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The molar free energy of a spin system can be written $$ \begin{aligned} \phi(T, H)=\phi_{0}(T) &-\frac{1}{2} J m^{2} \\ &+\frac{1}{2} k_{\mathrm{B}} T[(1+m) \ln (1+m)+(1-m) \ln (1-m)]-m H \end{aligned} $$ where \(J\) is the interaction strength, \(m\) is the net magnetization per mole, \(\phi_{0}(T)\) is the molar free energy in the absence of a net magnetization, \(H\) is an applied magnetic field, \(k_{\mathrm{B}}\) is Boltzmann's constant, and \(T\) is the temperature. (a) Compute the critical temperature (called the Curie temperature). (b) Compute the linear magnetic susceptibility of this system. (Hint: Only consider temperatures in the neighborhood of the critical point where \(m\) is small.)

Short Answer

Expert verified
The Curie temperature is \(T_c = \frac{J}{k_{\mathrm{B}}}\). The linear magnetic susceptibility is \(\chi = \frac{1}{k_{\mathrm{B}} (T - T_c)}\).

Step by step solution

01

Understanding the given Free Energy Expression

The given free energy expression for the spin system is: \[ \phi(T, H) = \phi_0(T) - \frac{1}{2} J m^2 + \frac{1}{2} k_{\mathrm{B}} T[(1+m) \ln(1+m) + (1-m) \ln(1-m)] - m H \]
02

Derive equation for critical temperature (Curie temperature)

At the critical temperature, the second derivative of the free energy with respect to magnetization \(m\) should be zero. Start by computing the first derivative of \(\phi(T, H)\) with respect to \(m\): \[ \frac{\partial \phi}{\partial m} = -J m + \frac{1}{2} k_{\mathrm{B}} T \left[ \ln(1+m) + 1 - \ln(1-m) - 1 \right] - H = -J m + \frac{1}{2} k_{\mathrm{B}} T \left[ \ln \left( \frac{1+m}{1-m} \right) \right] - H \]
03

Expand the logarithmic term near the critical point

Using the hint, we consider \(m\) to be small. Use the Taylor expansion for \(\ln(1+m)\) and \(\ln(1-m)\) around \(m = 0\): \[ \ln(1+m) \approx m - \frac{m^2}{2}, \quad \ln(1-m) \approx -m - \frac{m^2}{2} \] Therefore, \[ \ln \left( \frac{1+m}{1-m} \right) \approx 2m \]
04

Simplify the expression for first derivative

Substitute the expansion into the first derivative: \[ \frac{\partial \phi}{\partial m} = -J m + k_{\mathrm{B}} T m - H \] At equilibrium (no external field \(H = 0\)), set this derivative to zero: \[ -J m + k_{\mathrm{B}} T m = 0 \] When \(m eq 0\), this implies: \[ k_{\mathrm{B}} T - J = 0 \] Thus, the Curie temperature \(T_c\) is given by: \[ T_c = \frac{J}{k_{\mathrm{B}}} \]
05

Linear Magnetic Susceptibility

The linear magnetic susceptibility \(\chi\) is determined by: \[ \chi = \left( \frac{\partial m}{\partial H} \right)_{H\to0} \] To compute \(\chi\), perform the second derivative analysis. At \(T \approx T_c\) and for small \(m\): \[ \frac{\partial^2 \phi}{\partial m^2} = -J + k_{\mathrm{B}} T \] At the Curie temperature \(T_c\), this becomes zero. Above \(T_c\), \[ \left( \frac{\partial^2 \phi}{\partial m^2} \right) = k_{\mathrm{B}} (T - T_c) \] Therefore, the magnetic susceptibility: \[ \chi = \frac{1}{k_{\mathrm{B}} (T - T_c)} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

molar free energy
The molar free energy, denoted as \(\fhi(T, H)\), represents the energy per mole for a system influenced by temperature and magnetic field. For a spin system, the expression is: \(\fhi(T, H) = \fhi_0(T) - \frac{1}{2} J m^2 + \frac{1}{2} k_B T[(1+m) \text{ln}(1+m) + (1-m) \text{ln}(1-m)] - mH\). Here’s the breakdown:
  • \(\fhi_0(T)\) is the intrinsic free energy without magnetization.
  • \(J\) indicates the interaction strength within the system.
  • \(m\) is the magnetization, representing the net magnetic moment per mole.
  • \(H\) is the external magnetic field.
  • \(k_B\), Boltzmann's constant, bridges microscopic and macroscopic measurements.
  • \(T\) is the temperature of the system.
This expression captures the combined effects of thermal energy, interaction effects, and applied magnetic fields on the system's energy. It plays a crucial role in determining other properties such as the magnetization and susceptibility.
magnetization
Magnetization (\(m\)) refers to the net magnetic moment per mole within the spin system. It's crucial in studying how aligned the magnetic moments are in response to temperature and external fields. In the given expression for molar free energy, magnetization is highlighted as:
  • The term \(-\frac{1}{2} J m^2\) covers the interaction energy among magnetic moments.
  • The terms \(\frac{1}{2} k_B T [(1+m) \text{ln}(1+m) + (1-m) \text{ln}(1-m)]\) showcase the entropy contribution related to magnetization.
  • The term \(-mH\) shows the energy contribution due to an external magnetic field.
Magnetization changes with temperature, reaching zero at high temperatures where the magnet becomes paramagnetic. Understanding magnetization is essential to grasp key thermal and magnetic behaviors like the Curie temperature.
linear magnetic susceptibility
Linear magnetic susceptibility (\(\fchi\)) measures a material's response to an external magnetic field, indicating how easily it can be magnetized. For small magnetization (near the Curie temperature), the formula is: \(\fchi = \frac{\fleft(\fpartial m\fright)}{\fpartial H}\fgmid_{H \rightarrow 0}\).
Here's how to find it:
  • From the molar free energy, the first derivative with respect to \(m\) is simplified to \(-J m + k_B T m - H\).
  • At equilibrium with \(H=0\), solve \(J m = k_B T m\) to get the Curie temperature: \(T_c = \frac{J}{k_B}\).
  • Above \(T_c\), use the second derivative of \(\fleft(\fphi\fright)\) giving \(k_B (\fleft(T - T_c\fright))\) for susceptibility: \(\fchi = \frac{1}{k_B (T - T_c)}\).
This demonstrates how susceptibility approaches infinity as temperature nears and exceeds the Curie point, reflecting heightened magnetic responsiveness.
spin system
A spin system comprises particles with intrinsic spin, influencing their magnetic properties. Spins can align in different ways, impacting the system's free energy and magnetic behavior. For our spin system:
  • The expression \(\fphi(T, H)\) accounts for all influences on free energy: interaction energy, entropy effects, and external fields.
  • Its magnetization behavior, captured by \(m\), responds to temperature and applied field \(H\).
  • The critical behavior around the Curie temperature, defined as \(T_c = \frac{J}{k_B}\), marks the transition from ferromagnetic (ordered spins) to paramagnetic (random spins).
Understanding a spin system helps analyze its magnetic properties and predict behaviors under varying temperature and field conditions, crucial in fields like condensed matter physics and materials engineering.

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Most popular questions from this chapter

Compute the equilibrium vapor pressure of a monomolecular gas in equilibrium with, a spherical droplet of liquid of the same substance, as a function of the radius \(R\) of the droplet and for fixed temperature. Assume the gas phase is well described by the ideal gas equation of state and the liquid can be assumed to be incompressible. Use the fact that for mechanical equilibrium \(P_{1}-P_{\mathrm{g}}=\) \(2 \sigma / R\), where \(P_{1}\left(P_{g}\right)\) is the pressure of the liquid (gas) and \(\sigma\) is the surface tension.

A system in its solid phase has a Helmholtz free energy per mole, \(a_{s}=B / T v^{3}\) and in its liquid phase it has a Helmholtz free energy per mole \(a_{1}=A / T v^{2}\), where \(\mathrm{A}\) and \(\mathrm{B}\) are constants, \(v\) is the volume per mole, and \(T\) is the temperature. (a) Compute the molar Gibbs free energy density of the liquid and solid phases. (b) How are the molar volumes, \(v\), of the liquid and solid related at the liquidsolid phase transition? (c) What is the slope of the coexistence curve in the \(P-T\) plane?

One kilogram of superheated steam, at temperature \(t=350^{\circ} \mathrm{C}\), pressure \(P=100\) bar, and specific entropy \(s=5949 \mathrm{~kJ} /(\mathrm{kg} \mathrm{K})\), is expanded reversibly and adiabatically to form wet steam at \(t=\) \(200^{\circ} \mathrm{C}\) and pressure \(P=15.55\) bar. The specific entropy of water vapor and liquid water on the coexistence curve at \(t=200{ }^{\circ} \mathrm{C}\) are \(\mathrm{s}_{\mathrm{g}}=6.428 \mathrm{~kJ} /(\mathrm{kg} \mathrm{K})\) and \(s_{1}=2.331 \mathrm{~kJ} /(\mathrm{kg} \mathrm{K})\), respectively. The specific enthalpy of water vapor (gas) and liquid water on the coexistence curve at \(t=200^{\circ} \mathrm{C}\) are \(h_{\mathrm{g}}=\) \(2791 \mathrm{~kJ} / \mathrm{kg}\) and \(h_{1}=852.4 \mathrm{~kJ} / \mathrm{kg}\). (a) What is the specific enthalpy of the wet steam at \(t=200^{\circ} \mathrm{C}\) ? (b) What fraction of the wet steam is liquid water?

A mixture of particles A and B have a molar Gibbs free energy of the form $$ g=x_{\mathrm{A}} \mu_{\mathrm{A}}^{\circ}(P, T)+x_{\mathrm{B}} \mu_{\mathrm{B}}^{\circ}(P, T)+R T x_{\mathrm{A}} \ln x_{\mathrm{A}}+R T x_{\mathrm{B}} \ln x_{\mathrm{B}}+\lambda x_{\mathrm{A}} x_{\mathrm{B}} $$ where \(\mu_{\mathrm{A}}^{\circ}(P, T)\) and \(\mu_{\mathrm{B}}^{\circ}(P, T)\) are the chemical potentials of pure A and pure B, respectively, at pressure \(P\) and temperature \(T, R\) is the gas constant, \(x_{A}\) and \(x_{\mathrm{B}}\) are the mole fractions of A and B, respectively, and \(\lambda\) measures the strength of coupling between \(\mathrm{A}\) and \(\mathrm{B}\). In terms of dimensionless parameters, \(\bar{g}=g / \lambda, \bar{\mu}_{A}^{\circ}(P, T)=\mu_{\mathrm{A}}^{\circ}(P, T) / \lambda, \bar{\mu}_{\mathrm{B}}^{0}(P, T)=\mu_{\mathrm{B}}^{0}(P, T) / \lambda\), and \(\tau=R T / \lambda\), the molar Gibbs free energy takes the form. $$ \bar{g}=x_{\mathrm{A}} \bar{\mu}_{\mathrm{A}}^{\circ}(P, T)+x_{\mathrm{B}} \bar{\mu}_{\mathrm{B}}^{\circ}(P, T)+\tau x_{\mathrm{A}} \ln x_{\mathrm{A}}+\tau x_{\mathrm{B}} \ln x_{\mathrm{B}}+x_{\mathrm{A}} x_{\mathrm{B}} $$ Assume that \(\overline{\mu_{\mathrm{B}}}=0.45\) and \(\bar{\mu}_{\mathrm{A}}=0.40\). (a) Find the critical temperature \(\tau_{c}\) at which phase separation occurs and plot the curve separating the chemically stable from unstable regions in the \(\tau-x_{\mathrm{A}}\) plane. (b) For \(\tau=1 / 2.6\), find equilibrium values of \(x_{\mathrm{A}}\) on the coexistence curve. (c) For \(\tau=1 / 3.6\), find equilibrium values of \(x_{\mathrm{A}}\) on the coexistence curve. (d) On the same plot as in (a), plot (sketch) the coexistence curve. You can estimate its location based on your results in (b) and (c).

Consider a monatomic fluid along its liquid-gas coexistence curve. Compute the rate of change of chemical potential along the coexistence curve \((\mathrm{d} \mu / \mathrm{d} T)\) owex, where \(\mu\) is the chemical potential and \(T\) is the temperature. Express your answer in terms of \(s_{1}, v_{1}\) and \(s_{\mathrm{g}}, v_{\mathrm{g}}\), which are the molar entropy and molar volume of the liquid and gas, respectively.

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