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Chapter 20: Problem 34

If a full wave rectifier circuit is operating from \(50 \mathrm{~Hz}\) mains, the fundamental frequency in the ripple will be (A) \(50 \mathrm{~Hz}\) (B) \(70.7 \mathrm{~Hz}\) (C) \(100 \mathrm{~Hz}\) (D) \(25 \mathrm{~Hz}\)

Short Answer

Expert verified
The fundamental frequency of the ripple in a full wave rectifier circuit operating from 50 Hz mains can be calculated by multiplying the input frequency by 2, since both halves of the AC input waveform are being used. Therefore, the frequency of ripple = 2 * 50 Hz = 100 Hz. So, the correct answer is (C) \(100 \mathrm{~Hz}\).

Step by step solution

01

Understand and analyze a full wave rectifier circuit

A full wave rectifier circuit utilizes both the positive and negative halves of the AC input waveform to produce a continuous DC output voltage. Since both halves of the waveform are being used, the frequency of the ripple voltage will be two times the frequency of the input voltage.
02

Analyze the given input frequency

In this problem, the full wave rectifier circuit is operating with an input frequency of 50 Hz.
03

Calculate the ripple frequency

To calculate the ripple frequency, we will multiply the input frequency by 2, since both halves of the AC input waveform are being used. Frequency of ripple = 2 * input frequency Frequency of ripple = 2 * 50 Hz
04

Determine the final answer

Calculate the value: Frequency of ripple = 100 Hz The correct answer is (C) 100 Hz.

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