/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 The wavelength of the \(K_{\alph... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 19: Problem 54

The wavelength of the \(K_{\alpha}\) line for the uranium atom \((Z=92)\) is \(\left(R=10^{7} \mathrm{~m}^{-1}\right)\) (A) \(1.6 \AA\) (B) \(0.16 \AA\) (C) \(0.5 \AA\) (D) \(2.0 \AA\)

Short Answer

Expert verified
The wavelength of the \(K_{\alpha}\) line for the uranium atom is approximately \(0.16 \AA\) . Therefore the correct answer is (B) \(0.16 \AA\).

Step by step solution

01

Identify the atomic number of Uranium

The atomic number of Uranium, \( Z \), is given as 92.
02

Insert the value into Moseley's Law

From Moseley's Law, we know that \( \lambda_{K_{\alpha}} = 12.398 / (Z-1)^2 \). Substituting \( Z = 92 \) into the formula, we get \( \lambda_{K_{\alpha}} = 12.398 / (92-1)^2) \).
03

Calculate the wavelength

Calculating the above expression, one gets \( \lambda_{K_{\alpha}} \) as approximately 0.016_nm, which, when converted to Angstroms (unit of length used in atomic physics) (1nm = 10A), we have \( \lambda_{K_{\alpha}} \approx 0.16 \AA \) .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The work function \(W_{A}\) for photoelectric material \(A\) is \(2 \mathrm{eV}\) and \(W_{B}\) for another photoelectric material \(B\) is \(4 \mathrm{eV}\). If photons of energy \(E_{A}\) strike the surface of \(A\), the ejected photoelectrons have a minimum de Broglie wavelength and photons of energy \(E_{B}\) strike the surface \(B\), the ejected photoelectrons also have a minimum de Broglie's wavelength. If \(E_{B}-E_{A}=\) \(0.5 \mathrm{eV}\) and \(V_{A}\) and \(V_{B}\) are the respective stopping potentials, find \(V_{A}-V_{B}\).

The speed of an electron having a wavelength of the order of \(1 \AA\) will be (A) \(7.25 \times 10^{6} \mathrm{~m} / \mathrm{s}\) (B) \(6.26 \times 10^{6} \mathrm{~m} / \mathrm{s}\) (C) \(5.25 \times 10^{6} \mathrm{~m} / \mathrm{s}\) (D) \(4.24 \times 10^{6} \mathrm{~m} / \mathrm{s}\)

This question contains Statement 1 and statement \(2 .\) Of the four choices given after the statements, choose the one that best describes the two statements. [2008] Statement 1: Energy is released when heavy nuclei undergo fission or light nuclei undergo fusion and Statement 2: For heavy nuclei, binding energy per nucleon increases with increasing \(Z\) while for light nuclei it decreases with increasing \(Z\). (A) Statement 1 is true, Statement 2 is false (B) Statement 1 is false, Statement 2 is true (C) Statement 1 is true, Statement 2 is true; Statement 2 is a correct explanation for statement 1 (D) Statement 1 is true, Statement 2 is true; Statement 2 is not a correct explanation for Statement 1

The 'rad' is the correct unit used to report the measurement of (A) the rate of decay of radioactive source. (B) the ability of a beam of gamma ray photons to produce ions in a target. (C) the energy delivered by radiation to a target. (D) the biological effect of radiation.

Which of the following cannot be emitted by radioactive substances during their decay? (A) Protons (B) Neutrino's (C) Helium nuclei (D) Electrons
See all solutions

Recommended explanations on Physics Textbooks

Electricity

Read Explanation

Physical Quantities And Units

Read Explanation

Scientific Method Physics

Read Explanation

Rotational Dynamics

Read Explanation

Magnetism

Read Explanation

Wave Optics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.