}{d t^{2}}+R \frac{d q}{d t}+\alpha q+\beta q^{3}=0 $$ Find and classify all critical points of this nonlinear differential equation. [Hint: Divide into the two cases $\beta>0$ and $\beta<0$.]

Short Answer

Expert verified

Critical points: $ x_1 = 0 $ for $ \beta > 0 $ and $ x_1 = 0, \pm\sqrt{- \frac{\alpha}{\beta}} $ for $ \beta < 0 $.

Step by step solution

Set Up System of Equations

Convert the second-order differential equation into a system of first-order differential equations. Letting $ x_1 = q $ and $ x_2 = \frac{dq}{dt} $, the original equation becomes two equations: $ \frac{dx_1}{dt} = x_2 $ and $ \frac{dx_2}{dt} = -\frac{R}{L}x_2 - \frac{\alpha}{L}x_1 - \frac{\beta}{L}x_1^3 $.

Find Critical Points

Critical points occur when both equations' derivatives are zero. Set $ \frac{dx_1}{dt} = 0 $, which gives $ x_2 = 0 $. Set $ \frac{dx_2}{dt} = 0 $, leading to $ -\frac{R}{L}x_2 - \frac{\alpha}{L}x_1 - \frac{\beta}{L}x_1^3 = 0 $. Substitute $ x_2 = 0 $ into this equation, leading to $ - \frac{\alpha}{L} x_1 - \frac{\beta}{L} x_1^3 = 0 $. Thus, the critical points are solutions of $ \alpha x_1 + \beta x_1^3 = 0 $.

Solve for Critical Points

Factor the equation $ \alpha x_1 + \beta x_1^3 = 0 $ to get $ x_1(\alpha + \beta x_1^2) = 0 $. This yields the solutions $ x_1 = 0 $ and $ \alpha + \beta x_1^2 = 0 $. Solve $ \alpha + \beta x_1^2 = 0 $ for $ x_1 $, resulting in $ x_1 = \pm \sqrt{- \frac{\alpha}{\beta}} $ for $ \beta < 0 $. Let $ x_1 = 0 $ when both $ \beta > 0 $ and $ \beta < 0 $.

Classify Critical Points for $ \beta > 0 $

When $ \beta > 0 $, the only real critical point is $ x_1 = 0 $. Linearizing the system around $ x_1 = 0 $ using Jacobian, we find the eigenvalues are based on $ \alpha $. Since $ \alpha > 0 $, this point is a center or a stable/unstable node depending on the damping $ R $.

Classify Critical Points for $ \beta < 0 $

When $ \beta < 0 $, the critical points are $ x_1 = 0 $ and $ x_1 = \pm\sqrt{- \frac{\alpha}{\beta}} $. For $ x_1 = 0 $, the behavior is the same dependent on damping $ R $. For the non-zero $ x_1 $ values, plug back into the Jacobian and analyze eigenvalues. These can be saddle points, nodes, or even foci based on $ \alpha $ and $ \beta $.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

LRC Circuit Analysis

LRC circuits, which stand for Inductor (L), Resistor (R), and Capacitor (C) circuits, are fundamental in analyzing electrical networks. When examining such circuits, especially those that feature a nonlinear element like a capacitor, the analysis becomes more intricate. The circuit鈥檚 behavior is frequently modeled using differential equations because the current and voltage depend on time. Understanding this form of analysis is crucial for predicting the oscillatory behavior of the circuit.

Resistors contribute resistance, dissipating energy in the form of heat.
Capacitors store and release electrical energy, emphasizing time-dependent voltage and current.
Inductors oppose changes in current, introducing a time delay in the circuit鈥檚 response.

The interaction between these components is expressed in a differential equation format, often leading to systems that require numerical or analytical techniques to solve.

Nonlinear Capacitors

When we introduce a nonlinear capacitor into an LRC circuit, the voltage-current relationship deviates from the linear regime. Traditionally, a linear capacitor shows a proportional relationship between charge and voltage, depicted by the equation $V = \frac{q}{C}$. However, with a nonlinear capacitor, this relationship becomes a polynomial of higher degrees. For instance, it becomes $V = \alpha q + \beta q^3$.

$\alpha$ represents the linear term and must always be positive.
$\beta$, the nonlinear term, can be positive or negative, influencing the overall behavior significantly.

This modification means that the circuit鈥檚 response can include phenomena such as harmonic generation or complex oscillatory patterns, demanding more elaborate methods of analysis.

Critical Point Classification

Critical points in differential equations mark the steady states where the system's derivatives are zero. For our specific nonlinear differential equation case, we determine critical points by analyzing when $ \frac{dq}{dt} = 0 $ and $ \frac{d^2q}{dt^2} = 0$. These correspond to zero net forces or moments in a physical system.

Setting derivatives to zero leads to algebraic solutions for equilibrium.
The nature of these points can vastly differ depending on the parameters, especially the sign of $\beta$.

Understanding and classifying these points allow us to predict the long-term behavior of the system, such as stability and types of oscillations.

Jacobian Matrix

The Jacobian Matrix is a tool for analyzing stability in systems of differential equations. By linearizing differential equations around critical points, this matrix helps ascertain the type of equilibrium a point represents. For the transformed first-order system of the given LRC circuit, the Jacobian is derived from the partial derivatives of the system's equations.

The eigenvalues of the Jacobian determine the nature of the critical points.
If eigenvalues have positive real parts, the solution grows unbounded, indicating instability.
Conversely, negative real parts suggest a return to equilibrium, highlighting stability.

By inserting the critical points into the Jacobian matrix, one gains significant insights into the circuit's dynamics.

Free Circuit Differential Equations

Free circuit differential equations describe a scenario in which there is no external driving force or source, focusing instead on the circuit's inherent properties. In the context of an LRC circuit with a nonlinear capacitor, the equation $L \frac{d^2 q}{dt^2} + R \frac{dq}{dt} + \alpha q + \beta q^3 = 0$ comes into play.

$L \frac{d^2 q}{dt^2}$ represents the inducement effect, a key in determining oscillations.
$R \frac{dq}{dt}$ accounts for resistance, causing the system to lose energy.
The terms with $\alpha$ and $\beta$ embody the capacitor's voltage relationship, introducing nonlinearity.

The analysis of such equations illuminates the circuit鈥檚 behavior without external influences, presenting pure natural resonances and attenuation dynamics.

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Short Answer

Step by step solution

Set Up System of Equations

Find Critical Points

Solve for Critical Points

Classify Critical Points for \( \beta > 0 \)

Classify Critical Points for \( \beta < 0 \)

Key Concepts

LRC Circuit Analysis

Nonlinear Capacitors

Critical Point Classification

Jacobian Matrix

Free Circuit Differential Equations

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