Chapter 10: Problem 28
In Problems 13-32, use vaniation of parameters to solve the given system. $$ \mathbf{X}^{\prime}=\left(\begin{array}{rr} 0 & 1 \\ -1 & 0 \end{array}\right) \mathbf{X}+\left(\begin{array}{c} 1 \\ \cot t \end{array}\right) $$
Short Answer
Expert verified
The general solution is \( \mathbf{X} = c_1 \begin{bmatrix} \cos t \\ \sin t \end{bmatrix} + c_2 \begin{bmatrix} -\sin t \\ \cos t \end{bmatrix} + \begin{bmatrix} t\cos t \\ t\sin t \end{bmatrix} \).
Step by step solution
01
Determine the Homogeneous Solution
To solve the system \( \mathbf{X}' = A\mathbf{X} + \mathbf{F}(t) \) using variation of parameters, we first find the homogeneous solution. Given the matrix \( A = \begin{pmatrix} 0 & 1 \ -1 & 0 \end{pmatrix} \), the characteristic equation is \( \lambda^2 + 1 = 0 \), implying eigenvalues \( \lambda = i, -i \). The corresponding eigenvectors lead us to the fundamental matrix solution \( \mathbf{X}_h = c_1 \begin{pmatrix} \cos t \ \sin t \end{pmatrix} + c_2 \begin{pmatrix} -\sin t \ \cos t \end{pmatrix} \).
02
Setup Variation of Parameters
Next, we use variation of parameters by proposing a particular solution of the form \( \mathbf{X}_p = \begin{bmatrix} \cos t & -\sin t \ \sin t & \cos t \end{bmatrix} \begin{bmatrix} u_1(t) \ u_2(t) \end{bmatrix} \). Here \( u_1(t) \) and \( u_2(t) \) are functions to be determined.
03
Compute Derivatives and Substitute
Differentiate \( \mathbf{X}_p \) to find \( \mathbf{X}_p' \) and substitute into the non-homogeneous system. By product rule, \( \mathbf{X}_p' = \mathbf{X}_h' \begin{bmatrix} u_1(t) \ u_2(t) \end{bmatrix} + \mathbf{X}_h \begin{bmatrix} u_1'(t) \ u_2'(t) \end{bmatrix} \). The homogeneous part cancels with \( A\mathbf{X}_p \), isolating the equation \( \mathbf{X}_h \begin{bmatrix} u_1'(t) \ u_2'(t) \end{bmatrix} = \mathbf{F}(t) \).
04
Solve for u'(t)
The equation \( \begin{bmatrix} \cos t & -\sin t \ \sin t & \cos t \end{bmatrix} \begin{bmatrix} u_1'(t) \ u_2'(t) \end{bmatrix} = \begin{pmatrix} 1 \ \cot t \end{pmatrix} \) can be solved using the inverse of the fundamental matrix, which is \( \begin{bmatrix} \cos t & \sin t \ -\sin t & \cos t \end{bmatrix} \). Apply the inverse to obtain \( \begin{bmatrix} u_1'(t) \ u_2'(t) \end{bmatrix} = \begin{bmatrix} 1 \ 0 \end{bmatrix} \), leading to \( u_1'(t) = 1 \) and \( u_2'(t) = 0 \).
05
Integrate to Find u(t)
Integrate to find \( u_1(t) \) and \( u_2(t) \). Integration yields \( u_1(t) = t + C_1 \) and \( u_2(t) = C_2 \), where \( C_1 \) and \( C_2 \) are constants. As we're seeking a particular solution, we can choose \( C_1 = 0 \) and \( C_2 = 0 \), so \( u_1(t) = t \) and \( u_2(t) = 0 \).
06
Construct the Particular Solution
Substitute \( u_1(t) \) and \( u_2(t) \) back to find the particular solution: \( \mathbf{X}_p = \begin{bmatrix} \cos t & -\sin t \ \sin t & \cos t \end{bmatrix} \begin{bmatrix} t \ 0 \end{bmatrix} = \begin{bmatrix} t\cos t \ t\sin t \end{bmatrix} \).
07
Formulate the General Solution
The general solution \( \mathbf{X} = \mathbf{X}_h + \mathbf{X}_p \) is given by \[ \mathbf{X} = c_1 \begin{bmatrix} \cos t \ \sin t \end{bmatrix} + c_2 \begin{bmatrix} -\sin t \ \cos t \end{bmatrix} + \begin{bmatrix} t\cos t \ t\sin t \end{bmatrix} \]. This completes the solution of the system.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Homogeneous Solution
When tackling linear differential equations, a crucial initial step is to identify the **homogeneous solution**. This involves solving the associated homogeneous equation, which in this case is \( \mathbf{X}' = A\mathbf{X} \). The matrix \( A = \begin{pmatrix} 0 & 1 \ -1 & 0 \end{pmatrix} \) guides us here. By determining the eigenvalues and eigenvectors, we can construct the solution.
Understanding this solution is key to progressing towards more complex systems, such as non-homogeneous systems.
- Find the characteristic equation from the matrix \( A \): \( \lambda^2 + 1 = 0 \).
- Solve this to get the eigenvalues \( \lambda = i \) and \( \lambda = -i \).
Understanding this solution is key to progressing towards more complex systems, such as non-homogeneous systems.
Eigenvalues and Eigenvectors
**Eigenvalues and eigenvectors** are fundamental in solving systems of differential equations. They tell us about the behavior of solutions and specific dynamic properties of the system. For the matrix \( A = \begin{pmatrix} 0 & 1 \ -1 & 0 \end{pmatrix} \), the process to find these properties is straightforward:
These components not only help build solutions but often reveal stability and periodicity aspects of dynamical systems. That's why a strong grasp of eigenvalues and eigenvectors is invaluable.
- Calculate the determinant of \( A - \lambda I \) to obtain the characteristic polynomial.
- Solve \( \lambda^2 + 1 = 0 \) for eigenvalues \( \lambda = i \) and \( \lambda = -i \).
These components not only help build solutions but often reveal stability and periodicity aspects of dynamical systems. That's why a strong grasp of eigenvalues and eigenvectors is invaluable.
Non-Homogeneous Systems
When dealing with **non-homogeneous systems**, such as \( \mathbf{X}' = A\mathbf{X} + \mathbf{F}(t) \), the solution comprises two parts: the homogeneous solution and a particular solution. This approach is vital because the non-homogeneous term \( \mathbf{F}(t) = \begin{pmatrix} 1 \ \cot t \end{pmatrix} \) influences the system uniquely. Techniques like variation of parameters let us find particular solutions tailored to this function.
- Assume a form for the particular solution as \( \mathbf{X}_p = \mathbf{X}_h \begin{bmatrix} u_1(t) \ u_2(t) \end{bmatrix} \).
- Differentiating and substituting into the original system allows simplification and elimination of the homogeneous component.
Fundamental Matrix Solution
A **fundamental matrix solution** is a structured way to describe the general solution of a linear differential system. For the homogeneous system \( \mathbf{X}' = A\mathbf{X} \), this matrix, denoted as \( \Phi(t) \), is crafted from independent solutions of the system. In the process here, it’s embodied by functions of sine and cosine, presenting as a 2x2 matrix:
When the inverse \( \Phi^{-1}(t) \) is needed, this convenient and reversible form \( \Phi^{-1}(t) = \begin{pmatrix} \cos t & \sin t \ -\sin t & \cos t \end{pmatrix} \) makes computation efficient. Combining fundamental matrices with variation of parameters allows the complete solution of non-homogeneous systems, seamlessly integrating the homogeneous and particular solutions. This conceptual framework is crucial in both theoretical and applied contexts of linear systems.
- \( \Phi(t) = \begin{pmatrix} \cos t & -\sin t \ \sin t & \cos t \end{pmatrix} \)
When the inverse \( \Phi^{-1}(t) \) is needed, this convenient and reversible form \( \Phi^{-1}(t) = \begin{pmatrix} \cos t & \sin t \ -\sin t & \cos t \end{pmatrix} \) makes computation efficient. Combining fundamental matrices with variation of parameters allows the complete solution of non-homogeneous systems, seamlessly integrating the homogeneous and particular solutions. This conceptual framework is crucial in both theoretical and applied contexts of linear systems.