Chapter 7: Problem 25
$$\begin{aligned} (\mathbf{i}+\mathbf{j}) \times(\mathbf{i}+5 \mathbf{k}) &=[(\mathbf{i}+\mathbf{j}) \times \mathbf{i}]+[(\mathbf{i}+\mathbf{j}) \times 5 \mathbf{k}]=(\mathbf{i} \times \mathbf{i})+(\mathbf{j} \times \mathbf{i})+(\mathbf{i} \times 5 \mathbf{k})+(\mathbf{j} \times 5 \mathbf{k}) \\\ &=-\mathbf{k}+5(-\mathbf{j})+5 \mathbf{i}=5 \mathbf{i}-5 \mathbf{j}-\mathbf{k} \end{aligned}$$
Short Answer
Step by step solution
Expand the Cross Product
Distribute Each Term
Evaluate Individual Cross Products
Combine All Results
Simplify the Final Expression
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
For two standard unit vectors, such as \( \mathbf{i}, \mathbf{j}, \mathbf{k} \), their cross products are defined as:
- \( \mathbf{i} \times \mathbf{j} = \mathbf{k} \)
- \( \mathbf{j} \times \mathbf{k} = \mathbf{i} \)
- \( \mathbf{k} \times \mathbf{i} = \mathbf{j} \)
Vector Identities
Some key vector identities include:
- The cross product of a vector with itself is always zero: \( \mathbf{A} \times \mathbf{A} = \mathbf{0} \).
- Anticommutative property: \( \mathbf{A} \times \mathbf{B} = - (\mathbf{B} \times \mathbf{A}) \).
- Distributive property over addition: \( \mathbf{A} \times (\mathbf{B} + \mathbf{C}) = \mathbf{A} \times \mathbf{B} + \mathbf{A} \times \mathbf{C} \).
Distributive Property
In our exercise, this property is highlighted when distributing the cross product between sum pairs. For example:
- \( (\mathbf{i} + \mathbf{j}) \times \mathbf{i} = \mathbf{i} \times \mathbf{i} + \mathbf{j} \times \mathbf{i} \)
- \( (\mathbf{i} + \mathbf{j}) \times 5\mathbf{k} = 5(\mathbf{i} \times \mathbf{k} + \mathbf{j} \times \mathbf{k}) \)
Vector Simplification
The steps often include:
- Expanding using the distributive property to handle each part separately.
- Applying known vector identities to simplify each term (e.g., resolving cross products).
- Combining like terms by either adding or subtracting vectors.