Chapter 10: Problem 16
Verify that the vector \(\mathbf{X}\) is a solution of the given system. $$ \mathbf{X}^{\prime}=\left(\begin{array}{rrr} 1 & 0 & 1 \\ 1 & 1 & 0 \\ -2 & 0 & -1 \end{array}\right) \mathbf{x} ; \quad \mathbf{X}=\left(\begin{array}{c} \sin t \\ -\frac{1}{2} \sin t-\frac{1}{2} \cos t \\ -\sin t+\cos t \end{array}\right) $$
Short Answer
Step by step solution
Differentiate the vector function
Multiply the matrix and vector
Validate the calculation of each entry
Compare the results
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Functions
- Each component of the vector can be a function of one or more variables.
- In our example, each component is a trigonometric function of \( t \).
Matrix Multiplication
- We calculate the elements of the resulting vector by multiplying elements from the matrix rows by the vector components and summing them.
- This process allows us to verify if the vector function is a solution to the system of differential equations in question.
Differential Equations Verification
The verification steps include:
- First, differentiating each part of the vector function \( \mathbf{X}(t) \) to find \( \mathbf{X}'(t) \).
- Second, performing matrix multiplication with \( A \) and \( \mathbf{X}(t) \).
- Finally, comparing \( \mathbf{X}'(t) \) to the result of matrix multiplication.
Vector Calculus
- We used differentiation to find the rate of change of the vector function \( \mathbf{X}(t) \).
- This differentiation allowed us to assess how the components of the vector changed with respect to \( t \).