Chapter 8: Problem 23
$$\left|\begin{array}{lll} 1 & 1 & 1 \\ x & y & z \\ 2 & 3 & 4 \end{array}\right|=\left|\begin{array}{ll} y & z \\ 3 & 4 \end{array}\right|-\left|\begin{array}{ll} x & z \\ 2 & 4 \end{array}\right|+\left|\begin{array}{ll} x & y \\ 2 & 3 \end{array}\right|=(4 y-3 z)-(4 x-2 z)+(3 x-2 y)=-x+2 y-z$$
Short Answer
Step by step solution
Understand the Determinant Expression
Calculate the 3x3 Determinant
Compute the 2x2 Determinants
Combine the Results from Step 3
Verify the Simplification
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
3x3 Determinant
- Select an element from the first row, say, "1," and find the corresponding minor, which is a 2x2 matrix.
- The determinant then expands as: \[1 \cdot \begin{vmatrix} y & z \ 3 & 4 \end{vmatrix} - 1 \cdot \begin{vmatrix} x & z \ 2 & 4 \end{vmatrix} + 1 \cdot \begin{vmatrix} x & y \ 2 & 3 \end{vmatrix}\], using minors from each column under the element chosen.
- Finally, solve each 2x2 determinant and add or subtract as required.
2x2 Determinant
For example, consider \[\begin{vmatrix} y & z \ 3 & 4 \end{vmatrix}\], calculate the determinant by multiplying \(y\) by \(4\) and subtracting the product of \(z\) and \(3\), giving you \(4y - 3z\). This result demonstrates a small unit of a 3x3 determinant when expanded by minors.
The computation of each of the three involved 2x2 determinants was instrumental in solving the original problem as:
- \(\begin{vmatrix} y & z \ 3 & 4 \end{vmatrix} = 4y - 3z\)
- \(\begin{vmatrix} x & z \ 2 & 4 \end{vmatrix} = 4x - 2z\)
- \(\begin{vmatrix} x & y \ 2 & 3 \end{vmatrix} = 3x - 2y\)
Determinant Properties
- Linearity: The determinant is linear with respect to each row and column of the matrix. This means that if you scale a row by a constant, the determinant is also scaled by this constant.
- Swapping Rows: If you swap any two rows (or columns) of a matrix, the sign of the determinant changes. This is important and aids in certain methods of solving or simplifying matrix problems.
- Zero Determinant and Inverses: If the determinant of a matrix is zero, this means the matrix is singular, or not invertible. For full-rank matrices, a non-zero determinant implies the existence of an inverse matrix.
- Addition: If you add a multiple of one row to another, the determinant remains unchanged. This helps simplify matrix equations without altering specific values.