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Half-lives of two radioactive elements \(A\) and \(B\) are 20 minutes and 40 minutes, respectively. Initially, the samples have equal number of nuclei. After \(80 \mathrm{~min}\) utes, the ratio of decayed numbers of \(A\) and \(B\) nuclei will be (A) \(4: 1\) (B) \(1: 4\) (C) \(5: 4\) (D) \(1: 16\)

Short Answer

Expert verified
The remaining fraction of A and B nuclei after 80 minutes can be calculated using the radioactive decay formula \(N(t) = N_0 (1/2)^{t/T}\), where \(N(t)\) is the remaining number of nuclei, \(N_0\) is the initial number, T is the half-life, and t is the time. For A, \(N_A(t) = N_0 (1/2)^{80/20}\) and for B, \(N_B(t) = N_0 (1/2)^{80/40}\). The decayed number of nuclei for A and B are then \(D_A = N_0 - N_A(t)\) and \(D_B = N_0 - N_B(t)\), respectively. The ratio of decayed is given by \(\frac{D_A}{D_B} = \frac{N_0 - N_0 (1/2)^{80/20}}{N_0 - N_0 (1/2)^{80/40}}\). Simplifying this, we get the fraction \(\frac{15}{12}\), which simplifies to the ratio \(5:4\). Therefore, the ratio of decayed numbers of A and B nuclei after 80 minutes is \(5:4\), which is option (C).

Step by step solution

01

Use the radioactive decay formula to calculate the remaining fraction of A and B nuclei

\ To find the remaining fraction of A and B nuclei after 80 minutes of radioactive decay, we can use the radioactive decay formula: \(N(t) = N_0 (1/2)^{t/T}\) where \(N(t)\) is the number of radioactive nuclei remaining after time t, \(N_0\) is the initial number of radioactive nuclei, T is the half-life, and t is the time elapsed. For element A: \(N_A(t) = N_0 (1/2)^{80/20}\) For element B: \(N_B(t) = N_0 (1/2)^{80/40}\) Notice that we can keep the initial number of nuclei as \(N_0\) since A and B started with equal numbers of nuclei.
02

Calculate the number of decayed nuclei

\ The number of decayed nuclei for each element can be calculated by subtracting the remaining number of nuclei after 80 minutes from the initial number of nuclei. Decayed nuclei for element A: \(D_A = N_0 - N_A(t) = N_0 - N_0 (1/2)^{80/20}\) Decayed nuclei for element B: \(D_B = N_0 - N_B(t) = N_0 - N_0 (1/2)^{80/40}\)
03

Calculate the ratio of decayed numbers of A and B nuclei

\ Now we can compute the ratio of decayed numbers of A and B nuclei. The ratio can be written as: \(\frac{D_A}{D_B} = \frac{N_0 - N_0 (1/2)^{80/20}}{N_0 - N_0 (1/2)^{80/40}}\)
04

Simplify the expression and find the answer

\ We can simplify this expression by dividing the numerator and the denominator by \(N_0\), which leaves: \(\frac{D_A}{D_B} = \frac{1 - (1/2)^{80/20}}{1 - (1/2)^{80/40}} = \frac{1 - (1/2)^4}{1 - (1/2)^2}\) Now, we can simplify the expression: \(\frac{D_A}{D_B} = \frac{1 - 1/16}{1 - 1/4} = \frac{15/16}{3/4}\) Multiply the numerator by the reciprocal of the denominator: \(\frac{D_A}{D_B} = \frac{15/16}{3/4} \times \frac{4/3}{4/3} = \frac{15/16}{3/4} \times \frac{4/3}{1} = \frac{15}{12}\) Simplify this fraction: \(\frac{D_A}{D_B} = \frac{5}{4}\) So the ratio of decayed numbers of A and B nuclei after 80 minutes is \(5:4\), which corresponds to option (C).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Half-Life in Radioactive Decay
The concept of half-life is crucial in the realm of nuclear physics and particularly in understanding radioactive decay. It is the time required for half of the radioactive nuclei in a sample to undergo decay, transforming into a different element or isotope. This predictable rate of decay allows scientists to approximate the age of substances, the effectiveness of medical treatments, and even the time for a radioactive substance to become safe.

In practical terms, after one half-life, 50% of the original radioactive nuclei will have decayed. After two half-lives, 25% remain, and this pattern continues, halving with each consecutive half-life period. The exercise given illustrates this point by comparing the half-lives of two radioactive substances, A and B, each with different half-life times. Over these intervals, A and B will have different proportions of their original nuclei remaining, which leads us to use this concept to solve the problem of finding the ratio of decayed numbers of A and B nuclei.
Radioactive Decay Formula
The radioactive decay formula is a mathematical representation of the rate at which unstable atomic nuclei lose energy by emitting radiation. The standard formula used to determine the remaining number of radioactive nuclei after a certain amount of time is:
\[\begin{equation}N(t) = N_0 \times \bigg(\frac{1}{2}\bigg)^{\frac{t}{T}}\end{equation}\]
Here, \(N(t)\) is the number of nuclei remaining after time \(t\), \(N_0\) is the original number of nuclei, \(T\) is the half-life of the substance, and \(t\) is the time elapsed. When applying this formula to our problem, we find the ratio of decayed nuclei by first calculating how much of each substance remains and then determining what fraction has decayed. Understanding and correctly applying this formula is key to solving many problems related to the stability and longevity of radioactive materials.
Nuclei Decay Calculations
To comprehend nuclei decay calculations, one must first grasp the radioactive decay formula and half-life concept. By integrating these concepts, we can calculate both the remaining and decayed nuclei after a certain period. In our textbook exercise, it's essential to calculate the decayed nuclei for two elements to find their decay ratio after 80 minutes.

The step-by-step solution walks through this process, demonstrating how to subtract the remaining nuclei from the initial number to get the decayed count. The final step involves simplifying a ratio, which is a common necessity in such problems, and recognizes the importance of algebraic manipulation in nuclear chemistry calculations. The practice of nuclear decay calculations equips students with the skill to predict and analyze radioactive elements' behavior over time, a fundamental aspect of both basic understanding and application in various scientific fields.

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Most popular questions from this chapter

When photons of energy \(5 \mathrm{eV}\) strike the surface of a metal \(A\), the ejected photoelectrons have maximum kinetic energy \(K_{A} \mathrm{eV}\) and de Broglie wavelength \(\lambda_{A}\). The maximum kinetic energy of photoelectrons liberated from another metal \(B\) by photons of energy \(5.30 \mathrm{eV}\) is \(K_{B}=\left(K_{A}-1.5\right) . \mathrm{eV}\). If the de Broglie wavelength of these photoelectrons is \(\lambda_{B}=2 \lambda_{A}\), then find \(K_{A}\) and \(K_{B}\).

An electron and a proton are separated by a large distance. The electron starts approaching the proton with energy \(2 \mathrm{eV}\). The proton captures the electron and forms a hydrogen atom in first excited state. The resulting photon is incident on a photosensitive metal of threshold wavelength \(4600 \AA\). The maximum \(K E\) of the emitted photoelectron is \((h c=12420 \mathrm{eV} \AA)\) (A) \(2.4 \mathrm{eV}\) (B) \(2.7 \mathrm{eV}\) (C) \(2.9 \mathrm{eV}\) (D) \(5.4 \mathrm{eV}\)

Due to annihilation of electron-positron of same kinetic energy \(0.95 \mathrm{MeV}\), a photon is produced which can also be produced by a photo- electron of energy \(E\), the possible value(s) of \(E\) is/are (mass of electron \(=9.1 \times 10^{-31} \mathrm{~kg}, e=1.6 \times 10^{-19}\) Coulomb) (A) \(1.02 \mathrm{MeV}\) (B) \(2.42 \mathrm{MeV}\) (C) \(4.03 \mathrm{MeV}\) (D) \(2.93 \mathrm{MeV}\)

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Starting with a sample of pure \({ }^{66} \mathrm{Cu}, \frac{7}{8}\) of it decays into \(\mathrm{Zn}\) in 15 minutes. The corresponding half-life is (A) \(15 \mathrm{~min}\) (B) \(10 \mathrm{~min}\) (C) \(7 \frac{1}{2} \mathrm{~min}\) (D) \(5 \mathrm{~min}\)

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