Chapter 4: Problem 10
The Laplace transform of the differential equation is \\[ s \mathscr{L}\\{y\\}-\mathscr{L}\\{y\\}=\frac{2(s-1)}{\left((s-1)^{2}+1\right)^{2}} \\] Solving for \(\mathscr{L}\\{y\\}\) we obtain \\[ \mathscr{L}\\{y\\}=\frac{2}{\left((s-1)^{2}+1\right)^{2}} \\] Thus \\[ y=e^{t} \sin t-t e^{t} \cos t \\]
Short Answer
Step by step solution
Express the transform in terms of L{y}
Simplify to isolate L{y}
Identify the inverse transform
Recall known inverse transforms
Solution verification
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