Chapter 9: Problem 16
(a) \(\lim _{t \rightarrow \alpha}\left[-4 \mathbf{r}_{1}(t)+3 \mathbf{r}_{2}(t)\right]=-4(\mathbf{i}-2 \mathbf{j}+\mathbf{k})+3(2 \mathbf{i}+5 \mathbf{j}+7 \mathbf{k})=2 \mathbf{i}+23 \mathbf{j}+17 \mathbf{k}\) (b) \(\lim _{t \rightarrow \alpha} \mathbf{r}_{1}(t) \cdot \mathbf{r}_{2}(t)=(\mathbf{i}-2 \mathbf{j}+\mathbf{k}) \cdot(2 \mathbf{i}+5 \mathbf{j}+7 \mathbf{k})=-1\)
Short Answer
Step by step solution
Understanding the Problem
Evaluating the Linear Combination
Simplifying the Linear Combination
Evaluating the Dot Product
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Limits of Vector Functions
When calculating the limit of a vector function, each component of the vector is independently considered. For example, given two vectors \( \mathbf{r}_{1}(t) \to \mathbf{i} - 2 \mathbf{j} + \mathbf{k} \) and \( \mathbf{r}_{2}(t) \to 2 \mathbf{i} + 5 \mathbf{j} + 7 \mathbf{k} \) as \( t \to \alpha \), we can determine their limits by evaluating each component:
- The limit of the \( \mathbf{i} \) components
- The limit of the \( \mathbf{j} \) components
- The limit of the \( \mathbf{k} \) components
Dot Product
The formula for calculating the dot product for two vectors \( \mathbf{a} = a_{1}\mathbf{i} + a_{2}\mathbf{j} + a_{3}\mathbf{k} \) and \( \mathbf{b} = b_{1}\mathbf{i} + b_{2}\mathbf{j} + b_{3}\mathbf{k} \) is:\[ \mathbf{a} \cdot \mathbf{b} = a_{1}b_{1} + a_{2}b_{2} + a_{3}b_{3} \]For instance, for the vectors in our example, doing the dot product \((\mathbf{i} - 2\mathbf{j} + \mathbf{k}) \cdot (2\mathbf{i} + 5\mathbf{j} + 7\mathbf{k})\) involves:
- Multiplying the corresponding components: \(1 \cdot 2\), \(-2 \cdot 5\), and \(1 \cdot 7\).
- Summing up these products: \[ 2 + (-10) + 7 = -1 \].
Linear Combination of Vectors
To compute a linear combination, take vectors \( \mathbf{r}_{1}(t) \) and \( \mathbf{r}_{2}(t) \) and combine them as: \(-4\mathbf{r}_{1}(t) + 3\mathbf{r}_{2}(t)\). Just like with limits, treat each vector's component separately:
- Multiply \(-4\) by each component of \(\mathbf{r}_{1}(t)\): \(-4 \mathbf{i} + 8 \mathbf{j} - 4 \mathbf{k}\).
- Multiply \(3\) by each component of \(\mathbf{r}_{2}(t)\): \(6 \mathbf{i} + 15 \mathbf{j} + 21 \mathbf{k}\).
- Add the scaled vectors together to find the resultant vector.