Chapter 6: Problem 27
Magnitude of friction force acting on the plank is (A) \(\frac{F}{7}\) (B) \(\frac{F}{14}\) (C) \(\frac{F}{21}\) (D) \(\frac{2 F}{7}\)
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Chapter 6: Problem 27
Magnitude of friction force acting on the plank is (A) \(\frac{F}{7}\) (B) \(\frac{F}{14}\) (C) \(\frac{F}{21}\) (D) \(\frac{2 F}{7}\)
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An annular ring with inner and outer radii \(R_{1}\) and \(R_{2}\) is rolling without slipping with a uniform angular speed. The ratio of the forces experienced by two particles situated on the inner and outer parts of the ring is (C) \(\left(\frac{R_{1}}{R_{2}}\right)^{2}\) \([2005]\) (A) \(\frac{R_{1}}{R_{2}}\) (B) 1 (D) \(\frac{R_{2}}{R_{1}}\) [Note: The particles should be of same mass]
Let \(a_{r}\) and \(a_{t}\) represent radial and tangential acceleration. The motion of a particle may be circular if (A) \(a_{r}=a_{t}=0\) (B) \(a_{r}=0\) and \(a_{t} \neq 0\) (C) \(a_{r} \neq 0\) and \(a_{t}=0\) (D) \(a_{r} \neq 0\) and \(a_{t} \neq 0\)
While the disc skids, its translational and angular acceleration are related as (A) \(a=R \alpha\) (B) \(a=\frac{1}{4} R \alpha\) (C) \(a=\frac{1}{2} R \alpha\) (D) \(a=2 R \alpha\)
The centre of a wheel rolling on a plane surface moves with a speed \(v_{0}\). A particle on the rim of the wheel at the same level as that centre will be moving at speed \(\sqrt{n} v_{0}\) then the value of \(n\) is.
A particle of mass \(m\) is moving along the line \(y=3 x+5\) with speed \(v\). The magnitude of angular momentum about origin is (A) \(\sqrt{\frac{5}{2}} m v\) (B) \(\frac{5}{2} m v\) (C) \(\frac{1}{2} m v\) (D) \(\frac{1}{\sqrt{3}} m v\)
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