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The differential equation \(d P / d t=(k \cos t) P\) where \(k\) is a positive constant, is a model of human population \(P(t)\) of a certain community. Discuss an interpretation for the solution of this equation; in other words, what kind of population do you think the differential equation describes?

Short Answer

Expert verified
The equation models a population with periodic fluctuations, likely influenced by seasonal or cyclical factors.

Step by step solution

01

Analyze the differential equation

The given equation is \( \frac{dP}{dt} = (k \cos t) P \). It's a first-order linear differential equation where the rate of change of \( P(t) \) is proportional to \( P(t) \). This implies that the population growth rate depends on time in a cosine-like periodic manner.
02

Solve the differential equation

To solve the differential equation, separate the variables: \( \frac{dP}{P} = k \cos t \, dt \). Integrate both sides to find the solution: \( \ln |P| = k \int \cos t \, dt = k \sin t + C \). Exponentiating, we get the general solution \( P(t) = Ce^{k \sin t} \), where \( C \) is a constant.
03

Interpret the equation

The solution \( P(t) = Ce^{k \sin t} \) suggests that the population changes according to a sinusoidal function. This indicates that the population experiences regular periodic fluctuations, growing during certain periods and decreasing during others. Such a model could represent a population that migrates periodically or is influenced by seasonal factors.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Modeling
Population modeling is a fascinating topic where we use mathematics to study how populations of organisms, including humans, change over time. By using differential equations, we can predict potential increases or decreases in population sizes under various conditions. For example, the differential equation \(\frac{dP}{dt}=(k \cos t) P\) is one such model. It helps us understand how a community’s population size \(P(t)\) might change in response to factors that vary with time. When modeling population, we try to account for:
  • Births and deaths, which affect the population directly.
  • Immigration and emigration, or people moving in and out of the area.
  • Environmental factors that can cause the population to increase or decrease.

Using models like the one in the exercise helps researchers and policymakers make informed decisions, such as planning for resource allocation or conservation efforts.
First-Order Linear Differential Equations
First-order linear differential equations are equations that involve the first derivatives (rates of change) of a function and the function itself. This type of equation has the general form \(\frac{dy}{dx} + P(x)y = Q(x)\). They are used in many fields, including population dynamics. In our example, \(\frac{dP}{dt} = (k \cos t) P\), the equation is already in the form typically seen with population models.

This particular equation indicates that:
  • The rate of change of the population \(P(t)\) is proportional to the population itself.
  • The proportionality factor is \(k \cos t\), which means this rate of change is affected cyclically, like the cosine function itself.

We solve such equations often by separating variables, which involves manipulating the equation to integrate both sides. This gives insights into how \(P(t)\), the population at time \(t\), evolves. Once we solve these, we can predict dynamic population shifts, taking into account time-dependent factors.
Periodic Functions
Periodic functions are mathematical functions that repeat their values in regular intervals or periods. The most common types of periodic functions are the trigonometric functions such as sine and cosine. In the solution given, \(P(t) = Ce^{k \sin t}\), the sine function reveals a periodic behavior in the population size.

This means that:
  • Population increases and decreases cyclically, mirroring a wave-like pattern.
  • This wave could represent yearly cycles, such as seasonal migrations or breeding patterns, affecting the number of individuals in a population.

Periodic functions are crucial in modeling real-world phenomena where there is regular repetition, such as tidal movements, daylight hours, or climate patterns that impact the sustainability of populations over time.

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Most popular questions from this chapter

Verify that the indicated family of functions is a solution to the given differential equation. Assume an appropriate interval \(I\) of definition for each solution.$$ \frac{d P}{d t}=P(1-P) ; \quad P=\frac{c_{1} e^{t}}{1+c_{1} e^{t}} $$

Consider the differential equation \(d y / d x=y(a-b y)\), where \(a\) and \(b\) are positive constants. (a) Either by inspection, or by the method suggested in Problems 33-36, find two constant solutions of the DE. (b) Using only the differential equation, find intervals on the \(y\)-axis on which a nonconstant solution \(y=\phi(x)\) is increasing. On which \(y=\phi(x)\) is decreasing. (c) Using only the differential equation, explain why \(y=a / 2 b\) is the \(y\)-coordinate of a point of inflection of the graph of a nonconstant solution \(y=\phi(x)\). (d) On the same coordinate axes, sketch the graphs of the two constant solutions found in part (a). These constant solutions partition the \(x y\)-plane into three regions. In each region, sketch the graph of a nonconstant solution \(y=\phi(x)\) whose shape is suggested by the results in parts (b) and (c).

Determine a region of the \(x y\) -plane for which the given differential equation would have a unique solution whose graph passes through a point \(\left(x_{0}, y_{0}\right)\) in the region. $$ \frac{d y}{d x}=\sqrt{x y} $$

Determine a region of the \(x y\) -plane for which the given differential equation would have a unique solution whose graph passes through a point \(\left(x_{0}, y_{0}\right)\) in the region. $$ \frac{d y}{d x}-y=x $$

(a) Verify that \(y=\tan (x+c)\) is a one-parameter family of solutions of the differential equation \(y^{\prime}=1+y^{2}\). (b) Since \(f(x, y)=1+y^{2}\) and \(\partial f / \partial y=2 y\) are continuous everywhere, the region \(R\) in Theorem \(1.2 .1\) can be taken to be the entire \(x y\) -plane. Use the family of solutions in part (a) to find an explicit solution of the first-order initialvalue problem \(y^{\prime}=1+y^{2}, y(0)=0 .\) Even though \(x_{0}=0\) is in the interval \((-2,2)\), explain why the solution is not defined on this interval. (c) Determine the largest interval \(I\) of definition for the solution of the initial-value problem in part (b).

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