Chapter 21: Problem 2
Demonstrate that each of the following is harmonic and obtain the. conjugate function. (a) \(u(x, y)=\sinh x \cos y\) (b) \(u(x, y)=4 y(1+3 x)\).
Short Answer
Expert verified
Part (a) function is not harmonic. Conjugate function for Part (b) is \( v(x, y) = -4 x - 6 x^2 + 6 y^2 \).
Step by step solution
01
Verify that the function is harmonic (Part a)
A function is harmonic if it satisfies Laplace's equation: \[ u_{xx} + u_{yy} = 0. \] For the function \( u(x, y) = \sinh x \cos y \), compute the second partial derivatives: \[ u_x = \cosh x \cos y, \quad u_{xx} = \sinh x \cos y, \] \[ u_y = -\sinh x \sin y, \quad u_{yy} = \sinh x \cos y. \] Adding these, \[ u_{xx} + u_{yy} = \sinh x \cos y + \sinh x \cos y = 2 \sinh x \cos y eq 0. \] Therefore, \( u(x, y) \) is not harmonic.
02
Verify that the function is harmonic (Part b)
For the function \( u(x, y) = 4 y(1 + 3 x) \), compute the second partial derivatives: \[ u_x = 12 y, \quad u_{xx} = 0, \] \[ u_y = 4 (1 + 3 x), \quad u_{yy} = 0. \] Adding these, \[ u_{xx} + u_{yy} = 0 + 0 = 0. \] Therefore, \( u(x, y) \) is harmonic.
03
Find the conjugate function (Part b)
To find the harmonic conjugate, suppose \( u(x, y) = 4 y (1 + 3 x) \) and find \(v(x, y)\) such that \( u + iv \) is analytic. This requires: \[ u_x = v_y, \quad u_y = -v_x. \] From \( u_x = 12 y \): \[ v_y = 12 y \Rightarrow v = 6 y^2 + g(x), \] and from \( u_y = 4 (1 + 3 x) \): \[ -v_x = 4 (1 + 3 x) \Rightarrow v_x = -4 (1 + 3 x) \Rightarrow v = -4 x - 6 x^2 + h(y). \] Matching terms, \( v(x, y) = 6 y^2 - 4 x - 6 x^2 \). Thus, the harmonic conjugate is \( v(x, y) = -4 x - 6 x^2 + 6 y^2 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Laplace's equation
Laplace's equation is a crucial concept in the study of harmonic functions. A real-valued function, such as u(x, y), is considered harmonic if it satisfies this equation. Mathematically, Laplace's equation is expressed as: \[ u_{xx} + u_{yy} = 0 \] Here, \(u_{xx} \) and \(u_{yy} \) represent the second partial derivatives of the function \(u\) with respect to x and y, respectively.
A harmonic function implies there are no sources or sinks within the domain, meaning it represents a form of equilibrium. This property makes harmonic functions highly relevant in fields like physics and engineering, particularly in areas involving potential fields and steady-state heat distribution scenarios.
For example, consider the function in part (b) of the exercise: \(u(x, y) = 4 y(1+3 x) \). To determine if it is harmonic, we compute the second partial derivatives:
Understanding how to verify that a function satisfies Laplace's equation is the first step in identifying harmonic functions.
A harmonic function implies there are no sources or sinks within the domain, meaning it represents a form of equilibrium. This property makes harmonic functions highly relevant in fields like physics and engineering, particularly in areas involving potential fields and steady-state heat distribution scenarios.
For example, consider the function in part (b) of the exercise: \(u(x, y) = 4 y(1+3 x) \). To determine if it is harmonic, we compute the second partial derivatives:
- \( u_x = 12 y \)
- \( u_{xx} = 0 \)
- \( u_y = 4 (1 + 3 x) \)
- \( u_{yy} = 0 \)
Understanding how to verify that a function satisfies Laplace's equation is the first step in identifying harmonic functions.
Partial Derivatives
Partial derivatives measure how a function changes as its input variables change. In the context of multivariable functions, a partial derivative with respect to a variable shows how the function varies when all other variables are kept constant.
For a function \( u(x, y) \), the partial derivatives are denoted as \( u_x \) and \( u_y \), representing the rates of change with respect to x and y, respectively. When verifying if a function is harmonic, we need to compute the second partial derivatives, \( u_{xx} \) and \( u_{yy} \), and check if their sum is zero.
Consider part (a) from the exercise: \(u(x, y) = \sinh x \cos y \). We compute the first and second partial derivatives as follows:
Understanding how to compute and interpret partial derivatives is essential for verifying harmonicity and further analysis in multi-variable calculus.
For a function \( u(x, y) \), the partial derivatives are denoted as \( u_x \) and \( u_y \), representing the rates of change with respect to x and y, respectively. When verifying if a function is harmonic, we need to compute the second partial derivatives, \( u_{xx} \) and \( u_{yy} \), and check if their sum is zero.
Consider part (a) from the exercise: \(u(x, y) = \sinh x \cos y \). We compute the first and second partial derivatives as follows:
- \( u_x = \cosh x \cos y \)
- \( u_{xx} = \sinh x \cos y \)
- \( u_y = -\sinh x \sin y \)
- \( u_{yy} = \sinh x \cos y \)
Understanding how to compute and interpret partial derivatives is essential for verifying harmonicity and further analysis in multi-variable calculus.
Harmonic Conjugate
In complex analysis, a harmonic conjugate is a function paired with a given harmonic function to construct an analytic function. For a harmonic function \(u(x, y)\), a harmonic conjugate \(v(x, y)\) satisfies the Cauchy-Riemann equations:
\[ u_x = v_y \]
\[ u_y = -v_x \]
By solving these, we can find \(v(x, y)\).
In part (b) of the exercise, we sought the harmonic conjugate for \(u(x, y) = 4 y(1 + 3 x)\). From the partial derivatives, we have:
\( v_y = 12 y \Rightarrow v = 6 y^2 + g(x) \) \( -v_x = 4(1 + 3 x) \Rightarrow v_x = -4 - 12 x \Rightarrow v = -4 x - 6 x^2 + h(y) \) Combining these results, we resolve matching terms, giving us the harmonic conjugate function:
\( v(x, y) = -4 x - 6 x^2 + 6 y^2 \).
Examining harmonic conjugates helps in constructing complex functions and has applications in solving boundary value problems.
\[ u_x = v_y \]
\[ u_y = -v_x \]
By solving these, we can find \(v(x, y)\).
In part (b) of the exercise, we sought the harmonic conjugate for \(u(x, y) = 4 y(1 + 3 x)\). From the partial derivatives, we have:
- \( u_x = 12 y \)
- \( u_y = 4 (1 + 3 x) \)
\( v(x, y) = -4 x - 6 x^2 + 6 y^2 \).
Examining harmonic conjugates helps in constructing complex functions and has applications in solving boundary value problems.