Chapter 17: Problem 36
$$\frac{\left[8\left(\cos \frac{3 \pi}{8}+i \sin \frac{3 \pi}{8}\right)\right]^{3}}{\left[2\left(\cos \frac{\pi}{16}+i \sin \frac{\pi}{16}\right)\right]^{10}}=\frac{2^{9}}{2^{10}}\left[\cos \left(\frac{9 \pi}{8}-\frac{10 \pi}{16}\right)+i\left(\frac{9 \pi}{8}-\frac{10 \pi}{16}\right)\right]=\frac{1}{2}\left(\cos \frac{\pi}{2}+i \sin \frac{\pi}{2}\right)=\frac{1}{2} i$$
Short Answer
Step by step solution
Simplify the Numerator
Simplify the Denominator
Perform Division of Complex Numbers
Final Simplification
Result Verification
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Form of Complex Numbers
- \( r \) is the magnitude (or modulus) of the complex number.
- \( \theta \) is the argument (or angle) with respect to the positive x-axis.
- The magnitude \( r = \sqrt{x^2 + y^2} \) where \( z = x + iy \).
- The angle \( \theta = \text{atan2}(y, x) \).
Trigonometric Functions in Complex Numbers
When you see a complex number expressed as \( r(\cos \theta + i \sin \theta) \), it fundamentally represents the combination of these trigonometric coordinates scaled by \( r \). This makes use of Euler's formula, which contains the relationships:
- \( e^{i\theta} = \cos \theta + i \sin \theta \)
Multiplication and Division of Complex Numbers
- To multiply two complex numbers, multiply their magnitudes and add their angles.
- To divide two complex numbers, divide their magnitudes and subtract their angles.