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Motion of an oscillating liquid column in an U-tube is (A) periodic but not simple harmonic. (B) non-periodic. (C) simple harmonic and time period is independent of the density of the liquid. (D) simple harmonic and time period is directly proportional to the density of the liquid.

Short Answer

Expert verified
The motion of an oscillating liquid column in a U-tube is simple harmonic, and the time period is directly proportional to the square root of the density of the liquid (T = 2蟺鈭((蟻V^2g(2x))/F)).

Step by step solution

01

Understanding the Oscillating Liquid Column in a U-tube

In a U-tube, when one liquid column is displaced from its equilibrium position, it oscillates back and forth due to the movement of the other liquid column. The pressure difference between the two columns provides the restoring force, which drives the oscillation. In this system, there are a few forces that act on the liquid column such as gravitational and pressure forces.
02

Determining the Type of Motion

To determine if the motion is periodic or simple harmonic, we need to analyze the restoring force and its relationship with the displacement of the liquid column from its equilibrium position. If the restoring force is directly proportional to the displacement, then the motion is simple harmonic. For a liquid column in a U-tube with a small displacement x, the difference in height between two liquid columns on the two sides of the U-tube is approximately 2x. The pressure difference between the two columns can be represented as 螖P = 蟻g(2x), where 蟻 is the density of the liquid, g is the acceleration due to gravity, and x is the displacement. The restoring force acting on the liquid column is proportional to the pressure difference, therefore, F = k(螖P) = k(蟻g(2x)), where k is a constant. Since the restoring force is directly proportional to the displacement x, the motion of the oscillating liquid column in a U-tube is indeed simple harmonic.
03

Analyzing the Time Period and Density Dependency

In simple harmonic motion, the time period (T) is given by the equation T = 2蟺鈭(m/k), where m is the mass of the object, and k is the spring constant. In the case of the oscillating liquid column in a U-tube, m = 蟻V, where V is the volume of the liquid, and k is determined by the structure of the U-tube and fluid properties. Rearranging the previous equation of the force, we find the constant k = F/(蟻g(2x)). Substituting into the equation for the time period: T = 2蟺鈭(蟻V/k) = 2蟺鈭(蟻V/(F/(蟻g(2x)))) Simplifying the equation, we find: T = 2蟺鈭((蟻V^2g(2x))/F) From the equation, we can observe that the time period (T) is directly proportional to the square root of the density (蟻). Thus, the time period is dependent on the density of the liquid. Based on our analysis, the correct answer is: (D) simple harmonic and time period is directly proportional to the square root of the density of the liquid.

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