Chapter 9: Problem 17
We take the surface to be \(z=0 .\) Then \(\mathbf{n}=\mathbf{k}\) and \(d S=d A .\) since curl \(\mathbf{F}=\frac{1}{1+y^{2}} \mathbf{i}+2 z e^{x^{2}} \mathbf{j}+y^{2} \mathbf{k},\) $$\begin{aligned} \oint_{C} z^{2} e^{x^{2}} d x+x y d y+\tan ^{-1} y d z &=\iint_{S}(\operatorname{curl} \mathbf{F}) \cdot \mathbf{n} d S=\iint_{S} y^{2} d S=\iint_{R} y^{2} d A \\ &=\int_{0}^{2 \pi} \int_{0}^{3} r^{2} \sin ^{2} \theta r d r d \theta=\left.\int_{0}^{2 \pi} \frac{1}{4} r^{4} \sin ^{2} \theta\right|_{0} ^{3} d \theta \\ &=\frac{81}{4} \int_{0}^{2 \pi} \sin ^{2} \theta d \theta=\frac{81 \pi}{4}. \end{aligned}$$
Short Answer
Step by step solution
Understanding the Problem
Find the Curl of \(\mathbf{F}\)
Set up the Double Integral
Convert to Polar Coordinates
Evaluate the Radial Integral
Evaluate the Angular Integral
Combine Results
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Line Integral
In vector calculus, it often involves a vector field rather than just a regular function, and it measures the total effect covered as you move along the path. Mathematically, a line integral of a vector field \( \mathbf{F} = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k} \) across a path \( C \) is given by \[\oint_C \mathbf{F} \cdot d\mathbf{r} = \oint_C (P \, dx + Q \, dy + R \, dz)\]- **Path Direction Matters**: When evaluating a line integral, the direction along the curve matters. Flipping the direction can change the sign of the evaluation.
- **Applications**: Line integrals are useful in physics for calculating work done by a force field along a path. They are also used in electromagnetism and fluid flow.
Surface Integral
A surface integral of a vector field gives a scalar and can be expressed like this:\[\iint_S \mathbf{F} \cdot d\mathbf{S} = \iint_S \mathbf{F} \cdot \mathbf{n} \, dS\]where \(\mathbf{n} \) is the unit normal vector and \( dS \) is the differential area element. This allows you to accumulate the field influence over an entire surface.
- **Stokes' Theorem**: This theorem is crucial for converting a line integral around a closed curve into a surface integral over the surface it encloses. It states:\[\oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (abla \times \mathbf{F}) \cdot \mathbf{n} \, dS\]- **Applications**: Surface integrals are used in physics to find the flux passing through a surface, such as magnetic or electric flux.
Polar Coordinates
The conversion formulas from Cartesian to polar coordinates are:\[ x = r \cos \theta, \quad y = r \sin \theta\]For integrals, the area element transforms into \( dA = r \, dr \, d\theta \). This transformation is particularly useful when dealing with circles or radial symmetry.
- **Benefits**: It simplifies calculations involving circles and spheres as these shapes are naturally radial.- **Applications**: Polar coordinates are often used in fields like engineering and physics where problems have rotational symmetry.
Vector Calculus
- **Key Operations**: Key operations in vector calculus include the gradient (\( abla \)), divergence, and curl\( (abla \times \mathbf{F}) \), which help describe how vector fields change in space.- **Stokes' Theorem Revisited**: This theorem specifically relates field rotation (curl) over a surface to the circulation along its boundary, providing profound physical meaning in electromagnetism and fluid dynamics.
- **Applications**: The principles of vector calculus are essential in physics and engineering, particularly in fluid dynamics, electromagnetism, and heat transfer, where understanding fields and their properties is crucial.