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Chapter 19: Problem 4

The time by a photoelectron to come out after the photon strikes is approximately (A) \(10^{-1} \mathrm{~s}\) (B) \(10^{-4} \mathrm{~s}\) (C) \(10^{-10} \mathrm{~s}\) (D) \(10^{-16} \mathrm{~s}\)

Short Answer

Expert verified
The time it takes for a photoelectron to come out after the photon strikes is approximately (D) \(10^{-16} \mathrm{~s}\).

Step by step solution

01

Understand the photoelectric effect

The photoelectric effect is an important concept in modern physics. When a photon, which is a quantum of electromagnetic radiation, hits a metal surface, it can transfer its energy to an electron in the metal. If the energy received by the electron from the photon is equal to or greater than the work function of the metal, the electron will be ejected from the metal's surface. This ejected electron is called a photoelectron.
02

Recall the time scale of the photoelectron emission

The whole process of photon absorption and electron ejection happens extremely fast. The time it takes for a photoelectron to emerge from the surface after the photon strikes is typically in the order of \(10^{-15} \mathrm{~s}\). This time scale is known as femtoseconds.
03

Choose the correct option

Comparing the given options to the time scale we know from the previous step (order of \(10^{-15} \mathrm{~s}\)): (A) \(10^{-1} \mathrm{~s}\) - much slower than the actual process (B) \(10^{-4} \mathrm{~s}\) - still slower than the actual process (C) \(10^{-10} \mathrm{~s}\) - closer but still not accurate (D) \(10^{-16} \mathrm{~s}\) - the closest to the actual time scale The correct answer is (D) \(10^{-16} \mathrm{~s}\), as it is the closest to the actual time scale for photoelectron emission in the photoelectric effect.

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