/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 243 A bus is moving towards a huge w... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A bus is moving towards a huge wall with a velocity of \(5 \mathrm{~m} / \mathrm{s}\). The driver sounds a horn of frequency \(200 \mathrm{~Hz}\). What is the frequency of beats heard by a passenger of the bus, if the speed of sound in air is \(330 \mathrm{~m} / \mathrm{s}\).

Short Answer

Expert verified
The beat frequency heard by a passenger on the bus is approximately \(2.02\,\text{Hz}\).

Step by step solution

01

Analyze the given data

In this problem, we have: - Velocity of the bus (source), \(v_s = 5 \,\text{m/s}\) - Frequency of the horn, \(f_s = 200\,\text{Hz}\) - Speed of sound in air, \(v = 330 \,\text{m/s}\) The aim is to find the frequency of beats heard by the passenger on the bus.
02

Apply Doppler effect formula for the moving source and stationary listener

The Doppler effect formula for a moving source and a stationary listener is given by: \[f_{obs} = \frac{v}{v - v_s} * f_s\] where \(f_{obs}\) is the frequency observed by a stationary listener (in this case, the wall). Plug in the given values to find the frequency observed by the wall: \[f_{obs} = \frac{330}{330 - 5} * 200 = \frac{330}{325} * 200\]
03

Calculate the reflected frequency from the wall

Now we need to calculate the reflected frequency heard by the passenger on the bus. Since the wall is stationary, we need to consider the bus as the observer, and hence use the Doppler effect formula for the stationary source and moving observer: \[f_r = \frac{v + v_s}{v} * f_{obs}\] Plug in the given values (using the calculated frequency observed by the wall as \(f_{obs}\)): \[f_r = \frac{330 + 5}{330} * \frac{330}{325} * 200 = \frac{335}{330} * \frac{330}{325} * 200\]
04

Calculate the beat frequency

The beat frequency is the difference between the reflected frequency from the wall and the original frequency of the horn: \[f_{beat} = |f_r - f_s|\] Plug in the calculated reflected frequency (\(f_r\)) and the original frequency (\(f_s\)): \[f_{beat} = \left|\frac{335}{330} * \frac{330}{325} * 200 - 200\right|\]
05

Calculate the final result

Now, we can compute the final result, the beat frequency: \[f_{beat} = \left|\frac{335}{330} * \frac{330}{325} * 200 - 200\right| \approx 2.02\,\text{Hz}\] The beat frequency heard by a passenger on the bus is approximately 2.02 Hz.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If \(y, u\), and \(a\) represent displacement, velocity, and acceleration at any instant for a particle executing SHM, which of the following statements are true? (A) \(v\) and \(y\) may have same direction. (B) \(v\) and \(a\) have same direction twice in each cycle. (C) \(a\) and \(y\) may have same direction. (D) \(a\) and \(v\) never have same direction.

A wire of length \(1.5 \mathrm{~m}\) under tension emits a fundamental note of frequency \(120 \mathrm{~Hz}\). (A) What would be its fundamental frequency if the length is increased by half under the same tension? (B) By how much should the length be shortened so that the frequency is increased three-fold?

The amplitude of a damped oscillator decreases to \(0.9\) times its original magnitude in \(5 \mathrm{~s}\). In another \(10 \mathrm{~s}\) it will decrease to \(\alpha\) times its original magnitude, where \(\alpha\) equals (A) \(0.81\) (B) \(0.729\) (C) \(0.6\) (D) \(0.7\)

Two longitudinal waves propagating in the \(X\) and \(Y\) directions superimpose. The wave equations are as below \(\psi_{1}=A \cos (\omega t-k x)\) and \(\psi_{2}=A \cos (\omega t-k y)\). Trajectory of the motion of a particle lying on the line \(y=x+\frac{(2 n+1) \lambda}{2}\) will be (A) Straight line (B) Circle (C) Ellipse (D) None of these

A tuning fork of known frequency \(256 \mathrm{~Hz}\) makes 5 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per second when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was (A) \(256+2 \mathrm{~Hz}\) (B) \(256-2 \mathrm{~Hz}\) (C) \(256-5 \mathrm{~Hz}\) (D) \(256+5 \mathrm{~Hz}\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.