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Chapter 20: Problem 3

On increasing the reverse bias to a large value in a \(P-N\) junction diode, current (A) Increases slowly (B) Remains fixed (C) Suddenly increases (D) Decreases slowly

Short Answer

Expert verified
Based on the analysis of the relationship between reverse bias voltage and current in a P-N junction diode, the correct answer is (C) Suddenly increases. This is because at a certain large reverse bias voltage called the breakdown voltage, the current through the P-N junction diode suddenly increases due to avalanche breakdown.

Step by step solution

01

Understand P-N Junction Diode and Reverse Bias

A P-N junction diode is a semiconductor device formed by the junction of a p-type and n-type semiconductor material. In a reverse bias situation, the voltage across the P-N junction is such that the electric field direction opposes the natural movement of majority charge carriers. This means that the current flow through the diode is primarily due to the drift of minority carriers.
02

Analyze the Relationship Between Reverse Bias Voltage and Current

When the reverse bias voltage across a P-N junction diode is increased, the electric field strength at the junction increases. This results in a higher drift speed for minority carriers, and hence, a higher current flow due to minority carriers. However, this increase is not very significant as the concentration of minority carriers is usually very low as compared to majority carriers.
03

Evaluate Each Option

(A) Increases slowly: This statement is not accurate because, as explained above, the increase in current due to increasing reverse bias voltage is very minimal and not easily noticeable. (B) Remains fixed: This option is also incorrect because the current flow is not constant when the reverse bias voltage is increased. (C) Suddenly increases: This statement is accurate since at a certain large reverse bias voltage called the breakdown voltage, the current through the P-N junction diode suddenly increases due to avalanche breakdown. (D) Decreases slowly: This option is not correct because when the reverse bias voltage is increased, current doesn't decrease.
04

Choose the Correct Option

Based on our analysis, we can conclude that the correct option is: (C) Suddenly increases

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Most popular questions from this chapter

In a common emitter transistor, the current gain is 80 . What is the change in collector current, when the change in base current is \(250 \mu \mathrm{A} ?\) (A) \(80 \times 250 \mu \mathrm{A}\) (B) \((250-80) \mu \mathrm{A}\) (C) \((250+80) \mu \mathrm{A}\) (D) \(250 / 80 \mu \mathrm{A}\)

In an \(N P N\) transistor the collector current is \(24 \mathrm{~mA}\). If \(80 \%\) of electrons reach collector its base current in \(\mathrm{mA}\) is (A) 36 (B) 26 (C) 16 (D) 6

Consider the following statements \(A\) and \(B\) and identify the correct choice of the given answers \(A\) : The width of the depletion layer in a \(P-N\) junction diode increases in forwards bias \(B\) : In an intrinsic semiconductor the fermi energy level is exactly in the middle of the forbidden gap (A) \(A\) is true and \(B\) is false (B) Both \(A\) and \(B\) is false (C) \(A\) is false and \(B\) is true (D) Both \(A\) and \(B\) is true

In a common-base mode of transistor, the collector current is \(5.488 \mathrm{~mA}\) for an emitter current of \(5.60 \mathrm{~mA}\). The value of the base current amplification factor \((\beta)\) will be (A) 49 (B) 50 (C) 51 (D) 48

When the \(P\) end of \(P-N\) junction is connected to the negative terminal of the battery and the \(N\) end to the positive terminal of the battery, then the \(P-N\) junction behaves like (A) A conductor (B) An insulator (C) A super-conductor (D) A semi-conductor
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