Chapter 9: Problem 9
$$\begin{aligned} D_{\mathbf{u}} f(x, y) &=\lim _{h \rightarrow 0} \frac{f(x+h \sqrt{3} / 2, y+h / 2)-f(x, y)}{h}=\lim _{h \rightarrow 0} \frac{(x+h \sqrt{3} / 2)^{2}+(y+h / 2)^{2}-x^{2}-y^{2}}{h} \\ &=\lim _{h \rightarrow 0} \frac{h \sqrt{3} x+3 h^{2} / 4+h y+h^{2} / 4}{h}=\lim _{h \rightarrow 0}(\sqrt{3} x+3 h / 4+y+h / 4)=\sqrt{3} x+y \end{aligned}$$
Short Answer
Step by step solution
Understand the Directional Derivative
Expand the Function
Simplify the Terms
Simplify the Expression Under the Limit
Evaluate the Limit
Conclusion
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