Chapter 18: Problem 34
For \(f(z)=1 /(\overline{z-1}), \overline{f(z)}=1 /(z-1),\) so on \(z-1=2 e^{i t}, d z=2 i e^{i t} d t,\) and \(\oint_{C} \overline{f(z)} d z=\int_{0}^{2 \pi} \frac{1}{2 e^{i t}} \cdot 2 i e^{i t} d t=i \int_{0}^{2 \pi} d t=2 \pi i\). Thus circulation \(=\operatorname{Re}\left(\oint_{C} \overline{f(z)} d z\right)=0,\) and net \(\operatorname{flux}=\operatorname{Im}\left(\oint_{C} \overline{f(z)} d z\right)=2 \pi\).
Short Answer
Step by step solution
Expressing \( \overline{f(z)} \) in terms of \( z \)
Parametrize the contour \( z-1 = 2 e^{it} \)
Deriving \( dz \)
Setting up the contour integral
Simplifying the expression
Calculate the integral
Determine the real part (circulation)
Determine the imaginary part (net flux)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Contour Integration
- Parameterizing the contour to express complex functions in a form suitable for integration.
- Evaluating the integral by simplifying the expression, often making use of symmetries or cancellations inherent in the function or the contour.
Complex Conjugate
Parametrization
Imaginary and Real Parts
- The real part of the integral is often associated with circulation or as a measure of rotation around a point.
- The imaginary part is linked to flux, representing the net flow across the boundary of the contour.