Chapter 3: Problem 9
Consider a body \(B=\left\\{\boldsymbol{x} \in \boldsymbol{E}^{3} \mid
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Chapter 3: Problem 9
Consider a body \(B=\left\\{\boldsymbol{x} \in \boldsymbol{E}^{3} \mid
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These are the key concepts you need to understand to accurately answer the question.
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Suppose the Cauchy stress field in a body \(B=\left\\{\boldsymbol{x} \in \boldsymbol{E}^{3}|| x_{i} \mid<\right.\) \(1\\}\) is uniaxial of the form $$ [\boldsymbol{S}]=\left(\begin{array}{lll} 0 & 0 & 0 \\ 0 & \sigma & 0 \\ 0 & 0 & 0 \end{array}\right) $$ where \(\sigma \neq 0\) is constant. In this case notice that the traction field \(t\) on any plane through \(B\) will be constant because \(S\) and \(n\) are constant. (a) Consider the family of planes \(\Gamma_{\theta}\) through the origin which contain the \(x_{1}\)-axis and have unit normal \([\boldsymbol{n}]=(0, \cos \theta, \sin \theta)^{T}\), \(\theta \in[0, \pi / 2] .\) Find the normal and shear stresses \(\sigma_{n}\) and \(\sigma_{s}\) on these planes as a function of \(\theta\) (b) Show that the maximum normal stress is \(\sigma_{n}=|\sigma|\) and that this value occurs on the plane with \(\theta=0\). Similarly, show that the maximum shear stress is \(\sigma_{s}=\frac{1}{2}|\sigma|\) and that this value occurs on the plane with \(\theta=\pi / 4\). Remark: The result in (b) illustrates the principle that planes of maximum shear stress occur at 45 -degree angles to planes of maximum normal stress.
Suppose the Cauchy stress tensor at a point \(\boldsymbol{x}\) in a body has the form $$ [\boldsymbol{S}]=\left(\begin{array}{rrr} 5 & 3 & -3 \\ 3 & 0 & 2 \\ -3 & 2 & 0 \end{array}\right) $$ and consider a surface \(\Gamma\) with normal \([\boldsymbol{n}]=(0,1 / \sqrt{2}, 1 / \sqrt{2})^{T}\) and a surface \(\Gamma^{\prime}\) with normal \(\left[\boldsymbol{n}^{\prime}\right]=(1,0,0)^{T}\) at \(\boldsymbol{x} .\) (a) Find the normal and shear tractions \(\left[\boldsymbol{t}_{n}\right]\) and \(\left[\boldsymbol{t}_{s}\right]\) on each surface at \(x .\) In particular, show that \(\Gamma\) experiences no shear traction at \(\boldsymbol{x}\), whereas \(\Gamma^{\prime}\) does. (b) Find the principal stresses and stress directions at \(\boldsymbol{x}\) and verify that \([\boldsymbol{n}]\) is a principal direction.
Consider a continuum body \(B\) subject to a body force per unit volume \(\widehat{\boldsymbol{b}}\) and a traction field \(\boldsymbol{h}\) on its bounding surface. Suppose \(B\) is in equilibrium and let \(S\) denote its Cauchy stress field. Define the average stress tensor \(\bar{S}\) (a constant) in \(B\) by $$ \overline{\boldsymbol{S}}=\frac{1}{\operatorname{vol}[B]} \int_{B} \boldsymbol{S} d V_{\boldsymbol{x}} $$ (a) Use the local equilibrium equations for \(B\) to show that $$ \overline{\boldsymbol{S}}=\frac{1}{\operatorname{vol}[B]}\left[\int_{B} \boldsymbol{x} \otimes \widehat{\boldsymbol{b}} d V_{\boldsymbol{x}}+\int_{\partial B} \boldsymbol{x} \otimes \boldsymbol{h} d A_{\boldsymbol{x}}\right] $$ (b) Suppose that \(\widehat{b}=0\) and that the applied traction \(h\) is a uniform pressure, so that $$ \boldsymbol{h}=-p \boldsymbol{n} $$ where \(p\) is a constant and \(\boldsymbol{n}\) is the outward unit normal field on \(\partial B\). Use the result in (a) to show that the average stress tensor is spherical, namely $$ \overline{\boldsymbol{S}}=-p \boldsymbol{I} $$ (c) Under the same conditions as in (b) show that the uniform, spherical stress field \(\boldsymbol{S}=-p \boldsymbol{I}\) satisfies the equations of equilibrium in \(B\) and the boundary condition \(\boldsymbol{S} \boldsymbol{n}=\boldsymbol{h}\) on \(\partial B\). Thus in this case we have \(\boldsymbol{S}(\boldsymbol{x})=\overline{\boldsymbol{S}}\) for all \(\boldsymbol{x} \in B\) Remark: The result in (a) is known as Signorini's Theorem. It states that the average value of the Cauchy stress tensor in a body in equilibrium is completely determined by the external surface traction \(\boldsymbol{h}\) and the body force \(\widehat{\boldsymbol{b}}\).
Suppose a body with configuration \(B=\left\\{\boldsymbol{x} \in
\boldsymbol{E}^{3} \mid 0
Consider a continuum body \(B\) with mass density \(\rho\) subject to a body force per unit mass \(b\) and a traction \(h\) on its bounding surface. Assume the Cauchy stress field \(\boldsymbol{S}\) in \(B\) is related to a vector field \(\boldsymbol{u}: B \rightarrow \mathcal{V}\) by the expression $$ S=\mathbf{C} \boldsymbol{E} \quad \text { or } \quad S_{i j}=\mathrm{C}_{i j k l} E_{k l} $$ where \(\mathbf{C}\) is a constant fourth-order tensor and \(\boldsymbol{E}: B \rightarrow \mathcal{V}^{2}\) is defined by $$ \boldsymbol{E}=\operatorname{sym}(\nabla \boldsymbol{u})=\frac{1}{2}\left(\nabla \boldsymbol{u}+\nabla \boldsymbol{u}^{T}\right) $$ Here \(\boldsymbol{u}\) is the displacement field of the body from an unstressed state and \(\boldsymbol{E}\) is the infinitesimal strain tensor. Moreover, let \(W\) denote the strain energy in \(B\), defined by $$ W=\frac{1}{2} \int_{B} \boldsymbol{E}(\boldsymbol{x}): \mathbf{C} \boldsymbol{E}(\boldsymbol{x}) d V_{\boldsymbol{x}} $$ Assuming \(B\) is in equilibrium show that $$ W=\frac{1}{2}\left(\int_{B} \rho(\boldsymbol{x}) \boldsymbol{b}(\boldsymbol{x}) \cdot \boldsymbol{u}(\boldsymbol{x}) d V_{\boldsymbol{x}}+\int_{\partial B} \boldsymbol{h}(\boldsymbol{x}) \cdot \boldsymbol{u}(\boldsymbol{x}) d A_{\boldsymbol{x}}\right) $$
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