/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 107 A \(150 \mathrm{~m}\) long train... [FREE SOLUTION] | 91影视

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Chapter 2: Problem 107

A \(150 \mathrm{~m}\) long train is moving to north at a speed of \(10 \mathrm{~m} / \mathrm{s}\). A parrot is flying towards south with a speed of \(5 \mathrm{~m} / \mathrm{s}\) crosses the train. The time taken by the parrot to cross the train would be (A) \(30 \mathrm{~s}\) (B) \(15 \mathrm{~s}\) (C) \(8 \mathrm{~s}\) (D) \(10 \mathrm{~s}\)

Short Answer

Expert verified
The time taken by the parrot to cross the train is \(10 \mathrm{~s}\).

Step by step solution

01

Calculate the relative speed

As the train and parrot are moving in opposite directions, we sum their speeds to find the relative speed: \[Relative \ Speed = Speed \ of \ Train \ + Speed \ of \ Parrot = 10 \ m/s + 5 \ m/s = 15 \ m/s\]
02

Apply the distance-rate-time formula

Next, we will use the distance-rate-time formula: \[Time = \frac{Distance}{Rate}\] In our case, the distance (length of the train) is 150 meters, and the rate (relative speed) is 15 m/s: \[Time = \frac{150 \ m}{15 \ m/s} = \frac{150}{15} \ s = 10 \ s \]
03

Identify the correct answer

The time taken by the parrot to cross the train is 10 seconds. Thus, the correct answer is (D) \(10 \mathrm{~s}\).

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Most popular questions from this chapter

A man holds an umbrella at \(30^{\circ}\) with the vertical to keep himself dry. He, then, runs at a speed of \(10 \mathrm{~ms}^{-1}\) and finds the rain drops to be hitting vertically. Speed of the rain drops with respect to the running man and with respect to earth are (A) \(20 \mathrm{~ms}^{-1}, 10 \mathrm{~ms}^{-1}\) (B) \(10 \mathrm{~ms}^{-1}, 20 \sqrt{3} \mathrm{~ms}^{-1}\) (C) \(10 \sqrt{3} \mathrm{~ms}^{-1}, 20 \mathrm{~ms}^{-1}\) (D) \(20 \mathrm{~ms}^{-1}, 10 \sqrt{3} \mathrm{~ms}^{-1}\)

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