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Consider a two-dimensional lattice in the \(x-y\) plane with sides of length \(L_{x}\) and \(L_{y}\) which contains \(N\) atoms ( \(N\) very large) coupled by nearest-neighbor harmonic forces. (a) Compute the Debye frequency for this lattice. (b) In the limit \(T \rightarrow 0\), what is the heat capacity?

Short Answer

Expert verified
The Debye frequency is \(\omega_D = v_s \sqrt{(\pi L_x)^2 + (\pi L_y)^2}\). The heat capacity at low temperatures is \(C = A T^2\) where \(A\) is a constant.

Step by step solution

01

Understanding the Lattice

Consider a 2D lattice with side lengths \(L_x\) and \(L_y\), containing \(N\) atoms. These atoms are coupled by nearest-neighbor harmonic forces.
02

Defining the Debye Frequency

The Debye frequency \(\omega_D\) is the maximum frequency of the phonons in the lattice. It can be determined using the density of states and the Debye model.
03

Phonon Dispersion Relation

For a 2D lattice, the phonon dispersion relation for nearest-neighbor harmonic forces can be approximated as \(\omega(k) = v_s |k|\), where \(v_s\) is the speed of sound in the material.
04

Calculating the Debye Frequency

To find \(\omega_D\), we need to consider the maximum wavevector \(k_{max}\). For a 2D lattice, the maximum wavevector is related to the lattice dimensions: \[k_{max} = \sqrt{(\pi L_x)^2 + (\pi L_y)^2}.\] Thus, \(\omega_D = v_s k_{max}\).
05

Heat Capacity at Low Temperatures

In the limit \(T \rightarrow 0\), the heat capacity \(C\) of a system can be derived using the Debye model. For a 2D lattice, the heat capacity is proportional to \(T^2\). Specifically, \[C = A T^2,\] where \(A\) is a material-dependent constant.
06

Summary of Results

The Debye frequency for the 2D lattice is \(\omega_D = v_s \sqrt{(\pi L_x)^2 + (\pi L_y)^2}\). The heat capacity at low temperatures is \(C = A T^2\), with \(A\) being a constant that depends on the material.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

2D Lattice
A 2D lattice refers to a two-dimensional arrangement of atoms positioned in a flat plane. In this problem, the lattice is set on the x-y plane. Each atom is coupled with its nearest neighbor via harmonic forces, which are idealized interactions that mimic a perfect spring-like behavior. The dimensions of the lattice are denoted as \(L_x\) and \(L_y\), representing the lengths in the x and y directions respectively.

Given the large number of \(N\) atoms, this lattice resembles a periodic crystal structure in two dimensions. Understanding how waves or vibrations move through this lattice (phonons) is crucial, as these phonons significantly affect the lattice's thermal properties.
Phonon Dispersion
Phonon dispersion describes how the frequency of phonons (vibrational quanta) varies with their wavevector \(k\). For a 2D lattice, with atoms interacting through nearest-neighbor harmonic forces, the phonon dispersion relation can be approximated by \(\omega(k) = v_s |k|\). Here, \(\omega(k)\) represents the phonon frequency, \(v_s\) is the speed of sound in the material, and \(k\) is the wavevector.

The dispersion relation essentially tells us how waves of different wavelengths propagate through the lattice. Longer wavelengths (smaller \(k\)) are associated with lower frequencies, while shorter wavelengths (larger \(k\)) possess higher frequencies. This relationship helps in determining the Debye frequency, the maximum possible frequency in the phonon spectrum. Consequently, the Debye frequency for the 2D lattice is given by \(\omega_D = v_s \sqrt{(\pi L_x)^2 + (\pi L_y)^2} \), considering that \(k_{max} = \sqrt{(\pi L_x)^2 + (\pi L_y)^2} \).
Heat Capacity
Heat capacity is a measure of the amount of heat energy needed to change the temperature of a material. In the context of a 2D lattice at low temperatures (as \(T \to 0\)), the heat capacity behaves differently compared to higher temperatures. Using the Debye model for heat capacity, we account for the contribution of phonons.

At very low temperatures, the heat capacity \(C\) for a 2D lattice is proportional to \(T^2 \). This can be dismissed as
  • \(C = A \cdot T^2 \),
where \(A\) is a material-dependent constant. This quadratic dependency arises because only phonons with wavelengths comparable to or longer than the thermal wavelength contribute significantly to the heat capacity. As the temperature increases, more phonons are excited, resulting in higher heat capacity. This relationship is a fundamental aspect of condensed matter physics and aids in predicting how materials behave thermally at low temperatures.

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Most popular questions from this chapter

Consider a solid surface to be a two-dimensional lattice with \(N_{\mathrm{s}}\) sites. Assume that \(N_{\mathrm{a}}\) atoms \(\left(N_{a} \ll N_{s}\right)\) are adsorbed on the surface, so that each lattice site has either zero or one adsorbed atom. An adsorbed atom has energy \(E=-\varepsilon\), where \(\varepsilon>0\). Assume the atoms on the surface do not interact with one another. If the surface is at temperature \(T\), compute the chemical potential of the adsorbed atoms as a function of \(T, \varepsilon\), and \(N_{\mathrm{a}} / N_{\mathrm{s}}\) (use the canonical ensemble).

An ideal gas, in a box of volume \(V\), consists of a mixture of \(N_{r}\) "red" and \(N_{g}\) "green" atoms, both with mass \(m\). Red atoms are distinguishable from green atoms. The green atoms have an internal degree of freedom that allows the atom to exist in two energy states, \(E_{\mathrm{g}, 1}=p^{2} /(2 m)\) and \(E_{\mathrm{g} 2}=p^{2} /(2 m)+\Delta\). The red atoms have no internal degrees of freedom. Compute the chemical potential of the "green" atoms.

A dilute gas, composed of a mixture of \(N_{1}\) iodine atoms 1 and \(N_{12}\) iodine molecules \(I_{2}\), is confined to a box of volume \(V=1.0 \mathrm{~m}^{3}\) at temperature \(T=300 \mathrm{~K}\). The rotational temperature of the iodine molecules is \(\theta_{\text {rot }}=0.0537 \mathrm{~K}\) (for simplicity we neglect vibrational modes). (a) Compute the chemical potentials, \(\mu_{1}\) and \(\mu_{12}\), of the iodine atoms and molecules, respectively. (b) The numbers of the iodine atoms and molecules can change via chemical reactions with one another. The condition for chemical equilibrium is \(\mu_{12}=2 \mu_{1}\). Use this condition to find the ratio \(N^{2}{ }_{1} / N_{12}\) when the gas is in equilibrium. (c) Does the inclusion of the rotational degree of freedom increase or decrease the number of \(\bar{I}_{2}\) molecules at chemical equilibrium.

A one-dimensional lattice of spin-1/2 lattice sites can be decomposed into blocks of three spins each. Use renormalization theory to determine whether or not a phase transition can occur on this lattice. If a phase transition does occur, what are its critical exponents? Retain terms in the block Hamiltonian to order \((V)\), where \(V\) is the coupling between blocks.

Two distinguishable three-level atoms on a lattice can each have energies \(0, \epsilon, 2 \epsilon\). Thus, the two-atom system can exist in nine different states with energies \(E_{j}(j=1, \ldots, 9)\), where \(E_{1}=0, E_{2}=\) \(E_{3}=\epsilon\), and \(E_{4}=E_{5}=E_{6}=2 \epsilon, E_{7}=E_{8}=3 \epsilon\) and \(E_{9}=4 e\). Find the probabilities \(f_{j}\) of the nine configurations \((j=1, \ldots, 9)\), assuming that they extremize the entropy \(S=-k_{\mathrm{B}} \sum_{i=1}^{9} f_{j} \operatorname{In} f_{j}\) subject to the conditions that the probability be normalized \(\sum_{j=1}^{9} f_{j}=1\) and the average energy be \(\sum_{j=1}^{9} E_{j} f_{j}=\frac{3}{2} \epsilon_{.}\)

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