Chapter 8: Problem 24
$$\begin{aligned} \left|\begin{array}{ccc} 1 & 1 & 1 \\ x & y & z \\ 2+x & 3+y & 4+z \end{array}\right| &=\left|\begin{array}{cc} y & z \\ 3+y & 4+z \end{array}\right|-\left|\begin{array}{cc} x & z \\ 2+x & 4+z \end{array}\right|+\left|\begin{array}{cc} x & y \\ 2+x & 3+y \end{array}\right| \\ &=(4 y+y z-3 z-y z)-(4 x+x z-2 z-x z)+(3 x+x y-2 y-x y)=-x+2 y-z \end{aligned}$$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.