Chapter 18: Problem 19
$$\int_{-4 i}^{4 i} \frac{1}{z^{2}} d z=-\left.\frac{1}{z}\right|_{-4 i} ^{4 i}=-\left[\frac{1}{4 i}-\left(\frac{1}{-4 i}\right)\right]=\frac{1}{2} i$$
Short Answer
Expert verified
The integral evaluates to \( \frac{i}{2} \).
Step by step solution
01
Understanding the Function and Limits
We need to compute the integral of the function \( f(z) = \frac{1}{z^2} \) over the limits from \( -4i \) to \( 4i \). This function represents a simple rational function of \( z \).
02
Integration of \( \frac{1}{z^2} \)
To integrate \( \frac{1}{z^2} \), we use the formula for the antiderivative: if \( f(z) = z^n \) where \( n eq -1 \), then its antiderivative is \( \frac{z^{n+1}}{n+1} \). Here \( n = -2 \), so the antiderivative is \( \frac{-1}{z} \).
03
Substituting the Limits into the Antiderivative
We substitute the upper and lower limits \( 4i \) and \( -4i \) into the antiderivative: \(-\left.\frac{1}{z}\right|_{-4i}^{4i}\). This gives us: \(-\left[\frac{1}{4i} - \frac{1}{-4i}\right]\).
04
Simplifying the Expression
Simplify \(-\left[\frac{1}{4i} - \frac{1}{-4i}\right]\):1. Compute \( \frac{1}{4i} \): multiply numerator and denominator by \( i \) to get \( -\frac{i}{4} \).2. Compute \( \frac{1}{-4i} \): similarly multiply to get \( \frac{i}{4} \).3. The expression becomes: \(-\left( -\frac{i}{4} - \frac{i}{4} \right) = -\left( -\frac{i}{2} \right) = \frac{i}{2}.\)
05
Final Answer
After simplification, we find that the integral \( \int_{-4i}^{4i} \frac{1}{z^2} dz \) evaluates to \( \frac{i}{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Antiderivative
In calculus, an antiderivative refers to a function whose derivative is the given function. When you are looking for an antiderivative, you are essentially performing the reverse operation of differentiation. This is a significant concept in integral calculus.
- To find the antiderivative, we seek a function whose rate of change (or derivative) matches the original function.
- For a function in the form of \( f(z) = z^n \) where \( n eq -1 \), the antiderivative is \( \frac{z^{n+1}}{n+1} \).
Rational Function
A rational function is defined as a ratio of two polynomials. In mathematical terms, it looks like \( f(z) = \frac{P(z)}{Q(z)} \), where both \( P(z) \) and \( Q(z) \) are polynomial functions.
- These functions can often be broken down into simpler parts, which can be easier to analyze or integrate.
- Rational functions are particularly interesting in complex analysis due to their behavior near poles and zeros.
Complex Numbers
Complex numbers extend the idea of the one-dimensional number line to a two-dimensional complex plane using an imaginary unit, \( i \). A complex number is expressed as \( z = a + bi \), where \( a \) and \( b \) are real numbers.
- The real part, \( a \), and the imaginary part, \( bi \), are crucial for operations involving complex numbers.
- In integration involving complex numbers, the limits themselves can be complex, such as from \( -4i \) to \( 4i \).
Definite Integral
A definite integral represents the signed area under a curve defined by a function over a specific interval. The process involves evaluating the antiderivative at specified bounds and subtracting accordingly.
- The definite integral has limits which, in the exercise, range from \( -4i \) to \( 4i \).
- This provides a numerical value representing the accumulation of quantities expressed by the function from one point to another on the complex plane.